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Zorluk: OrtaAbsolute Value Equations and Inequalities

If yy is a real number such that ∣3−12y∣=5|3 - \frac{1}{2}y| = 5, what is the sum of all possible values of yy?

  1. A
    -4
  2. 12Cevap
  3. C
    16
  4. D
    -12
  5. E
    20

Cevap

12
Solving the equation ∣3−12y∣=5|3 - \frac{1}{2}y| = 5 requires setting up two cases: 3−12y=53 - \frac{1}{2}y = 5 and 3−12y=−53 - \frac{1}{2}y = -5. Solving the first case gives y=−4y = -4, and solving the second case gives y=16y = 16. The sum of these two solutions is −4+16=12-4 + 16 = 12.

Adım Adım Çözüm

1
Set up the two equations represented by the absolute value expression.
3−12y=53 - \frac{1}{2}y = 5 and 3−12y=−53 - \frac{1}{2}y = -5
An absolute value equation ∣u∣=C|u| = C (where C≥0C \ge 0) splits into two cases: u=Cu = C and u=−Cu = -C.
2
Solve the first equation 3−12y=53 - \frac{1}{2}y = 5.
y=−4y = -4
Subtracting 3 from both sides yields −12y=2-\frac{1}{2}y = 2. Multiplying both sides by −2-2 isolates yy.
3
Solve the second equation 3−12y=−53 - \frac{1}{2}y = -5.
y=16y = 16
Subtracting 3 from both sides yields −12y=−8-\frac{1}{2}y = -8. Multiplying both sides by −2-2 isolates yy.
4
Calculate the sum of all possible values of yy.
1212
Add the two solutions together: −4+16=12-4 + 16 = 12.

Anahtar Kavram

Absolute Value Equations
Tahmini Süre:1m 30s
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