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Zorluk: OrtaGeometric Figures on the Coordinate Plane

In the standard (x,y)(x, y) coordinate plane, three vertices of a rhombus are (1,2)(1, 2), (5,5)(5, 5), and (9,2)(9, 2). If the yy-coordinate of the fourth vertex is less than 2, what are the coordinates of the fourth vertex?

  1. (5,1)(5, -1)Cevap
  2. B
    (13,5)(13, 5)
  3. C
    (13,1)(13, -1)
  4. D
    (6,2)(6, -2)
  5. E
    (3,5)(-3, 5)

Cevap

The coordinates of the fourth vertex are (5,1)(5, -1).
The correct answer is the coordinate pair (5,1)(5, -1). Since opposite sides of a rhombus are parallel and congruent, the vector from (5,5)(5, 5) to (1,2)(1, 2) is (4,3)(-4, -3). Applying this vector to (9,2)(9, 2) gives (94,23)=(5,1)(9 - 4, 2 - 3) = (5, -1). This point satisfies the requirement that the yy-coordinate is less than 2, and all four side lengths are exactly 5.

Adım Adım Çözüm

1
Calculate the vector translation between two adjacent vertices of the rhombus.
The vector from vertex (5,5)(5, 5) to vertex (1,2)(1, 2) is (15,25)=(4,3)(1 - 5, 2 - 5) = (-4, -3).
In a rhombus, opposite sides must be parallel and equal in length, meaning the translation from one vertex to another on one side must equal the translation on the opposite side.
2
Apply the translation vector to the third vertex to find the fourth vertex.
Applying the vector (4,3)(-4, -3) to the vertex (9,2)(9, 2) yields (94,23)=(5,1)(9 - 4, 2 - 3) = (5, -1).
This determines the coordinates of the fourth vertex that completes the parallelogram structure.
3
Verify that the resulting vertex satisfies all conditions of the problem.
The yy-coordinate of (5,1)(5, -1) is 1-1, which is less than 2. The side lengths are all equal to 5: (51)2+(12)2=5\sqrt{(5-1)^2 + (-1-2)^2} = 5 and (59)2+(12)2=5\sqrt{(5-9)^2 + (-1-2)^2} = 5.
This confirms that the figure is a rhombus and satisfies the yy-coordinate constraint.

Anahtar Kavram

Using vector translations and distance formulas to determine coordinates of geometric figures on the coordinate plane.
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