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Zorluk: OrtaArithmetic and Geometric Sequences and Series

A geometric sequence has a first term of 232^3 and a common ratio of 222^2. What is the value of the 5th term of this sequence?

  1. A
    2424
  2. B
    512512
  3. 2,0482,048Cevap
  4. D
    8,1928,192
  5. E
    16,777,21616,777,216

Cevap

The 5th term of the geometric sequence is 2,0482,048.
To find the 5th term of a geometric sequence, we use the formula an=a1rn1a_n = a_1 \cdot r^{n-1}. Substituting the given first term a1=23=8a_1 = 2^3 = 8 and the common ratio r=22=4r = 2^2 = 4 for n=5n = 5 gives a5=23(22)4a_5 = 2^3 \cdot (2^2)^4. Applying the power of a power rule, (22)4=22×4=28(2^2)^4 = 2^{2 \times 4} = 2^8. Then, multiplying the bases by adding the exponents gives 2328=23+8=2112^3 \cdot 2^8 = 2^{3+8} = 2^{11}, which evaluates to 2,0482,048.

Adım Adım Çözüm

1
Identify the given values and the formula for the nn-th term of a geometric sequence.
The first term is a1=23=8a_1 = 2^3 = 8, the common ratio is r=22=4r = 2^2 = 4, and we need to find the term for n=5n = 5 using the formula an=a1rn1a_n = a_1 \cdot r^{n-1}.
Knowing the correct formula is necessary to compute the specific term of a geometric sequence.
2
Substitute the values into the formula to express the 5th term in terms of base 2.
a5=23(22)51=23(22)4a_5 = 2^3 \cdot (2^2)^{5-1} = 2^3 \cdot (2^2)^4
This substitutes the specific term number and sequence parameters into the general term formula.
3
Simplify the exponential expression and calculate the final numerical value.
a5=2328=23+8=211=2,048a_5 = 2^3 \cdot 2^8 = 2^{3+8} = 2^{11} = 2,048
Applying exponent rules (multiplying powers of a power and adding exponents when multiplying like bases) allows us to evaluate the expression to a single number.

Anahtar Kavram

Finding a specific term in a geometric sequence using exponential properties
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