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Zorluk: KolayConic Sections

A parabola in the standard (x,y)(x, y) coordinate plane is defined by the equation y2=12xy^2 = 12x. What is the xx-coordinate of the focus of this parabola?

Cevap: 3

Cevap

The xx-coordinate of the focus is 3.
The equation y2=12xy^2 = 12x represents a parabola with vertex at the origin opening to the right. The standard form for such a parabola is y2=4pxy^2 = 4px, where the focus is located at (p,0)(p, 0). By setting 4p=124p = 12, we find p=3p = 3. Thus, the focus is (3,0)(3, 0), and its xx-coordinate is 3.

Adım Adım Çözüm

1
Identify the standard form of the parabola's equation.
The equation y2=12xy^2 = 12x fits the standard form of a horizontal parabola with its vertex at the origin, y2=4pxy^2 = 4px.
This allows us to relate the given equation to the coordinate of the focus, which is located at (p,0)(p, 0).
2
Solve for the parameter pp.
4p=124p = 12, which gives p=3p = 3.
By equating the coefficients of xx from the given equation and the standard form, we can find the value of pp.
3
Determine the focus coordinate.
The focus is at (3,0)(3, 0), so the xx-coordinate is 3.
The focus of a parabola of the form y2=4pxy^2 = 4px has coordinates (p,0)(p, 0).

Anahtar Kavram

Focus of a Parabola
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