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Zorluk: KolayLaw of Sines and Law of Cosines

In triangle PQRPQR, the measure of angle PP is 3030^\circ, the measure of angle QQ is 4545^\circ, and the length of side QRQR is 1010 units. Which of the following expressions represents the length, in units, of side PRPR?

  1. A
    10sin(30)sin(45)10\sin(30^\circ)\sin(45^\circ)
  2. B
    10sin(30)sin(45)\frac{10\sin(30^\circ)}{\sin(45^\circ)}
  3. C
    10cos(45)cos(30)\frac{10\cos(45^\circ)}{\cos(30^\circ)}
  4. 10sin(45)sin(30)\frac{10\sin(45^\circ)}{\sin(30^\circ)}Cevap
  5. E
    10cos(30)sin(45)\frac{10\cos(30^\circ)}{\sin(45^\circ)}

Cevap

The length of side PRPR is represented by the expression 10sin(45)sin(30)\frac{10\sin(45^\circ)}{\sin(30^\circ)}.
The correct answer is derived by setting up the Law of Sines proportion: PRsin(45)=10sin(30)\frac{PR}{\sin(45^\circ)} = \frac{10}{\sin(30^\circ)}. Multiplying both sides by sin(45)\sin(45^\circ) yields PR=10sin(45)sin(30)PR = \frac{10\sin(45^\circ)}{\sin(30^\circ)}.

Adım Adım Çözüm

1
Identify the known values and corresponding angle-side pairs in triangle PQRPQR.
Angle P=30P = 30^\circ is opposite to side QR=10QR = 10, and angle Q=45Q = 45^\circ is opposite to side PRPR.
This allows us to set up the appropriate trigonometric relationship to solve for the unknown side.
2
Apply the Law of Sines to relate the ratios of the side lengths to the sines of their opposite angles.
PRsin(Q)=QRsin(P)\frac{PR}{\sin(Q)} = \frac{QR}{\sin(P)}, which becomes PRsin(45)=10sin(30)\frac{PR}{\sin(45^\circ)} = \frac{10}{\sin(30^\circ)}.
The Law of Sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant for all three sides.
3
Isolate the variable representing the length of side PRPR.
PR=10sin(45)sin(30)PR = \frac{10\sin(45^\circ)}{\sin(30^\circ)}.
Multiply both sides of the equation by sin(45)\sin(45^\circ) to solve for PRPR.

Anahtar Kavram

The Law of Sines relates the side lengths of a triangle to the sines of its angles: asin(A)=bsin(B)=csin(C)\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}.
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