Tüm alıştırma soruları

541 soru

Soru 141Soru

A community theater sells adult tickets for $15\$15 each and student tickets for $10\$10 each. The number of tickets sold for the evening performances on Friday and Saturday is represented by the matrix AA:

A=[804511060]A = \begin{bmatrix} 80 & 45 \\ 110 & 60 \end{bmatrix}

where the rows represent Friday and Saturday, respectively, and the columns represent adult and student tickets, respectively.

The ticket prices are represented by the matrix BB:

B=[1510]B = \begin{bmatrix} 15 \\ 10 \end{bmatrix}

The product matrix C=ABC = AB represents the total ticket revenue for each night. What is the element in the second row and first column of matrix CC, which represents the total ticket revenue, in dollars, for Saturday's performance?

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Cevap: 2250

Cevap

The correct answer is 22502250 dollars, which represents the ticket revenue for Saturday's performance.
The correct answer is 22502250 dollars. The element in the second row and first column of the product matrix C=ABC = AB is obtained by multiplying the elements of the second row of matrix AA (Saturday's ticket sales: 110110 adult, 6060 student) by the corresponding elements of the first column of matrix BB (ticket prices: $15\$15 adult, $10\$10 student) and summing the products: 110×15+60×10=1650+600=2250110 \times 15 + 60 \times 10 = 1650 + 600 = 2250.

Adım Adım Çözüm

1
Identify the row of matrix AA representing Saturday's sales and the column of matrix BB representing the prices.
The second row of matrix AA is [11060]\begin{bmatrix} 110 & 60 \end{bmatrix} (representing 110110 adult tickets and 6060 student tickets sold on Saturday). Matrix BB is [1510]\begin{bmatrix} 15 \\ 10 \end{bmatrix} (representing the prices of $15\$15 and $10\$10 respectively).
Since the question asks for Saturday's performance (the second row of matrix AA) and the revenue is calculated by multiplying sales by prices, we use these specific components for the matrix multiplication.
2
Calculate the dot product of Saturday's sales row and the price column.
110×15+60×10=1650+600=2250110 \times 15 + 60 \times 10 = 1650 + 600 = 2250.
This calculation determines the sum of the revenue from adult tickets (110×15=1650110 \times 15 = 1650) and student tickets (60×10=60060 \times 10 = 600) to yield the total revenue.

Anahtar Kavram

Matrix Multiplication
Soru 142Soru

For the quadratic equation 3x26x+2=03x^2 - 6x + 2 = 0, what is the value of the discriminant?

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Cevap: 12

Cevap

The discriminant of the quadratic equation is 12.
The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is determined by the expression b24acb^2 - 4ac. By substituting the coefficients a=3a = 3, b=6b = -6, and c=2c = 2 from the given equation 3x26x+2=03x^2 - 6x + 2 = 0, we calculate (6)24(3)(2)=3624=12(-6)^2 - 4(3)(2) = 36 - 24 = 12.

Adım Adım Çözüm

1
Identify the coefficients of the quadratic equation
a=3a = 3, b=6b = -6, and c=2c = 2
The standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0.
2
Substitute the coefficients into the discriminant formula
D=(6)24(3)(2)D = (-6)^2 - 4(3)(2)
The discriminant formula is D=b24acD = b^2 - 4ac.
3
Simplify the expression to find the final value
3624=1236 - 24 = 12
Squaring 6-6 gives 3636 and multiplying 4×3×24 \times 3 \times 2 gives 2424. Subtracting 2424 from 3636 gives 1212.

Anahtar Kavram

Calculating the discriminant of a quadratic equation
Tahmini Süre:45s
Soru 143Soru

A system of equations consists of a parabola with the equation y=x2y = x^2 and a line with the equation y=3x2y = 3x - 2. The line and the parabola intersect at two points, (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2). What is the product of the yy-coordinates, y1y2y_1 \cdot y_2, of these two points?

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Cevap: 4

Cevap

The product of the y-coordinates of the intersection points is 4.
Solving the system of equations by setting x2=3x2x^2 = 3x - 2 leads to the quadratic equation x23x+2=0x^2 - 3x + 2 = 0, which factors as (x1)(x2)=0(x - 1)(x - 2) = 0. The x-coordinates of the intersection points are x=1x = 1 and x=2x = 2. Substituting these into y=x2y = x^2 gives the corresponding y-coordinates as y=12=1y = 1^2 = 1 and y=22=4y = 2^2 = 4. The product of these y-coordinates is 14=41 \cdot 4 = 4.

Adım Adım Çözüm

1
Equate the two equations to find the x-coordinates of the intersection points.
x2=3x2x^2 = 3x - 2
Since both equations are solved for y, setting them equal to each other allows us to find the x-coordinates where they intersect.
2
Move all terms to one side to set the quadratic equation to zero.
x23x+2=0x^2 - 3x + 2 = 0
This puts the equation in the standard form ax2+bx+c=0ax^2 + bx + c = 0, which can be solved by factoring.
3
Factor the quadratic equation.
(x1)(x2)=0(x - 1)(x - 2) = 0, so x1=1x_1 = 1 and x2=2x_2 = 2
Factoring shows that the values of x that satisfy the equation are the roots of the quadratic.
4
Substitute the x-coordinates back into the equation of the parabola to find the y-coordinates.
For x1=1x_1 = 1, y1=12=1y_1 = 1^2 = 1. For x2=2x_2 = 2, y2=22=4y_2 = 2^2 = 4.
Substituting x into either of the original equations gives the corresponding y-coordinates of the intersection points.
5
Calculate the product of the y-coordinates.
14=41 \cdot 4 = 4
The question asks for the product of the y-coordinates, so we multiply y1y_1 and y2y_2.

Anahtar Kavram

Solving systems of linear and quadratic equations by substitution.
Soru 144Soru

For what greatest integer value of yy is the inequality 92y169 - 2y \geq 16 true?

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Cevap: -4

Cevap

The greatest integer value of yy that satisfies the inequality is 4-4.
Subtracting 9 from both sides of 92y169 - 2y \geq 16 gives 2y7-2y \geq 7. Dividing both sides by 2-2 and reversing the inequality sign yields y3.5y \leq -3.5. The greatest integer less than or equal to 3.5-3.5 is 4-4.

Adım Adım Çözüm

1
Subtract 9 from both sides of the inequality.
2y7-2y \geq 7
This isolates the term containing yy on the left side.
2
Divide both sides of the inequality by 2-2 and reverse the direction of the inequality sign.
y3.5y \leq -3.5
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.
3
Identify the greatest integer that is less than or equal to 3.5-3.5.
4-4
The value of yy must be less than or equal to 3.5-3.5. The integers satisfying this condition are 4,5,6,-4, -5, -6, \dots, and the greatest of these is 4-4.

Anahtar Kavram

Solving linear inequalities by isolating the variable and reversing the inequality sign when dividing by a negative number.
Soru 145Soru

Matrices AA, BB, and CC are defined such that A=[x324]A = \begin{bmatrix} x & 3 \\ -2 & 4 \end{bmatrix}, B=[21y5]B = \begin{bmatrix} 2 & -1 \\ y & 5 \end{bmatrix}, and C=[1411422]C = \begin{bmatrix} 14 & 11 \\ 4 & 22 \end{bmatrix}. If AB=CAB = C, what is the value of x+yx + y?

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Cevap: 6

Cevap

The value of x+yx + y is 6.
The correct answer is 6 because performing the matrix multiplication ABAB yields the matrix [2x+3yx+154+4y22]\begin{bmatrix} 2x + 3y & -x + 15 \\ -4 + 4y & 22 \end{bmatrix}. Equating this to matrix CC gives the equations x+15=11-x + 15 = 11, which yields x=4x = 4, and 4+4y=4-4 + 4y = 4, which yields y=2y = 2. The sum of these values is 4+2=64 + 2 = 6. This is verified by checking the remaining equation 2(4)+3(2)=142(4) + 3(2) = 14.

Adım Adım Çözüm

1
Multiply matrix AA and matrix BB to express the product ABAB algebraically.
AB=[x(2)+3(y)x(1)+3(5)2(2)+4(y)2(1)+4(5)]=[2x+3yx+154+4y22]AB = \begin{bmatrix} x(2) + 3(y) & x(-1) + 3(5) \\ -2(2) + 4(y) & -2(-1) + 4(5) \end{bmatrix} = \begin{bmatrix} 2x + 3y & -x + 15 \\ -4 + 4y & 22 \end{bmatrix}
To solve for the variables, we must first determine the resulting matrix from the multiplication of AA and BB.
2
Set up equations by equating the entries of ABAB with the corresponding entries of matrix CC.
2x+3y=142x + 3y = 14, x+15=11-x + 15 = 11, and 4+4y=4-4 + 4y = 4
Two matrices are equal if and only if all of their corresponding elements are equal.
3
Solve the single-variable equation from the first row, second column for xx.
x+15=11    x=4    x=4-x + 15 = 11 \implies -x = -4 \implies x = 4
Isolating xx gives its numeric value.
4
Solve the single-variable equation from the second row, first column for yy.
4+4y=4    4y=8    y=2-4 + 4y = 4 \implies 4y = 8 \implies y = 2
Isolating yy gives its numeric value.
5
Verify consistency with the remaining equation and calculate the final sum x+yx + y.
2(4)+3(2)=8+6=142(4) + 3(2) = 8 + 6 = 14 (consistent), and x+y=4+2=6x + y = 4 + 2 = 6.
Checking the first row, first column confirms the values are correct, and adding them yields the requested sum.

Anahtar Kavram

Matrix multiplication and matrix equality
Soru 146Soru

An agricultural cooperative packages a premium seed mixture containing rye grass, fescue, and bluegrass. The weight of the fescue in the mixture is 1010 pounds less than twice the weight of the rye grass. The weight of the bluegrass is 1515 pounds more than half the weight of the fescue. If the total weight of the mixture is 120120 pounds, how many pounds of bluegrass are in the mixture?

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Cevap: 40

Cevap

The weight of the bluegrass in the mixture is 40 pounds.
By translating the given relationships into equations (f=2r10f = 2r - 10, b=12f+15b = \frac{1}{2}f + 15, and r+f+b=120r + f + b = 120), we can express all variables in terms of rr, yielding r+(2r10)+(r+10)=120r + (2r - 10) + (r + 10) = 120. Solving this gives r=30r = 30. Substituting this back gives the weight of bluegrass as 30+10=4030 + 10 = 40 pounds.

Adım Adım Çözüm

1
Define variables for each type of grass in the mixture.
Let rr represent the weight of rye grass, ff represent the weight of fescue, and bb represent the weight of bluegrass.
Establishing variables is necessary to translate the verbal descriptions into algebraic terms.
2
Translate the given relationships into equations.
f=2r10f = 2r - 10 and b=12f+15b = \frac{1}{2}f + 15
The problem states the fescue is 10 pounds less than twice the rye grass, and the bluegrass is 15 pounds more than half the fescue.
3
Substitute the expression for f into the equation for b to express b solely in terms of r.
b=12(2r10)+15=r5+15=r+10b = \frac{1}{2}(2r - 10) + 15 = r - 5 + 15 = r + 10
Reducing the number of variables simplifies the system of equations.
4
Set up the total weight equation and solve for r.
r+(2r10)+(r+10)=120    4r=120    r=30r + (2r - 10) + (r + 10) = 120 \implies 4r = 120 \implies r = 30
The sum of the three grass weights is given as 120 pounds.
5
Calculate the weight of the bluegrass using the value of r.
b=30+10=40b = 30 + 10 = 40
The question asks specifically for the weight of the bluegrass.

Anahtar Kavram

Translating verbal relationships into linear equations and solving a system of equations
Soru 147Soru

A manufacturing company determines that its weekly profit from producing xx batches of a product is constrained by resource availability. To meet these resource constraints, the number of batches xx must satisfy the inequality:

5(6x)33(x+2)4>2x11\frac{5(6 - x)}{3} - \frac{3(x + 2)}{4} > 2x - 11

What is the greatest number of whole batches the company can produce while satisfying this constraint?

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Cevap: 4

Cevap

The greatest number of whole batches the company can produce is 4.
Solving the inequality yields x<234534.415x < \frac{234}{53} \approx 4.415. The greatest integer value that satisfies this condition is 4.

Adım Adım Çözüm

1
Multiply both sides of the inequality by the least common multiple of the denominators, which is 12.
20(6x)9(x+2)>24x13220(6 - x) - 9(x + 2) > 24x - 132
Multiplying by 12 eliminates the fractions, making the inequality easier to solve.
2
Distribute the constants on the left side of the inequality.
12020x9x18>24x132120 - 20x - 9x - 18 > 24x - 132
Distributing 20 to (6x)(6 - x) yields 12020x120 - 20x, and distributing 9-9 to (x+2)(x + 2) yields 9x18-9x - 18.
3
Combine like terms on the left side of the inequality.
10229x>24x132102 - 29x > 24x - 132
Combining 12018120 - 18 gives 102102, and combining 20x9x-20x - 9x gives 29x-29x.
4
Subtract 24x24x from both sides to group the variable terms on the left side.
10253x>132102 - 53x > -132
This groups all terms containing the variable xx on one side of the inequality.
5
Subtract 102 from both sides to isolate the variable term.
53x>234-53x > -234
This isolates the term containing xx on the left side of the inequality.
6
Divide both sides by 53-53 and reverse the inequality sign.
x<23453x < \frac{234}{53}
Dividing by a negative number requires reversing the direction of the inequality sign.
7
Evaluate the fraction as a decimal and determine the greatest integer value of xx that satisfies the inequality.
x<4.415x < 4.415, which means the greatest integer is 4.
Since the company must produce a whole number of batches, we find the largest integer less than 4.415.

Anahtar Kavram

Solving multi-step linear inequalities involving fractional coefficients, distributing negative numbers, and reversing the inequality sign when multiplying or dividing by a negative number.

Alternatif Yöntem

Instead of solving algebraically, you can test integer values for xx directly in the inequality. Testing x=4x = 4 gives 103184=3.334.5=1.17\frac{10}{3} - \frac{18}{4} = 3.33 - 4.5 = -1.17, which is greater than 2(4)11=32(4) - 11 = -3 (True). Testing x=5x = 5 gives 53214=1.675.25=3.58\frac{5}{3} - \frac{21}{4} = 1.67 - 5.25 = -3.58, which is not greater than 2(5)11=12(5) - 11 = -1 (False). This confirms 4 is the largest integer satisfying the inequality.
Tahmini Süre:2m 30s
Soru 148Soru

When the expression 4x(x2y)(2x3y)2+5y(2xy)4x(x - 2y) - (2x - 3y)^2 + 5y(2x - y) is simplified to the form Ax2+Bxy+Cy2Ax^2 + Bxy + Cy^2, where AA, BB, and CC are constants, what is the value of BB?

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Cevap: 14

Cevap

The value of the coefficient BB is 14.
Expanding the entire expression yields 4x28xy4x2+12xy9y2+10xy5y24x^2 - 8xy - 4x^2 + 12xy - 9y^2 + 10xy - 5y^2. Grouping and combining the xyxy terms gives (8+12+10)xy=14xy(-8 + 12 + 10)xy = 14xy. Therefore, the coefficient BB is 14.

Adım Adım Çözüm

1
Expand the first term
4x28xy4x^2 - 8xy
Distribute 4x4x to both terms inside the parentheses: 4x(x)4x(2y)=4x28xy4x(x) - 4x(2y) = 4x^2 - 8xy.
2
Expand the squared binomial and apply the negative sign
4x2+12xy9y2-4x^2 + 12xy - 9y^2
Use the binomial expansion formula (2x3y)2=4x212xy+9y2(2x - 3y)^2 = 4x^2 - 12xy + 9y^2, then multiply each term by 1-1.
3
Expand the third term
10xy5y210xy - 5y^2
Distribute 5y5y to both terms inside the parentheses: 5y(2x)5y(y)=10xy5y25y(2x) - 5y(y) = 10xy - 5y^2.
4
Combine the coefficients of the like terms
0x2+14xy14y20x^2 + 14xy - 14y^2
Sum the coefficients for each corresponding variable group: (44)x2+(8+12+10)xy+(95)y2(4 - 4)x^2 + (-8 + 12 + 10)xy + (-9 - 5)y^2.

Anahtar Kavram

Simplifying Algebraic Expressions and Combining Like Terms
Soru 149Soru

In the standard (x,y)(x, y) coordinate plane, the line defined by the equation 3x4y=k3x - 4y = k is tangent to the circle defined by the equation x2+y22x4y=4x^2 + y^2 - 2x - 4y = 4. If k>0k > 0, what is the value of kk?

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Cevap: 10

Cevap

10
The correct answer is 10. Completing the square for the circle's equation gives (x1)2+(y2)2=9(x - 1)^2 + (y - 2)^2 = 9, showing the center is (1,2)(1, 2) and the radius is 33. The distance from (1,2)(1, 2) to the line 3x4yk=03x - 4y - k = 0 is 3(1)4(2)k32+(4)2=k+55\frac{|3(1) - 4(2) - k|}{\sqrt{3^2 + (-4)^2}} = \frac{|k + 5|}{5}. For tangency, this distance must equal the radius: k+55=3\frac{|k + 5|}{5} = 3, which gives k+5=15|k + 5| = 15. Solving this absolute value equation gives k=10k = 10 or k=20k = -20. Since kk must be positive, the value is 10.

Adım Adım Çözüm

1
Complete the square for the circle's equation x2+y22x4y=4x^2 + y^2 - 2x - 4y = 4.
(x1)2+(y2)2=9(x - 1)^2 + (y - 2)^2 = 9, which represents a circle with center (1,2)(1, 2) and radius R=3R = 3.
To find the center and radius of the circle, which are needed to use the distance formula.
2
Express the distance dd from the center (1,2)(1, 2) to the line 3x4yk=03x - 4y - k = 0 using the formula d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}.
d=3(1)4(2)k32+(4)2=5k5=k+55d = \frac{|3(1) - 4(2) - k|}{\sqrt{3^2 + (-4)^2}} = \frac{|-5 - k|}{5} = \frac{|k + 5|}{5}.
A line is tangent to a circle if and only if the distance from the center of the circle to the line equals the radius.
3
Set the distance equal to the radius (33) and solve for kk.
k+55=3k+5=15\frac{|k + 5|}{5} = 3 \Rightarrow |k + 5| = 15, which yields k+5=15k=10k + 5 = 15 \Rightarrow k = 10, or k+5=15k=20k + 5 = -15 \Rightarrow k = -20.
To find the values of kk that make the line tangent to the circle.
4
Select the positive value of kk.
k=10k = 10.
The problem specifies that k>0k > 0.

Anahtar Kavram

Systems of Linear and Non-Linear Equations
Tahmini Süre:2m 30s
Soru 150Soru

Consider the function ff defined on the domain [23,)[\frac{2}{3}, \infty) by the equation f(x)=2+3x2f(x) = 2 + \sqrt{3x - 2}. If f1f^{-1} represents the inverse of ff, what is the only real value of xx for which f(x)=f1(x)f(x) = f^{-1}(x)?

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Cevap: 6

Cevap

The only real value of xx for which f(x)=f1(x)f(x) = f^{-1}(x) is 6.
For a strictly increasing function, the intersection of f(x)f(x) and f1(x)f^{-1}(x) must occur on the line y=xy = x. Equating f(x)=xf(x) = x gives 2+3x2=x2 + \sqrt{3x - 2} = x. Isolating the radical term yields 3x2=x2\sqrt{3x - 2} = x - 2. Squaring both sides produces 3x2=x24x+43x - 2 = x^2 - 4x + 4, which simplifies to the quadratic equation x27x+6=0x^2 - 7x + 6 = 0. Factoring this equation gives (x6)(x1)=0(x - 6)(x - 1) = 0, yielding the solutions x=6x = 6 and x=1x = 1. Substituting these back into the original equation shows that x=6x = 6 is a valid solution (2+16=62 + \sqrt{16} = 6), whereas x=1x = 1 is extraneous because it results in 2+1=312 + 1 = 3 \neq 1. Furthermore, the domain of f1f^{-1} is the range of ff, which is [2,)[2, \infty), meaning f1(1)f^{-1}(1) is undefined. Thus, the only real solution is 6.

Adım Adım Çözüm

1
Equate the function to xx using properties of increasing functions and their inverses.
Since f(x)f(x) is strictly increasing on its domain [23,)[\frac{2}{3}, \infty), the graph of f(x)f(x) and the graph of its inverse f1(x)f^{-1}(x) can only intersect on the line of symmetry y=xy = x. Therefore, the equation f(x)=f1(x)f(x) = f^{-1}(x) is equivalent to f(x)=xf(x) = x.
This simplifies the relation by eliminating the need to solve a high-degree polynomial equation derived from direct composition or substitution.
2
Set up the equation f(x)=xf(x) = x and isolate the radical term.
2+3x2=x    3x2=x22 + \sqrt{3x - 2} = x \implies \sqrt{3x - 2} = x - 2
Isolating the square root term is a necessary prerequisite step before squaring both sides.
3
Square both sides and rewrite the equation as a standard quadratic equation.
3x2=(x2)2    3x2=x24x+4    x27x+6=03x - 2 = (x - 2)^2 \implies 3x - 2 = x^2 - 4x + 4 \implies x^2 - 7x + 6 = 0
Squaring eliminates the radical to yield a standard quadratic equation that can be solved analytically.
4
Solve the quadratic equation by factoring.
(x6)(x1)=0    x=6 or x=1(x - 6)(x - 1) = 0 \implies x = 6 \text{ or } x = 1
Factoring the quadratic trinomial yields the two candidate values for xx.
5
Check the candidate solutions in the original equation to eliminate extraneous roots.
For x=1x = 1: 2+3(1)2=312 + \sqrt{3(1)-2} = 3 \neq 1 (extraneous). For x=6x = 6: 2+3(6)2=2+4=62 + \sqrt{3(6)-2} = 2 + 4 = 6 (valid). Also, the domain of f1f^{-1} is the range of ff, which is [2,)[2, \infty), thus excluding x=1x = 1.
Squaring both sides can introduce extraneous roots. We must verify that the solutions satisfy the original radical equation and fall within the domains of both ff and f1f^{-1}.

Anahtar Kavram

Applying the symmetry of inverse functions about the line y=xy=x to solve composition-based equations, while rigorously accounting for domain restrictions and extraneous roots.

Alternatif Yöntem

Find the algebraic formula for f1(x)f^{-1}(x) by setting y=2+3x2y = 2 + \sqrt{3x-2}. Subtracting 2 and squaring both sides gives (y2)2=3x2(y - 2)^2 = 3x - 2 for y2y \geq 2. Solving for xx yields f1(x)=(x2)2+23f^{-1}(x) = \frac{(x - 2)^2 + 2}{3} for x2x \geq 2. Equating f(x)=f1(x)f(x) = f^{-1}(x) results in 2+3x2=(x2)2+232 + \sqrt{3x - 2} = \frac{(x - 2)^2 + 2}{3}. Multiplying by 3 and isolating the radical term gives 33x2=x24x3\sqrt{3x - 2} = x^2 - 4x. Squaring both sides results in a fourth-degree polynomial equation: 9(3x2)=(x24x)2    x48x3+16x227x+18=09(3x - 2) = (x^2 - 4x)^2 \implies x^4 - 8x^3 + 16x^2 - 27x + 18 = 0. This factors into (x6)(x1)(x2x+3)=0(x - 6)(x - 1)(x^2 - x + 3) = 0. Since the domain of f1(x)f^{-1}(x) is restricted to x2x \geq 2, the root x=1x = 1 is rejected, and the quadratic factor x2x+3=0x^2 - x + 3 = 0 has no real roots, leaving x=6x = 6 as the unique real solution.
Tahmini Süre:3m 0s
Soru 151Soru

Let matrix X=[5321]X = \begin{bmatrix} 5 & -3 \\ 2 & 1 \end{bmatrix} and matrix Y=[1423]Y = \begin{bmatrix} 1 & 4 \\ -2 & 3 \end{bmatrix}. If Z=XYZ = X - Y, what is the value of the element in the first row and second column of ZZ?

Cevabı ve açıklamayı göster

Cevap: -7

Cevap

The correct answer is 7-7.
To find the element in the first row and second column of matrix Z=XYZ = X - Y, we subtract the element in the first row and second column of matrix YY from the corresponding element in matrix XX. The element in the first row and second column of XX is 3-3, and the element in the first row and second column of YY is 44. Subtracting these values gives 34=7-3 - 4 = -7.

Adım Adım Çözüm

1
Identify the elements in the first row and second column for both matrices.
x1,2=3x_{1,2} = -3 and y1,2=4y_{1,2} = 4
To find the element in the first row and second column of the resulting matrix ZZ, we must use the corresponding elements from matrices XX and YY.
2
Subtract the element of YY from the element of XX.
34=7-3 - 4 = -7
Since Z=XYZ = X - Y, each element zi,jz_{i,j} of the resulting matrix is calculated as xi,jyi,jx_{i,j} - y_{i,j}.

Anahtar Kavram

Matrix Subtraction
Soru 152Soru

What is the sum of the two solutions to the quadratic equation 2x27x4=02x^2 - 7x - 4 = 0?

Cevabı ve açıklamayı göster

Cevap: 3.5

Cevap

The sum of the solutions is 3.53.5.
The sum of the solutions of the quadratic equation 2x27x4=02x^2 - 7x - 4 = 0 is 3.53.5. According to Vieta's formulas, the sum of the roots of a quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0 is given by ba-\frac{b}{a}. Here, a=2a = 2 and b=7b = -7, so the sum is 72=3.5-\frac{-7}{2} = 3.5. Alternatively, solving the equation using the quadratic formula yields the roots 44 and 0.5-0.5, which sum to 3.53.5.

Adım Adım Çözüm

1
Identify the coefficients from the quadratic equation 2x27x4=02x^2 - 7x - 4 = 0.
a=2a = 2, b=7b = -7, and c=4c = -4.
A quadratic equation in standard form is written as ax2+bx+c=0ax^2 + bx + c = 0.
2
Apply the sum of roots formula ba-\frac{b}{a}.
Sum =72=3.5= -\frac{-7}{2} = 3.5.
By Vieta's formulas, the sum of the roots of ax2+bx+c=0ax^2 + bx + c = 0 is ba-\frac{b}{a}.

Anahtar Kavram

Sum of roots of a quadratic equation using Vieta's formulas

Alternatif Yöntem

Solve the quadratic equation by factoring or using the quadratic formula. Factoring 2x27x4=02x^2 - 7x - 4 = 0 yields (2x+1)(x4)=0(2x + 1)(x - 4) = 0, which gives solutions x=0.5x = -0.5 and x=4x = 4. Adding these solutions together gives 0.5+4=3.5-0.5 + 4 = 3.5.
Tahmini Süre:1m 0s
Soru 153Soru

The polynomial P(x)P(x) is defined by P(x)=(2x23x+5)24x(x32x27x+1)P(x) = (2x^2 - 3x + 5)^2 - 4x(x^3 - 2x^2 - 7x + 1). When P(x)P(x) is written in standard form, what is the coefficient of the x2x^2 term?

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Cevap: 57

Cevap

The coefficient of the x2x^2 term is 57.
Expanding (2x23x+5)2(2x^2 - 3x + 5)^2 yields (2x23x+5)(2x23x+5)=4x412x3+29x230x+25(2x^2 - 3x + 5)(2x^2 - 3x + 5) = 4x^4 - 12x^3 + 29x^2 - 30x + 25. Distributing the 4x-4x term yields 4x(x32x27x+1)=4x4+8x3+28x24x-4x(x^3 - 2x^2 - 7x + 1) = -4x^4 + 8x^3 + 28x^2 - 4x. Combining the x2x^2 terms from both expressions gives 29x2+28x2=57x229x^2 + 28x^2 = 57x^2. Thus, the coefficient of the x2x^2 term is 57.

Adım Adım Çözüm

1
Expand the squared trinomial (2x23x+5)2(2x^2 - 3x + 5)^2
4x412x3+29x230x+254x^4 - 12x^3 + 29x^2 - 30x + 25
Expanding the first part of the expression by multiplying the trinomial by itself.
2
Distribute the term 4x-4x to the trinomial (x32x27x+1)(x^3 - 2x^2 - 7x + 1)
4x4+8x3+28x24x-4x^4 + 8x^3 + 28x^2 - 4x
Expanding the second part of the polynomial expression while distributing the negative sign to all terms.
3
Combine the expanded expressions and isolate the x2x^2 terms
29x2+28x2=57x229x^2 + 28x^2 = 57x^2
Adding the coefficients of the terms of degree 2 to find the combined coefficient.

Anahtar Kavram

Operations on Polynomials
Soru 154Soru

If the quadratic expression 6x27x56x^2 - 7x - 5 is factored completely into the product of two linear binomials of the form (ax+b)(cx+d)(ax + b)(cx + d), where aa, bb, cc, and dd are integers such that a>c>0a > c > 0, what is the value of the expression adbcad - bc?

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Cevap: 13

Cevap

The value of the expression adbcad - bc is 13.

Adım Adım Çözüm

1
Factor the quadratic expression 6x27x56x^2 - 7x - 5.
(3x5)(2x+1)(3x - 5)(2x + 1)
Find two numbers that multiply to 6×(5)=306 \times (-5) = -30 and add to 7-7, which are 10-10 and 33. Rewrite the middle term and factor by grouping: 6x210x+3x5=2x(3x5)+1(3x5)=(3x5)(2x+1)6x^2 - 10x + 3x - 5 = 2x(3x - 5) + 1(3x - 5) = (3x - 5)(2x + 1).
2
Determine the values of the coefficients aa, bb, cc, and dd.
a=3a = 3, b=5b = -5, c=2c = 2, and d=1d = 1
The expression is factored into the form (ax+b)(cx+d)(ax + b)(cx + d) where a>c>0a > c > 0. Comparing the factors (3x5)(3x - 5) and (2x+1)(2x + 1), we see the coefficients of xx are 33 and 22. Since 3>2>03 > 2 > 0, we have a=3a = 3 and c=2c = 2. This leaves b=5b = -5 and d=1d = 1.
3
Calculate the value of adbcad - bc.
13
Substitute a=3a = 3, b=5b = -5, c=2c = 2, and d=1d = 1 into the expression: adbc=(3)(1)(5)(2)=3+10=13ad - bc = (3)(1) - (-5)(2) = 3 + 10 = 13.

Anahtar Kavram

Factoring quadratic polynomials of the form ax2+bx+cax^2 + bx + c with a>1a > 1.
Soru 155Soru

What is the value of the larger real solution to the equation 10x3x1=2\frac{10}{x} - \frac{3}{x-1} = 2?

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Cevap: 2.5

Cevap

The larger real solution is 2.52.5.
Multiplying the equation by the least common denominator x(x1)x(x-1) yields 10(x1)3x=2x(x1)10(x-1) - 3x = 2x(x-1). Simplifying this leads to 2x29x+10=02x^2 - 9x + 10 = 0. Factoring the quadratic yields (2x5)(x2)=0(2x-5)(x-2) = 0, which gives the solutions x=2.5x = 2.5 and x=2x = 2. The larger of these two solutions is 2.52.5.

Adım Adım Çözüm

1
Multiply the entire equation by the least common denominator, which is x(x1)x(x-1), for x0x \neq 0 and x1x \neq 1.
10(x1)3x=2x(x1)10(x-1) - 3x = 2x(x-1)
This clears the fractions from the rational equation.
2
Expand both sides of the equation.
10x103x=2x22x10x - 10 - 3x = 2x^2 - 2x
Expanding the terms allows us to combine like terms.
3
Combine like terms on the left side and move all terms to one side to set the quadratic equation equal to zero.
2x29x+10=02x^2 - 9x + 10 = 0
Setting the quadratic equation to zero is required to solve it by factoring.
4
Factor the quadratic equation by grouping.
(2x5)(x2)=0(2x-5)(x-2) = 0
Factoring allows us to find the roots of the quadratic equation.
5
Solve for xx by setting each factor equal to zero.
x=2.5x = 2.5 or x=2x = 2
By the zero product property, at least one of the factors must be zero.
6
Check for extraneous solutions and select the larger real value.
Both 22 and 2.52.5 are valid because they do not make the original denominators zero. The larger value is 2.52.5.
The question specifically asks for the larger of the two real solutions.

Anahtar Kavram

Solving rational equations by clearing denominators
Tahmini Süre:1m 30s
Soru 156Soru
If xx and yy are positive real numbers such that
(x3y2)k(x1y4)3=x6y6(x^3 y^{-2})^k \cdot (x^{-1} y^4)^3 = x^6 y^6
what is the value of the exponent kk?
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Cevap: 3

Cevap

The value of the exponent kk is 3.
Applying the exponent rules simplifies the left side of the equation to x3k3y122kx^{3k-3}y^{12-2k}. Equating the exponent of xx to the right side gives 3k3=63k - 3 = 6, which yields k=3k = 3. This value is confirmed by equating the exponent of yy, since 122(3)=612 - 2(3) = 6.

Adım Adım Çözüm

1
Apply the power of a power rule (am)n=amn(a^m)^n = a^{mn} to expand the terms in the expression.
(x3y2)k=x3ky2k(x^3 y^{-2})^k = x^{3k} y^{-2k} and (x1y4)3=x3y12(x^{-1} y^4)^3 = x^{-3} y^{12}
To remove the outer parentheses by multiplying the internal exponents of each variable by the outer exponent.
2
Multiply the terms together by applying the product rule for exponents, aman=am+na^m \cdot a^n = a^{m+n}.
(x3ky2k)(x3y12)=x3k3y122k(x^{3k} y^{-2k})(x^{-3} y^{12}) = x^{3k-3} y^{12-2k}
To combine the like bases of xx and yy into a single simplified expression.
3
Set the exponents of like bases equal to the exponents on the right-hand side of the equation, x6y6x^6 y^6.
3k3=63k - 3 = 6 and 122k=612 - 2k = 6
Since the bases are equal and non-zero, their respective exponents must also be equal.
4
Solve the linear equation 3k3=63k - 3 = 6 for kk.
3k=9    k=33k = 9 \implies k = 3
To determine the numerical value of the variable kk.
5
Verify the solution by solving the second linear equation, 122k=612 - 2k = 6.
2k=6    k=3-2k = -6 \implies k = 3
To ensure consistency across both variable exponents in the expression.

Anahtar Kavram

Properties of Exponents in Algebraic Expressions
Soru 157Soru

Let the function hh be defined by h(x)=3x5h(x) = 3x - 5, and let the function gg be defined by g(x)=x2+cg(x) = x^2 + c for some constant cc. If h(g(2))=10h(g(2)) = 10, what is the value of cc?

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Cevap: 1

Cevap

The value of the constant cc is 11.
The correct answer is 11. Evaluating the inner function g(2)g(2) gives 22+c=4+c2^2 + c = 4 + c. Applying the outer function h(x)h(x) to this expression gives h(4+c)=3(4+c)5h(4 + c) = 3(4 + c) - 5. Simplifying this expression results in 12+3c5=7+3c12 + 3c - 5 = 7 + 3c. We are given that this value equals 1010, so 7+3c=107 + 3c = 10. Subtracting 7 from both sides gives 3c=33c = 3, which yields c=1c = 1.

Adım Adım Çözüm

1
Evaluate g(2)g(2) in terms of cc
g(2)=4+cg(2) = 4 + c
We substitute x=2x = 2 into the definition g(x)=x2+cg(x) = x^2 + c to get 22+c=4+c2^2 + c = 4 + c.
2
Substitute g(2)g(2) into the definition of h(x)h(x) to express h(g(2))h(g(2))
h(g(2))=3(4+c)5h(g(2)) = 3(4 + c) - 5
Since the composition is h(g(2))h(g(2)), we evaluate the function hh at the input value g(2)=4+cg(2) = 4 + c.
3
Set h(g(2))=10h(g(2)) = 10 and solve the linear equation for cc
c=1c = 1
Expanding and simplifying the equation 3(4+c)5=103(4 + c) - 5 = 10 gives 12+3c5=1012 + 3c - 5 = 10, which reduces to 7+3c=107 + 3c = 10. Subtracting 7 gives 3c=33c = 3, so c=1c = 1.

Anahtar Kavram

Function Composition and Parameter Evaluation
Tahmini Süre:1m 15s
Soru 158Soru

What is the smallest integer value of xx that satisfies the inequality 113x<211 - 3x < 2?

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Cevap: 4

Cevap

The smallest integer value of xx that satisfies the inequality is 4.
Solving the inequality 113x<211 - 3x < 2 leads to 3x<9-3x < -9. Dividing by 3-3 and reversing the inequality sign gives x>3x > 3. The smallest integer that is strictly greater than 3 is 4.

Adım Adım Çözüm

1
Isolate the variable term on one side of the inequality by subtracting 11 from both sides.
3x<9-3x < -9
Subtracting 11 from both sides of the inequality keeps the relationship balanced.
2
Divide both sides of the inequality by the coefficient of xx, which is 3-3.
x>3x > 3
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.
3
Determine the smallest integer that is strictly greater than 3.
4
Since the inequality is strict (x>3x > 3), 3 is not included in the solution set. The smallest integer greater than 3 is 4.

Anahtar Kavram

Solving linear inequalities and reversing the inequality sign when dividing by a negative number.
Soru 159Soru

The matrices MM and NN are defined as follows:

M=[4213],N=[2501]M = \begin{bmatrix} 4 & -2 \\ 1 & 3 \end{bmatrix}, \quad N = \begin{bmatrix} 2 & 5 \\ 0 & -1 \end{bmatrix}

If the product matrix PP is defined by the equation P=MNP = MN, what is the value of the element in the first row and second column of PP?

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Cevap: 22

Cevap

The value of the element in the first row and second column of PP is 22.
To find the element in the first row and second column of the product matrix P=MNP = MN, we calculate the dot product of the first row of matrix MM ([4,2][4, -2]) and the second column of matrix NN ([51]\begin{bmatrix} 5 \\ -1 \end{bmatrix}): 4(5)+(2)(1)=20+2=224(5) + (-2)(-1) = 20 + 2 = 22.

Adım Adım Çözüm

1
Determine the row of the left matrix and the column of the right matrix needed for the target element.
To find the element in row 1, column 2 of P=MNP = MN, use the first row of MM, which is [4,2][4, -2], and the second column of NN, which is [51]\begin{bmatrix} 5 \\ -1 \end{bmatrix}.
The entry in row ii and column jj of a product matrix is the dot product of row ii of the first matrix and column jj of the second matrix.
2
Compute the dot product of the selected row and column.
(4×5)+(2×1)=20+2(4 \times 5) + (-2 \times -1) = 20 + 2
Multiply corresponding elements and sum the products.
3
Simplify to get the final numeric answer.
22
Adding 20 and 2 yields 22.

Anahtar Kavram

Matrix multiplication involves multiplying the rows of the first matrix by the columns of the second matrix.
Soru 160Soru

A triangle has a base of 2x+42x + 4 inches and a height of x3x - 3 inches. What is the coefficient of xx when the expression representing the area of the triangle, in square inches, is written in standard form?

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Cevap: -1

Cevap

The coefficient of xx is 1-1.
The area of a triangle is calculated using Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}. Substituting the given expressions, we get Area=12(2x+4)(x3)\text{Area} = \frac{1}{2}(2x + 4)(x - 3). First, we can multiply the 12\frac{1}{2} by (2x+4)(2x + 4), which simplifies to x+2x + 2. Next, we expand (x+2)(x3)(x + 2)(x - 3) using FOIL to get x23x+2x6x^2 - 3x + 2x - 6. Combining like terms yields x2x6x^2 - x - 6. The coefficient of the xx term in this simplified expression is 1-1.

Adım Adım Çözüm

1
State the formula for the area of a triangle.
Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
To establish the mathematical relationship.
2
Substitute the given values into the formula.
Area=12(2x+4)(x3)\text{Area} = \frac{1}{2}(2x + 4)(x - 3)
To express the area in terms of the variable xx.
3
Distribute the fraction to the first binomial.
x+2x + 2
Distributing 12\frac{1}{2} to (2x+4)(2x + 4) simplifies the expression before multiplying.
4
Expand the product of the binomials.
x23x+2x6x^2 - 3x + 2x - 6
Using the FOIL method to multiply (x+2)(x + 2) and (x3)(x - 3).
5
Combine the linear terms.
x2x6x^2 - x - 6
To simplify the polynomial and write it in standard form.
6
Identify the coefficient of xx.
1-1
The coefficient of the xx term in x2x6x^2 - x - 6 is 1-1.

Anahtar Kavram

Multiplying binomials and applying formulas in geometric contexts
Tahmini Süre:1m 0s
ÖncekiSayfa 8 / 28Sonraki
Tüm alıştırma soruları — ACT | Examkin