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Zorluk: OrtaAbsolute Value Equations and Inequalities

Which of the following is the set of all real values of pp for which the inequality 73p14|7 - 3p| \ge 14 is true?

  1. A
    73p7-\frac{7}{3} \le p \le 7
  2. p73 or p7p \le -\frac{7}{3} \text{ or } p \ge 7Cevap
  3. C
    p73p \le -\frac{7}{3}
  4. D
    p72 or p72p \le -\frac{7}{2} \text{ or } p \ge \frac{7}{2}
  5. E
    p73 or p7p \ge -\frac{7}{3} \text{ or } p \le 7

Cevap

p73 or p7p \le -\frac{7}{3} \text{ or } p \ge 7
To solve the inequality 73p14|7 - 3p| \ge 14, we split it into two separate inequalities: 73p147 - 3p \ge 14 or 73p147 - 3p \le -14. Solving the first inequality gives 3p7-3p \ge 7, which simplifies to p73p \le -\frac{7}{3} after dividing by 3-3 and reversing the inequality sign. Solving the second inequality gives 3p21-3p \le -21, which simplifies to p7p \ge 7 after dividing by 3-3 and reversing the inequality sign. Combining these two cases yields the set of values p73p \le -\frac{7}{3} or p7p \ge 7.

Adım Adım Çözüm

1
Set up the two compound inequalities representing the absolute value inequality 73p14|7 - 3p| \ge 14.
73p147 - 3p \ge 14 or 73p147 - 3p \le -14
An absolute value inequality of the form uc|u| \ge c (where c>0c > 0) is equivalent to the union of ucu \ge c or ucu \le -c.
2
Solve the first inequality 73p147 - 3p \ge 14.
p73p \le -\frac{7}{3}
Subtract 77 from both sides to get 3p7-3p \ge 7. Then, divide by 3-3 and reverse the inequality sign because of division by a negative number.
3
Solve the second inequality 73p147 - 3p \le -14.
p7p \ge 7
Subtract 77 from both sides to get 3p21-3p \le -21. Then, divide by 3-3 and reverse the inequality sign because of division by a negative number.
4
Combine the two case solutions to state the final solution set.
p73 or p7p \le -\frac{7}{3} \text{ or } p \ge 7
The complete solution set is the union of the solutions from both individual cases.

Anahtar Kavram

Solving absolute value inequalities of the form ax+bc|ax + b| \ge c
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