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Zorluk: OrtaLinear Equations and Graphing

The table below shows coordinate points (x,y)(x, y) that lie on a line LL in the standard (x,y)(x, y) coordinate system:

xxyy
−2-2−7-7
1122
441111

What is the xx-intercept of line LL?

  1. 13\frac{1}{3}Cevap
  2. B
    −13-\frac{1}{3}
  3. C
    −1-1
  4. D
    −5-5
  5. E
    53\frac{5}{3}

Cevap

The correct answer is 13\frac{1}{3}
The correct answer is 13\frac{1}{3}. First, find the slope of the line using the points (−2,−7)(-2, -7) and (1,2)(1, 2) from the table: m=2−(−7)1−(−2)=3m = \frac{2 - (-7)}{1 - (-2)} = 3. Next, substitute the slope and the coordinate point (1,2)(1, 2) into the point-slope equation to get y−2=3(x−1)y - 2 = 3(x - 1), which simplifies to y=3x−1y = 3x - 1. To find the xx-intercept, set y=0y = 0 and solve for xx: 0=3x−10 = 3x - 1, which gives x=13x = \frac{1}{3}.

Adım Adım Çözüm

1
Calculate the slope (mm) of line LL using the coordinate points (−2,−7)(-2, -7) and (1,2)(1, 2) from the table.
The slope is m=2−(−7)1−(−2)=93=3m = \frac{2 - (-7)}{1 - (-2)} = \frac{9}{3} = 3.
The slope of a line represents its constant rate of change and is calculated using the formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.
2
Write the linear equation in slope-intercept form using the slope m=3m = 3 and the point (1,2)(1, 2).
Using the point-slope form: y−2=3(x−1)⇒y−2=3x−3⇒y=3x−1y - 2 = 3(x - 1) \Rightarrow y - 2 = 3x - 3 \Rightarrow y = 3x - 1.
Using point-slope form y−y1=m(x−x1)y - y_1 = m(x - x_1) allows us to easily simplify the relationship into slope-intercept form y=mx+by = mx + b.
3
Find the xx-intercept of the line by setting y=0y = 0 and solving the equation for xx.
Setting y=0y = 0 gives 0=3x−1⇒3x=1⇒x=130 = 3x - 1 \Rightarrow 3x = 1 \Rightarrow x = \frac{1}{3}.
The xx-intercept is the coordinate value where the graph intersects the xx-axis, which mathematically occurs when y=0y = 0.

Anahtar Kavram

Determining the equation of a line from tabular coordinates and calculating its intercepts
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