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Zorluk: ZorFactors, Multiples, and Prime Factorization

Two positive integers, aa and bb, are such that a<ba < b. The greatest common divisor of aa and bb is 1212, and their least common multiple is 720720. If aa is a multiple of 55 but bb is not a multiple of 55, what is the value of aa?

Cevap: 60

Cevap

60
By representing a=12xa = 12x and b=12yb = 12y with gcd(x,y)=1\gcd(x, y) = 1 and x<yx < y, the least common multiple constraint gives 12xy=72012xy = 720, which simplifies to xy=60xy = 60. Since aa is a multiple of 55 and bb is not, the factor of 55 in 6060 must belong to xx. Given that x<yx < y and gcd(x,y)=1\gcd(x, y) = 1, the only valid coprime factorization of 6060 where the factor 55 is in xx and x<yx < y is x=5x = 5 and y=12y = 12. This yields a=12×5=60a = 12 \times 5 = 60.

Adım Adım Çözüm

1
Express the two numbers in terms of their greatest common divisor (GCD).
a=12xa = 12x and b=12yb = 12y, where gcd(x,y)=1\gcd(x, y) = 1 and x<yx < y.
Since the greatest common divisor of aa and bb is 1212, both numbers must be multiples of 1212, and their remaining parts xx and yy must be coprime to ensure their GCD is exactly 1212.
2
Use the least common multiple (LCM) to find the product of xx and yy.
xy=60xy = 60.
The least common multiple of 12x12x and 12y12y when gcd(x,y)=1\gcd(x, y) = 1 is 12xy12xy. Setting 12xy=72012xy = 720 and dividing by 1212 gives xy=60xy = 60.
3
Identify the constraints on xx and yy based on the divisibility by 55.
55 must divide xx, and 55 must not divide yy.
We are given that a=12xa = 12x is a multiple of 55, which means 55 must be a factor of xx. Since b=12yb = 12y is not a multiple of 55, 55 cannot be a factor of yy.
4
Determine the unique pair (x,y)(x, y) that satisfies all constraints.
x=5x = 5 and y=12y = 12.
The product xy=60xy = 60 has prime factorization 22×3×52^2 \times 3 \times 5. Since gcd(x,y)=1\gcd(x, y) = 1, the factor 55 must belong to xx, and the other prime factors 222^2 and 33 can be distributed. To satisfy x<yx < y, the only possible assignment is x=5x = 5 and y=12y = 12 (since other assignments like x=15,y=4x = 15, y = 4 or x=20,y=3x = 20, y = 3 violate x<yx < y).
5
Calculate the value of aa.
a=60a = 60.
Since a=12xa = 12x and x=5x = 5, we find a=12×5=60a = 12 \times 5 = 60.

Anahtar Kavram

Using prime factorizations to analyze greatest common divisors and least common multiples under algebraic and inequality constraints.
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