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Zorluk: OrtaTransformations in the Coordinate Plane

In the standard (x,y)(x, y) coordinate plane, a point PP is reflected across the yy-axis and then translated 4 units down and 3 units right. The coordinates of the resulting image point, PP', are (1,2)(1, -2). What are the coordinates of the original point PP?

  1. A
    (2,2)(-2, -2)
  2. B
    (2,2)(-2, 2)
  3. C
    (2,6)(2, -6)
  4. D
    (2,2)(2, -2)
  5. (2,2)(2, 2)Cevap

Cevap

The coordinates of the original point PP are (2,2)(2, 2).
To find the coordinates of the original point P(x,y)P(x, y), we apply the inverse transformations in reverse order to the final image point P(1,2)P'(1, -2). First, we undo the translation of 4 units down and 3 units right by translating PP' 4 units up and 3 units left. This results in the intermediate coordinates (13,2+4)=(2,2)(1 - 3, -2 + 4) = (-2, 2). Next, we undo the reflection across the yy-axis by reflecting (2,2)(-2, 2) across the yy-axis again (since a reflection is its own inverse). Changing the sign of the xx-coordinate gives (2,2)(2, 2). Alternatively, setting up the equations x+3=1-x + 3 = 1 and y4=2y - 4 = -2 and solving them yields x=2x = 2 and y=2y = 2, which corresponds to the point (2,2)(2, 2).

Adım Adım Çözüm

1
Set up equations to express the composite transformations of the point P(x,y)P(x, y) to P(1,2)P'(1, -2).
Reflecting P(x,y)P(x, y) across the yy-axis changes the sign of the xx-coordinate, yielding (x,y)(-x, y). Translating this point 4 units down and 3 units right yields (x+3,y4)(-x + 3, y - 4).
Establishing the mathematical relationship for each transformation is necessary to work backward to find the coordinates of the pre-image.
2
Equate the coordinates of the transformed point to the coordinates of the final image point P(1,2)P'(1, -2).
x+3=1-x + 3 = 1 and y4=2y - 4 = -2
This sets up two independent linear equations that can be solved for the original coordinates xx and yy.
3
Solve the equations for xx and yy.
From x+3=1-x + 3 = 1, we get x=2-x = -2, which means x=2x = 2. From y4=2y - 4 = -2, we get y=2y = 2. Therefore, the coordinates of PP are (2,2)(2, 2).
Solving these equations gives the exact coordinates of the original pre-image point.

Anahtar Kavram

Working backward with composite transformations in the coordinate plane
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