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Zorluk: KolayCircle Geometry: Arc Length and Sector Area

A windshield wiper of length 15 inches15\text{ inches} sweeps through a central angle of 120120^\circ across a windshield. What is the area, in square inches, of the region swept by the wiper?

  1. A
    10π10\pi
  2. 75π75\piCevap
  3. C
    112.5π112.5\pi
  4. D
    150π150\pi
  5. E
    225π225\pi

Cevap

75π75\pi square inches
The area of the region swept by the wiper is the area of a circle sector with a radius of 15 inches15\text{ inches} and a central angle of 120120^\circ. The formula for the area of a sector is A=θ360×πr2A = \frac{\theta}{360} \times \pi r^2. Substituting 1515 for the radius and 120120 for the angle gives A=120360×π(15)2=13×225π=75πA = \frac{120}{360} \times \pi (15)^2 = \frac{1}{3} \times 225\pi = 75\pi square inches.

Adım Adım Çözüm

1
Determine the formula for the area of a sector of a circle.
A=θ360×πr2A = \frac{\theta}{360^\circ} \times \pi r^2
The area of a sector is a fraction of the total area of the circle, where the fraction is determined by the central angle θ\theta divided by the total degrees in a circle (360360^\circ).
2
Substitute the given values into the sector area formula, using a radius of 1515 and a central angle of 120120^\circ.
A=120360×π(15)2A = \frac{120^\circ}{360^\circ} \times \pi (15)^2
The windshield wiper length represents the radius r=15 inchesr = 15\text{ inches}, and the sweep angle represents the central angle θ=120\theta = 120^\circ.
3
Simplify the expression to find the final area.
A=13×225π=75πA = \frac{1}{3} \times 225\pi = 75\pi
Reducing the fraction 120360\frac{120}{360} to 13\frac{1}{3} and squaring 1515 to get 225225 yields the area of 75π75\pi square inches.

Anahtar Kavram

The area of a circle sector is found by multiplying the total circle area, πr2\pi r^2, by the ratio of the central angle to the total degree measure of a circle, θ360\frac{\theta}{360^\circ}.
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