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Zorluk: OrtaMaking Predictions Based on Models

Researchers study the electrical resistance of four different wire samples as a function of temperature. The resistance RR (in ohms, Ω\Omega) of a metal wire at temperature TT (in C^\circ\text{C}) is modeled by the linear relationship:

R(T)=R0[1+α(TT0)]R(T) = R_0 [1 + \alpha(T - T_0)]

where R0R_0 is the baseline resistance at the reference temperature T0=20CT_0 = 20^\circ\text{C}, and α\alpha is the temperature coefficient of resistance (in C1^\circ\text{C}^{-1}).

The baseline resistance and temperature coefficients for the four wire samples are shown in the table below:

Wire MaterialBaseline Resistance (R0R_0 at 20C20^\circ\text{C})Temperature Coefficient (α\alpha)
Copper10 Ω10\ \Omega0.0040 C10.0040\ ^\circ\text{C}^{-1}
Iron8 Ω8\ \Omega0.0060 C10.0060\ ^\circ\text{C}^{-1}
Tungsten12 Ω12\ \Omega0.0045 C10.0045\ ^\circ\text{C}^{-1}
Carbon15 Ω15\ \Omega0.0005 C1-0.0005\ ^\circ\text{C}^{-1}

Arrange the wire samples in order of their predicted electrical resistance at 120C120^\circ\text{C} from lowest resistance to highest resistance.

  1. 1Iron wire
  2. 2Copper wire
  3. 3Carbon wire
  4. 4Tungsten wire

Cevap

The correct order of wire samples from lowest to highest predicted resistance is Iron wire, Copper wire, Carbon wire, and Tungsten wire.
Evaluating the linear resistance model at 120C120^\circ\text{C} (TT0=100CT - T_0 = 100^\circ\text{C}) yields resistances of 12.8 Ω12.8\ \Omega for Iron, 14.0 Ω14.0\ \Omega for Copper, 14.25 Ω14.25\ \Omega for Carbon, and 17.4 Ω17.4\ \Omega for Tungsten, establishing the sequence from lowest to highest.

Adım Adım Çözüm

1
Calculate the temperature difference (TT0T - T_0) from the reference temperature to the target temperature.
TT0=120C20C=100CT - T_0 = 120^\circ\text{C} - 20^\circ\text{C} = 100^\circ\text{C}
The model uses the temperature deviation from the baseline reference temperature T0=20CT_0 = 20^\circ\text{C}.
2
Apply the model R(T)=R0[1+α(TT0)]R(T) = R_0 [1 + \alpha(T - T_0)] to calculate the resistance of each wire at 120C120^\circ\text{C}.
Iron: 8×[1+0.0060(100)]=12.8 Ω8 \times [1 + 0.0060(100)] = 12.8\ \Omega; Copper: 10×[1+0.0040(100)]=14.0 Ω10 \times [1 + 0.0040(100)] = 14.0\ \Omega; Carbon: 15×[10.0005(100)]=14.25 Ω15 \times [1 - 0.0005(100)] = 14.25\ \Omega; Tungsten: 12×[1+0.0045(100)]=17.4 Ω12 \times [1 + 0.0045(100)] = 17.4\ \Omega.
Evaluating the mathematical model with the given parameters determines the resistance values for comparison.
3
Order the wire materials from the smallest calculated resistance value to the largest.
Iron (12.8 Ω12.8\ \Omega) < Copper (14.0 Ω14.0\ \Omega) < Carbon (14.25 Ω14.25\ \Omega) < Tungsten (17.4 Ω17.4\ \Omega).
This matches the requested sorting direction from lowest to highest resistance.

Anahtar Kavram

Applying mathematical linear models to predict physical quantities at specific conditions.
Tahmini Süre:1m 30s
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