A box contains 5 red tickets, 7 blue tickets, and 8 green tickets. If one ticket is select… — ACT

A box contains $5$ red tickets, $7$ blue tickets, and $8$ green tickets. If one ticket is selected at random from the box, what is the probability that the selected ticket is NOT blue?

A
$\frac{7}{20}$
$\frac{13}{20}$ Cevap
C
$\frac{7}{13}$
D
$\frac{3}{5}$
E
$\frac{13}{7}$

Cevap

The probability that the selected ticket is not blue is

\frac{13}{20}

To find the probability of selecting a ticket that is not blue, divide the number of non-blue tickets by the total number of tickets. There are

5 + 7 + 8 = 20

total tickets, of which

5 + 8 = 13

are not blue. Thus, the probability is

\frac{13}{20}

Adım Adım Çözüm

Find the total number of outcomes (total tickets in the box).

Total tickets =

5 + 7 + 8 = 20

Basic probability requires dividing the number of favorable outcomes by the total sample space.

Calculate the number of favorable outcomes (tickets that are NOT blue).

Favorable tickets =

5\text{ (red)} + 8\text{ (green)} = 13

(or

20 - 7 = 13

The complement of choosing a blue ticket is choosing a red or green ticket.

Form the probability ratio of favorable outcomes to total outcomes.

Probability =

\frac{13}{20}

Probability is defined as

\frac{\text{Favorable Outcomes}}{\text{Total Outcomes}}

Anahtar Kavram

Basic Probability of Complementary Events

Tahmini Süre:45s

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