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Zorluk: ZorDescriptive Statistics and Data Representations

A quality control engineer measured the lengths of precision bolts manufactured across five production lines. The table below shows the number of bolts tested from each line and the mean length, in millimeters, of the bolts from that line.

Production LineNumber of Bolts TestedMean Length (mm)
Line 1151524.824.8
Line 2252525.225.2
Line 3202024.624.6
Line 4101025.425.4
Line 5xx25.625.6

If the overall mean length of all the bolts tested across all five lines is 25.125.1 millimeters, what is the value of xx, the number of bolts tested from Line 5?

  1. A
    99
  2. B
    1515
  3. 1818Cevap
  4. D
    2525
  5. E
    3030

Cevap

18
To find the number of bolts xx tested from Line 5, compute the sum of the bolt lengths for the first four lines by multiplying each count by its respective mean: (15×24.8)+(25×25.2)+(20×24.6)+(10×25.4)=372+630+492+254=1748(15 \times 24.8) + (25 \times 25.2) + (20 \times 24.6) + (10 \times 25.4) = 372 + 630 + 492 + 254 = 1748 mm. The total number of bolts across all five lines is 15+25+20+10+x=70+x15 + 25 + 20 + 10 + x = 70 + x. Setting the weighted average equal to the target overall mean of 25.125.1 yields the equation 1748+25.6x70+x=25.1\frac{1748 + 25.6x}{70 + x} = 25.1. Multiplying both sides by (70+x)(70 + x) gives 1748+25.6x=1757+25.1x1748 + 25.6x = 1757 + 25.1x. Subtracting 25.1x25.1x and 17481748 from both sides gives 0.5x=90.5x = 9, which simplifies to x=18x = 18.

Adım Adım Çözüm

1
Calculate the total sum of lengths for Lines 1 through 4.
Line 1: 15×24.8=37215 \times 24.8 = 372; Line 2: 25×25.2=63025 \times 25.2 = 630; Line 3: 20×24.6=49220 \times 24.6 = 492; Line 4: 10×25.4=25410 \times 25.4 = 254. Total sum for Lines 1-4 = 372+630+492+254=1748372 + 630 + 492 + 254 = 1748 mm.
The total length of bolts in a line equals the line count multiplied by its mean length.
2
Determine the total count of bolts tested across all five lines.
Total count = 15+25+20+10+x=70+x15 + 25 + 20 + 10 + x = 70 + x.
Adding the number of bolts from each of the 5 production lines gives the overall sample size.
3
Set up the overall weighted mean equation and solve for xx.
1748+25.6x70+x=25.1    1748+25.6x=25.1(70+x)    1748+25.6x=1757+25.1x    0.5x=9    x=18\frac{1748 + 25.6x}{70 + x} = 25.1 \implies 1748 + 25.6x = 25.1(70 + x) \implies 1748 + 25.6x = 1757 + 25.1x \implies 0.5x = 9 \implies x = 18.
Overall mean is equal to the total sum of all bolt lengths divided by the overall number of bolts.

Anahtar Kavram

Weighted Mean and Combined Data Sets
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