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Zorluk: OrtaFundamental Trigonometric Identities

If tanθ=2\tan \theta = 2, what is the value of 3sinθ+4cosθ5sinθ2cosθ\frac{3\sin \theta + 4\cos \theta}{5\sin \theta - 2\cos \theta}?

Cevap: 1.25

Cevap

The value of the expression is 1.25.
Using the trigonometric quotient identity tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}, dividing both the numerator and denominator of 3sinθ+4cosθ5sinθ2cosθ\frac{3\sin \theta + 4\cos \theta}{5\sin \theta - 2\cos \theta} by cosθ\cos \theta transforms the fraction into 3tanθ+45tanθ2\frac{3\tan \theta + 4}{5\tan \theta - 2}. Substituting tanθ=2\tan \theta = 2 gives 3(2)+45(2)2=108=1.25\frac{3(2) + 4}{5(2) - 2} = \frac{10}{8} = 1.25. Alternatively, constructing a right triangle with opposite side 2 and adjacent side 1 gives a hypotenuse of 5\sqrt{5}, yielding sinθ=25\sin \theta = \frac{2}{\sqrt{5}} and cosθ=15\cos \theta = \frac{1}{\sqrt{5}}, which produces the exact same ratio of 10/58/5=1.25\frac{10/\sqrt{5}}{8/\sqrt{5}} = 1.25.

Adım Adım Çözüm

1
Divide every term in both the numerator and the denominator by cosθ\cos \theta.
The expression becomes 3(sinθcosθ)+4(cosθcosθ)5(sinθcosθ)2(cosθcosθ)\frac{3\left(\frac{\sin \theta}{\cos \theta}\right) + 4\left(\frac{\cos \theta}{\cos \theta}\right)}{5\left(\frac{\sin \theta}{\cos \theta}\right) - 2\left(\frac{\cos \theta}{\cos \theta}\right)}.
Dividing by cosθ\cos \theta allows us to convert sine-and-cosine terms into tangent terms using the quotient identity.
2
Apply the quotient identity tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}.
The expression simplifies to 3tanθ+45tanθ2\frac{3\tan \theta + 4}{5\tan \theta - 2}.
This reduces the trigonometric expression to an algebraic expression containing only tanθ\tan \theta.
3
Substitute tanθ=2\tan \theta = 2 into the simplified expression and compute the result.
\frac{3(2) + 4}{5(2) - 2} = \frac{6 + 4}{10 - 2} = \frac{10}{8} = 1.25.
Performing basic arithmetic yields the exact numeric answer.

Anahtar Kavram

Quotient Identity of Tangent
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