Tüm alıştırma soruları

5556 soru

Soru 1841Soru

Which of the following expressions is equivalent to 12x84x2\frac{12x^8}{4x^2} for all x0x \neq 0?

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Cevap: 3x63x^6

Cevap

The expression 3x63x^6
To simplify the expression, divide the coefficients first: 124=3\frac{12}{4} = 3. Then, apply the quotient rule of exponents to the variable terms, which states that for any non-zero base, xaxb=xab\frac{x^a}{x^b} = x^{a-b}. Subtracting the exponents gives x82=x6x^{8-2} = x^6. Combining these results yields the correct expression 3x63x^6.

Adım Adım Çözüm

1
Divide the numerical coefficients of the terms.
124=3\frac{12}{4} = 3
When simplifying a fraction with algebraic terms, the coefficients are divided normally.
2
Apply the quotient rule of exponents to simplify the variable terms.
x8x2=x82=x6\frac{x^8}{x^2} = x^{8-2} = x^6
According to the quotient rule of exponents, when dividing expressions with the same base, subtract the exponent in the denominator from the exponent in the numerator.
3
Multiply the simplified coefficient and variable results together.
3x63x^6
Combining the divided coefficient and the simplified variable expression gives the final simplified result.

Anahtar Kavram

Quotient Rule of Exponents

Alternatif Yöntem

Alternatively, you can expand the exponent terms in the numerator and denominator: 12xxxxxxxx4xx\frac{12 \cdot x \cdot x \cdot x \cdot x \cdot x \cdot x \cdot x \cdot x}{4 \cdot x \cdot x}. Simplifying the coefficients gives 33, and canceling two pairs of xx from both the numerator and denominator leaves six factors of xx in the numerator, which simplifies to 3x63x^6.
Tahmini Süre:45s
Soru 1842Soru

Which of the following is the solution set for the inequality 52x<9|5 - 2x| < 9?

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Cevap: 2<x<7-2 < x < 7

Cevap

2<x<7-2 < x < 7
The correct solution is found by setting up the compound inequality 9<52x<9-9 < 5 - 2x < 9. Subtracting 55 from all parts gives 14<2x<4-14 < -2x < 4. Finally, dividing by 2-2 and reversing the inequality signs yields the interval 2<x<7-2 < x < 7.

Adım Adım Çözüm

1
Rewrite the absolute value inequality as a compound inequality.
9<52x<9-9 < 5 - 2x < 9
An absolute value inequality of the form u<c|u| < c represents all points within distance cc from 00, which translates to c<u<c-c < u < c.
2
Subtract 55 from all three parts of the inequality.
14<2x<4-14 < -2x < 4
To isolate the variable term, we perform the inverse operation of adding 55, which is subtracting 55.
3
Divide all three parts by 2-2 and reverse the inequality signs.
2<x<7-2 < x < 7
Dividing by a negative number reverses the inequality direction. Doing so gives 7>x>27 > x > -2, which is conventionally written as 2<x<7-2 < x < 7.

Anahtar Kavram

Solving absolute value inequalities of the form ax+b<c|ax + b| < c
Soru 1843Soru

A company's daily profit is modeled by the function P(x)=3x50P(x) = 3x - 50, where xx represents the number of items sold. The number of items sold depends on the number of hours the store is open, hh, according to the function x(h)=5hx(h) = 5h. What is the daily profit, in dollars, when the store is open for 88 hours?

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Cevap: 70

Cevap

70
Evaluating the composite function in the correct order, P(x(8))P(x(8)), yields 7070. First, find the number of items sold when the store is open for 8 hours: x(8)=5(8)=40x(8) = 5(8) = 40. Then, calculate the daily profit by substituting this output into the profit function: P(40)=3(40)50=12050=70P(40) = 3(40) - 50 = 120 - 50 = 70.

Adım Adım Çözüm

1
Determine the number of items sold, xx, when the store is open for 88 hours by evaluating the function x(h)=5hx(h) = 5h at h=8h = 8.
x(8)=5×8=40x(8) = 5 \times 8 = 40 items.
The number of items sold is the input for the profit function.
2
Substitute the number of items sold (x=40x = 40) into the profit function P(x)=3x50P(x) = 3x - 50.
P(40)=3(40)50=12050=70P(40) = 3(40) - 50 = 120 - 50 = 70 dollars.
Evaluating the profit function at the given number of items sold determines the final daily profit.

Anahtar Kavram

Evaluating a composite function by finding the output of the inner function and using it as the input for the outer function.
Tahmini Süre:1m 0s
Soru 1844Soru

What is the sum of the solutions to the equation 3(x2)2=6x+363(x - 2)^2 = -6x + 36?

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Cevap: 2

Cevap

The sum of the solutions is 2.
The correct answer is 2. Expanding the equation correctly and rearranging it into standard form yields x22x8=0x^2 - 2x - 8 = 0. Factoring this expression gives (x4)(x+2)=0(x - 4)(x + 2) = 0, which results in the solutions x=4x = 4 and x=2x = -2. The sum of these two solutions is 4+(2)=24 + (-2) = 2.

Adım Adım Çözüm

1
Divide both sides of the equation by 3 to simplify.
(x2)2=2x+12(x - 2)^2 = -2x + 12
Dividing both sides by the common factor of 3 simplifies the coefficients, making the algebraic manipulation and factoring steps easier.
2
Expand the squared binomial on the left side.
x24x+4=2x+12x^2 - 4x + 4 = -2x + 12
Expanding the binomial (x2)2(x - 2)^2 using the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 is necessary to write the equation in standard form.
3
Move all terms to the left side to set the equation equal to zero.
x22x8=0x^2 - 2x - 8 = 0
A quadratic equation must be in the standard form ax2+bx+c=0ax^2 + bx + c = 0 to solve it by factoring.
4
Factor the quadratic trinomial.
(x4)(x+2)=0(x - 4)(x + 2) = 0
We find two numbers that multiply to 8-8 and add to 2-2. These numbers are 4-4 and 22.
5
Set each factor to zero to solve for the roots.
x=4x = 4 or x=2x = -2
By the zero product property, if the product of two factors is zero, at least one factor must equal zero.
6
Calculate the sum of the solutions.
4+(2)=24 + (-2) = 2
The question asks for the sum of the solutions, so we add the two calculated values of xx.

Anahtar Kavram

Solving quadratic equations by expanding, rearranging into standard form, and factoring over the integers.
Soru 1845Soru

A set of 1010 distinct positive integers has a median of 2525 and a range of 3030. What is the greatest possible value of the mean of these 1010 integers?

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Cevap: 33

Cevap

The greatest possible value of the mean of the 10 integers is 33.
The correct answer is 33. To find the greatest possible mean of the 10 distinct positive integers, we must maximize their sum. Let the sorted integers be x1<x2<x3<x4<x5<x6<x7<x8<x9<x10x_1 < x_2 < x_3 < x_4 < x_5 < x_6 < x_7 < x_8 < x_9 < x_{10}. The median is the average of the 5th and 6th terms, so x5+x62=25\frac{x_5 + x_6}{2} = 25, or x5+x6=50x_5 + x_6 = 50. Since the integers are distinct, the maximum value for x5x_5 is 24, which forces x6=26x_6 = 26. To maximize the sum of the first five terms, they should be consecutive integers ending at 24: x1=20,x2=21,x3=22,x4=23,x5=24x_1 = 20, x_2 = 21, x_3 = 22, x_4 = 23, x_5 = 24. Since the range is 30, the maximum value is x10=x1+30=20+30=50x_{10} = x_1 + 30 = 20 + 30 = 50. To maximize the remaining terms in the upper half, we choose the largest possible distinct integers less than 50: x7=47,x8=48,x9=49x_7 = 47, x_8 = 48, x_9 = 49. The maximum sum is 20+21+22+23+24+26+47+48+49+50=33020 + 21 + 22 + 23 + 24 + 26 + 47 + 48 + 49 + 50 = 330, yielding a maximum mean of 330/10=33330 / 10 = 33.

Adım Adım Çözüm

1
Define the variables and apply the median constraint.
Let the 10 sorted distinct positive integers be x1<x2<x3<x4<x5<x6<x7<x8<x9<x10x_1 < x_2 < x_3 < x_4 < x_5 < x_6 < x_7 < x_8 < x_9 < x_{10}. The median is the average of the 5th and 6th terms: x5+x62=25\frac{x_5 + x_6}{2} = 25, which means x5+x6=50x_5 + x_6 = 50.
Since the number of terms is even, the median is the average of the two middle terms.
2
Maximize the first five integers to find the maximum value of the first term.
Since the integers are distinct, we must have x5<x6x_5 < x_6. With x5+x6=50x_5 + x_6 = 50, the maximum possible integer value for x5x_5 is 24 (which makes x6=26x_6 = 26). To maximize the sum, we make the preceding terms as large as possible: x4=23x_4 = 23, x3=22x_3 = 22, x2=21x_2 = 21, and x1=20x_1 = 20.
To maximize the mean, we must maximize the sum of all terms, which requires making each term as large as possible within the distinct integer constraints.
3
Apply the range constraint to find the maximum value of the last term.
The range is 30, so x10x1=30x_{10} - x_1 = 30. Since the maximum value of x1x_1 is 20, the maximum possible value for x10x_{10} is 20+30=5020 + 30 = 50.
The range of a dataset is the difference between the maximum and minimum values.
4
Maximize the remaining terms in the upper half of the dataset.
We have x6=26x_6 = 26. The remaining terms must satisfy 26<x7<x8<x9<x10=5026 < x_7 < x_8 < x_9 < x_{10} = 50. To maximize the sum, we choose the largest possible distinct integers for these slots: x9=49x_9 = 49, x8=48x_8 = 48, and x7=47x_7 = 47.
This maximizes the sum of the upper half of the dataset under the constraint that the maximum value is 50.
5
Calculate the maximum sum and the resulting maximum mean.
Sum = 20+21+22+23+24+26+47+48+49+50=33020 + 21 + 22 + 23 + 24 + 26 + 47 + 48 + 49 + 50 = 330. Mean = 33010=33\frac{330}{10} = 33.
The mean is calculated by dividing the sum of the elements by the number of elements.

Anahtar Kavram

Maximizing the mean of a bounded dataset using median, range, and distinctness constraints.
Soru 1846Soru

For a real number xx, the equation 2(x+5)=162(x + 5) = 16 is true. What is the value of the expression 3x13x - 1?

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Cevap: 8

Cevap

The value of the expression 3x13x - 1 is 8.
Solving the equation 2(x+5)=162(x + 5) = 16 gives x=3x = 3. Evaluating the expression 3x13x - 1 for x=3x = 3 yields 3(3)1=83(3) - 1 = 8.

Adım Adım Çözüm

1
Distribute the 2 on the left side of the equation.
2x+10=162x + 10 = 16
To eliminate the parentheses using the distributive property.
2
Subtract 10 from both sides of the equation.
2x=62x = 6
To isolate the variable term on one side of the equation.
3
Divide both sides of the equation by 2.
x=3x = 3
To find the value of xx.
4
Substitute the value of xx into the expression 3x13x - 1.
3(3)1=83(3) - 1 = 8
To evaluate the final expression as requested by the question.

Anahtar Kavram

Solving multi-step linear equations and evaluating algebraic expressions.
Tahmini Süre:45s
Soru 1847Soru

What is the positive real solution to the equation 3x22x=1\frac{3}{x-2} - \frac{2}{x} = 1?

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Cevap: 4

Cevap

The positive real solution to the equation is 4.
By multiplying the entire equation by the least common denominator, x(x2)x(x-2), the rational equation is cleared of fractions, resulting in 3x2(x2)=x(x2)3x - 2(x-2) = x(x-2). Simplifying this yields the quadratic equation x23x4=0x^2 - 3x - 4 = 0. Factoring the quadratic equation gives (x4)(x+1)=0(x - 4)(x + 1) = 0, which has roots of x=4x = 4 and x=1x = -1. The positive solution is 4.

Adım Adım Çözüm

1
Multiply both sides of the equation by the least common denominator, x(x2)x(x-2), to eliminate the fractions.
3x2(x2)=x(x2)3x - 2(x-2) = x(x-2)
Eliminating the denominators simplifies the rational equation into a polynomial equation.
2
Distribute and combine like terms to simplify both sides of the equation.
x+4=x22xx + 4 = x^2 - 2x
Simplification is necessary before rearranging the equation into a solvable form.
3
Rearrange the terms into standard quadratic form: ax2+bx+c=0ax^2 + bx + c = 0.
x23x4=0x^2 - 3x - 4 = 0
Setting the quadratic expression equal to zero allows for factoring and solving.
4
Factor the quadratic equation.
(x4)(x+1)=0(x - 4)(x + 1) = 0
Finding the factors reveals the potential values for xx.
5
Solve for the roots and select the positive real solution.
x=4x = 4
The equation yields two solutions, x=4x = 4 and x=1x = -1, and the question explicitly requests the positive solution.

Anahtar Kavram

Solving rational equations by converting them to quadratic equations using the least common denominator.
Soru 1848Soru

For the imaginary unit ii, where i2=1i^2 = -1, what is the value of the expression (3+2i)2(32i)2(3 + 2i)^2 - (3 - 2i)^2?

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Cevap: 24i24i

Cevap

The correct answer is 24i24i.
The expression can be simplified by expanding each binomial term first. The first term, (3+2i)2(3 + 2i)^2, expands to 9+12i+4i29 + 12i + 4i^2. Since i2=1i^2 = -1, this simplifies to 9+12i4=5+12i9 + 12i - 4 = 5 + 12i. The second term, (32i)2(3 - 2i)^2, expands to 912i+4i29 - 12i + 4i^2, which simplifies to 912i4=512i9 - 12i - 4 = 5 - 12i. Subtracting the second simplified term from the first gives (5+12i)(512i)=55+12i(12i)=24i(5 + 12i) - (5 - 12i) = 5 - 5 + 12i - (-12i) = 24i.

Adım Adım Çözüm

1
Expand the first squared binomial expression, (3+2i)2(3 + 2i)^2.
(3+2i)2=9+12i+4i2=9+12i4=5+12i(3 + 2i)^2 = 9 + 12i + 4i^2 = 9 + 12i - 4 = 5 + 12i
Apply the binomial squaring formula (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2 and use the property of the imaginary unit where i2=1i^2 = -1.
2
Expand the second squared binomial expression, (32i)2(3 - 2i)^2.
(32i)2=912i+4i2=912i4=512i(3 - 2i)^2 = 9 - 12i + 4i^2 = 9 - 12i - 4 = 5 - 12i
Apply the binomial squaring formula (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2 and use the property of the imaginary unit where i2=1i^2 = -1.
3
Subtract the second expanded expression from the first.
(5+12i)(512i)=5+12i5+12i=24i(5 + 12i) - (5 - 12i) = 5 + 12i - 5 + 12i = 24i
Distribute the negative sign to both terms of the second complex number and combine the real and imaginary parts.

Anahtar Kavram

Complex Numbers and Operations
Soru 1849Soru

The cubic polynomial 2x3+5x28x202x^3 + 5x^2 - 8x - 20 can be factored completely over the integers into the form (xa)(x+b)(cx+d)(x - a)(x + b)(cx + d), where aa, bb, cc, and dd are positive integers. What is the value of a+b+c+da + b + c + d?

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Cevap: 11

Cevap

The value of a+b+c+da + b + c + d is 11.
The polynomial 2x3+5x28x202x^3 + 5x^2 - 8x - 20 can be factored completely by first grouping the terms as x2(2x+5)4(2x+5)=(x24)(2x+5)x^2(2x + 5) - 4(2x + 5) = (x^2 - 4)(2x + 5). Factoring the difference of squares x24x^2 - 4 yields (x2)(x+2)(2x+5)(x - 2)(x + 2)(2x + 5). Matching this to the given form (xa)(x+b)(cx+d)(x - a)(x + b)(cx + d) gives the positive integers a=2a = 2, b=2b = 2, c=2c = 2, and d=5d = 5. The sum of these values is 2+2+2+5=112 + 2 + 2 + 5 = 11.

Adım Adım Çözüm

1
Group the terms of the polynomial 2x3+5x28x202x^3 + 5x^2 - 8x - 20.
(2x3+5x2)(8x+20)(2x^3 + 5x^2) - (8x + 20)
Grouping the terms allows us to look for common factors within each pair of terms.
2
Factor out the greatest common factor (GCF) from each group.
x2(2x+5)4(2x+5)x^2(2x + 5) - 4(2x + 5)
The GCF of the first group 2x3+5x22x^3 + 5x^2 is x2x^2, and the GCF of the second group 8x+208x + 20 is 44.
3
Factor out the common binomial factor (2x+5)(2x + 5).
(x24)(2x+5)(x^2 - 4)(2x + 5)
Both terms share the binomial factor (2x+5)(2x + 5).
4
Factor the difference of squares x24x^2 - 4.
(x2)(x+2)(2x+5)(x - 2)(x + 2)(2x + 5)
The term x24x^2 - 4 is a difference of squares, which factors as (x2)(x+2)(x - 2)(x + 2).
5
Compare the factored expression with the template (xa)(x+b)(cx+d)(x - a)(x + b)(cx + d) to determine the values of aa, bb, cc, and dd.
a=2a = 2, b=2b = 2, c=2c = 2, and d=5d = 5
Comparing the terms yields xa=x2    a=2x - a = x - 2 \implies a = 2, x+b=x+2    b=2x + b = x + 2 \implies b = 2, and cx+d=2x+5    c=2,d=5cx + d = 2x + 5 \implies c = 2, d = 5. All values are positive integers as required.
6
Calculate the sum a+b+c+da + b + c + d.
11
Substituting the values of the variables into the expression gives 2+2+2+5=112 + 2 + 2 + 5 = 11.

Anahtar Kavram

Factoring a cubic polynomial by grouping and then factoring the resulting difference of squares.

Alternatif Yöntem

Instead of factoring by grouping, we can use the Rational Root Theorem to find rational roots of the polynomial. The possible rational roots of 2x3+5x28x20=02x^3 + 5x^2 - 8x - 20 = 0 are of the form ±pq\pm \frac{p}{q}, where pp is a factor of 2020 and qq is a factor of 22. Testing values shows that x=2x = 2 and x=2x = -2 are roots, which corresponds to the linear factors (x2)(x - 2) and (x+2)(x + 2). Dividing the original cubic by their product, (x24)(x^2 - 4), yields the remaining linear factor (2x+5)(2x + 5).
Tahmini Süre:1m 30s
Soru 1850Soru

For the functions f(x)=x23x1f(x) = x^2 - 3x - 1 and g(x)=x1g(x) = |x - 1|, what is the product of all real values of xx for which f(g(x))=3f(g(x)) = 3?

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Cevap: -15

Cevap

The product of all real values of xx is 15-15.
The correct answer is 15-15. By substituting g(x)=x1g(x) = |x - 1| into f(x)=x23x1f(x) = x^2 - 3x - 1, we get x123x11=3|x - 1|^2 - 3|x - 1| - 1 = 3. Letting u=x1u = |x - 1| yields the quadratic u23u4=0u^2 - 3u - 4 = 0, which factors into (u4)(u+1)=0(u - 4)(u + 1) = 0. Since u0u \geq 0, we have u=4u = 4. Solving x1=4|x - 1| = 4 yields x=5x = 5 and x=3x = -3. The product of these solutions is 5×(3)=155 \times (-3) = -15.

Adım Adım Çözüm

1
Substitute the function g(x)=x1g(x) = |x - 1| into f(x)=x23x1f(x) = x^2 - 3x - 1 to form the composite function f(g(x))f(g(x)).
f(g(x))=x123x11f(g(x)) = |x - 1|^2 - 3|x - 1| - 1
To evaluate the composite function before setting it equal to 33.
2
Set the composite function equal to 33 and substitute u=x1u = |x - 1| (where u0u \geq 0) to rewrite the equation as a quadratic in terms of uu.
u23u1=3u23u4=0u^2 - 3u - 1 = 3 \Rightarrow u^2 - 3u - 4 = 0
Using substitution simplifies the absolute value equation into a standard quadratic equation.
3
Factor the quadratic equation (u4)(u+1)=0(u - 4)(u + 1) = 0 to solve for uu, and discard the extraneous solution.
u=4u = 4 or u=1u = -1. Since u=x10u = |x - 1| \geq 0, we discard u=1u = -1, leaving u=4u = 4.
The absolute value of a real expression must be non-negative, so uu cannot be 1-1.
4
Solve the absolute value equation x1=4|x - 1| = 4 for all possible real values of xx.
x1=4x=5x - 1 = 4 \Rightarrow x = 5, and x1=4x=3x - 1 = -4 \Rightarrow x = -3.
An absolute value equation A=B|A| = B (where B>0B > 0) yields two scenarios: A=BA = B and A=BA = -B.
5
Calculate the product of the two real solutions found.
5×(3)=155 \times (-3) = -15
To find the final product of all real values of xx that satisfy the equation.

Anahtar Kavram

Function composition and solving absolute value equations using quadratic substitution
Tahmini Süre:2m 0s
Soru 1851Soru

For all real numbers xx such that x1x \neq 1 and x1x \neq -1, which of the following is equivalent to the expression (1x1+1x+1)2\left(\frac{1}{x-1} + \frac{1}{x+1}\right)^2?

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Cevap: 4x2(x21)2\frac{4x^2}{(x^2-1)^2}

Cevap

The expression is equivalent to the fraction with numerator four times x squared and denominator the square of the difference x squared minus one.
The correct answer is found by first rewriting the terms inside the parentheses with the common denominator (x21)(x^2-1), which simplifies the sum to 2xx21\frac{2x}{x^2-1}. Squaring the numerator (2x)2(2x)^2 yields 4x24x^2, and squaring the denominator yields (x21)2(x^2-1)^2.

Adım Adım Çözüm

1
Find a common denominator for the two fractions inside the parentheses.
The common denominator is (x1)(x+1)=x21(x-1)(x+1) = x^2-1. The expression inside the parentheses becomes x+1x21+x1x21\frac{x+1}{x^2-1} + \frac{x-1}{x^2-1}.
To add rational expressions, they must have a common denominator.
2
Combine the numerators over the common denominator.
The sum is (x+1)+(x1)x21=2xx21\frac{(x+1) + (x-1)}{x^2-1} = \frac{2x}{x^2-1}.
Combine the like terms in the numerator to simplify the expression before squaring.
3
Square the simplified rational expression by squaring the numerator and the denominator separately.
(2xx21)2=(2x)2(x21)2=4x2(x21)2.\left(\frac{2x}{x^2-1}\right)^2 = \frac{(2x)^2}{(x^2-1)^2} = \frac{4x^2}{(x^2-1)^2}.
Apply the power of a quotient property to obtain the final simplified expression.

Anahtar Kavram

Simplifying rational expressions and applying the power of a quotient rule.
Tahmini Süre:1m 30s
Soru 1852Soru

Let the function ff be defined by f(x)=x1x+1f(x) = \frac{x - 1}{x + 1} for all real numbers x1x \neq -1. Let f1(x)=f(x)f^1(x) = f(x), and let fn(x)=f(fn1(x))f^n(x) = f(f^{n-1}(x)) for all integers n2n \geq 2. What is the value of 30f2026(3)30 \cdot f^{2026}(3)?

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Cevap: -10

Cevap

The value of the expression is -10.
Evaluating successive iterations of f(3)f(3) reveals a repeating sequence: f1(3)=1/2f^1(3) = 1/2, f2(3)=1/3f^2(3) = -1/3, f3(3)=2f^3(3) = -2, f4(3)=3f^4(3) = 3, and then f5(3)=1/2f^5(3) = 1/2. This indicates a cycle of period 4. Dividing the power 2026 by the period 4 gives a remainder of 2, meaning f2026(3)f^{2026}(3) is equal to f2(3)=1/3f^2(3) = -1/3. Multiplying this by 30 yields the final answer of -10.

Adım Adım Çözüm

1
Calculate the first few compositions of the function evaluated at the given input x=3x = 3.
f1(3)=1/2f^1(3) = 1/2, f2(3)=1/3f^2(3) = -1/3, f3(3)=2f^3(3) = -2, and f4(3)=3f^4(3) = 3.
To look for a repeating pattern or periodic behavior in the iterated function composition.
2
Identify the period of the repeating cycle.
The cycle has a length of 4, repeating the values [1/2,1/3,2,3][1/2, -1/3, -2, 3].
Since f4(3)=3f^4(3) = 3, evaluating further iterations will yield the same sequence of values.
3
Use modular arithmetic to find the value of the 2026th composition.
20262(mod4)2026 \equiv 2 \pmod 4, meaning f2026(3)=f2(3)=1/3f^{2026}(3) = f^2(3) = -1/3.
Since the cycle repeats every 4 iterations, dividing 2026 by 4 yields a remainder of 2, indicating the second value in the sequence.
4
Multiply the computed composition value by the given coefficient.
30(1/3)=1030 \cdot (-1/3) = -10.
To find the final value of the expression 30f2026(3)30 \cdot f^{2026}(3).

Anahtar Kavram

Evaluating repeated function compositions using periodicity and modular arithmetic.
Soru 1853Soru

A gardener starts with 1515 flowers already planted in a garden. She plans to plant additional flowers at a constant rate of 88 flowers per hour. How many hours will it take the gardener to have a total of 7979 flowers planted?

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Cevap: 8

Cevap

It will take the gardener 88 hours to have a total of 7979 flowers planted.
The total number of flowers planted can be modeled by the linear equation 15+8h=7915 + 8h = 79, where hh is the number of hours. Subtracting 1515 from both sides of the equation gives 8h=648h = 64. Dividing both sides by 88 reveals that h=8h = 8 hours.

Adım Adım Çözüm

1
Set up the linear equation representing the total flowers planted over time.
15+8h=7915 + 8h = 79, where hh is the number of hours.
The gardener begins with 1515 flowers and adds 88 flowers for each hour hh, with the final goal of 7979 total flowers.
2
Isolate the variable term by subtracting the initial number of flowers from the total.
8h=648h = 64
Subtracting 1515 from both sides of the equation isolates the term containing the variable hh.
3
Divide by the rate to solve for the number of hours.
h=8h = 8
Dividing the remaining flowers to be planted (6464) by the planting rate (88 flowers per hour) yields the total number of hours required.

Anahtar Kavram

Translating a real-world scenario into a linear equation and solving for the unknown variable.
Soru 1854Soru

If xx and yy are real numbers, the expression 3x(x2y)2x2(3x10y)y2(2xy)3x(x - 2y)^2 - x^2(3x - 10y) - y^2(2x - y) can be simplified to which of the following?

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Cevap: 2x2y+10xy2+y3-2x^2y + 10xy^2 + y^3

Cevap

The correct expression is 2x2y+10xy2+y3-2x^2y + 10xy^2 + y^3.
The correct expression 2x2y+10xy2+y3-2x^2y + 10xy^2 + y^3 is obtained by correctly expanding the binomial (x2y)2(x-2y)^2 into x24xy+4y2x^2 - 4xy + 4y^2, distributing the outer terms 3x3x, x2-x^2, and y2-y^2 to all terms inside their respective parentheses, and then combining the coefficients of the matching variable terms: the x3x^3 terms cancel out, the x2yx^2y terms combine to 2x2y-2x^2y, the xy2xy^2 terms combine to 10xy210xy^2, and the y3y^3 term remains.

Adım Adım Çözüm

1
Expand the binomial expression (x2y)2(x - 2y)^2.
x24xy+4y2x^2 - 4xy + 4y^2
Before distributing 3x3x, the squared binomial must be expanded using the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
2
Multiply the expanded binomial by the coefficient 3x3x.
3x312x2y+12xy23x^3 - 12x^2y + 12xy^2
Distribute 3x3x to each of the three terms in the expanded expression: 3x(x2)=3x33x(x^2) = 3x^3, 3x(4xy)=12x2y3x(-4xy) = -12x^2y, and 3x(4y2)=12xy23x(4y^2) = 12xy^2.
3
Distribute x2-x^2 to (3x10y)(3x - 10y).
3x3+10x2y-3x^3 + 10x^2y
Distribute x2-x^2 to both terms, noting that multiplying two negative signs yields a positive term: x2(3x)=3x3-x^2(3x) = -3x^3 and x2(10y)=+10x2y-x^2(-10y) = +10x^2y.
4
Distribute y2-y^2 to (2xy)(2x - y).
2xy2+y3-2xy^2 + y^3
Distribute y2-y^2 to both terms, adding the exponents of yy where appropriate: y2(2x)=2xy2-y^2(2x) = -2xy^2 and y2(y1)=+y3-y^2(-y^1) = +y^3.
5
Combine all parts and group the like terms together.
2x2y+10xy2+y3-2x^2y + 10xy^2 + y^3
Group and add the coefficients of identical variable terms: (3x33x3)+(12x2y+10x2y)+(12xy22xy2)+y3=0x32x2y+10xy2+y3(3x^3 - 3x^3) + (-12x^2y + 10x^2y) + (12xy^2 - 2xy^2) + y^3 = 0x^3 - 2x^2y + 10xy^2 + y^3.

Anahtar Kavram

Simplifying polynomial expressions with multiple variables by expanding binomials, distributing coefficients (including negative signs), and combining like terms.
Soru 1855Soru

A company produces solar-powered chargers. The daily production cost, in dollars, is a linear function of the number of chargers produced. The setup cost is the cost when 00 chargers are produced. If the company produces 1515 chargers, the total daily cost is 400400 dollars. If the company produces 2525 chargers, the total daily cost is 580580 dollars. The company updates its production process, which reduces the cost per charger by 20%20\% but increases the setup cost by 5050 dollars. Under the updated process, what is the total daily cost, in dollars, to produce 3030 chargers?

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Cevap: 612612 dollars

Cevap

The correct daily cost under the updated process is 612612 dollars.
The correct answer is 612612 dollars. First, the relationship between unit cost and setup cost is modeled as a linear equation. Subtracting the cost of producing 1515 chargers (400400 dollars) from the cost of producing 2525 chargers (580580 dollars) gives the cost of producing the 1010 additional units, which is 180180 dollars. This determines the unit cost is 1818 dollars per charger. Substituting this value back shows the original setup cost is 130130 dollars. The updated rate decreases the unit cost to 14.4014.40 dollars (80%80\% of 1818) and increases the setup cost to 180180 dollars (130+50130 + 50). For 3030 chargers, the total daily cost is 14.40(30)+180=61214.40(30) + 180 = 612 dollars.

Adım Adım Çözüm

1
Set up a system of linear equations using the cost function C(c)=mc+SC(c) = mc + S, where mm is the cost per charger, SS is the setup cost, and cc is the number of chargers.
Equation 1: 15m+S=40015m + S = 400
Equation 2: 25m+S=58025m + S = 580
This establishes the relationship between production volume and total cost under the initial process.
2
Solve the system of equations for the unit cost mm and the setup cost SS.
Subtracting Equation 1 from Equation 2 yields 10m=180    m=1810m = 180 \implies m = 18.
Substituting m=18m = 18 into Equation 1 yields 15(18)+S=400    270+S=400    S=13015(18) + S = 400 \implies 270 + S = 400 \implies S = 130.
This determines the original pricing parameters.
3
Apply the updates to the cost parameters.
New unit cost: 18×(10.20)=14.4018 \times (1 - 0.20) = 14.40 dollars.
New setup cost: 130+50=180130 + 50 = 180 dollars.
This accounts for the 20%20\% decrease in the variable cost and the 5050 dollar increase in the fixed setup cost.
4
Evaluate the new linear cost function for 3030 chargers.
Cnew(30)=14.40(30)+180=432+180=612C_{\text{new}}(30) = 14.40(30) + 180 = 432 + 180 = 612 dollars.
This calculates the total daily cost under the updated process.

Anahtar Kavram

Translating and Solving Algebraic Word Problems

Alternatif Yöntem

Instead of solving for the setup cost first, note that under the original process, the cost of 3030 chargers would be the cost of 1515 chargers plus the cost of 1515 more units: 400+15(18)=670400 + 15(18) = 670 dollars. The updated process reduces the rate of each of the 3030 units by 20%20\% of 1818 dollars (saving 3.60×30=1083.60 \times 30 = 108 dollars) and increases the setup cost by 5050 dollars. Thus, the new cost is 670108+50=612670 - 108 + 50 = 612 dollars.
Tahmini Süre:2m 0s
Soru 1856Soru

When the expression 2x(3xy)23y2(x2y)x2(18x15y)2x(3x - y)^2 - 3y^2(x - 2y) - x^2(18x - 15y) is simplified by combining like terms, what is the coefficient of x2yx^2y?

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Cevap: 3

Cevap

The coefficient of x2yx^2y is 33.
The correct coefficient of 33 is obtained by expanding the expression step-by-step. First, the square of the binomial (3xy)2(3x - y)^2 is 9x26xy+y29x^2 - 6xy + y^2. Distributing 2x2x gives 18x312x2y+2xy218x^3 - 12x^2y + 2xy^2. Next, distributing x2-x^2 to (18x15y)(18x - 15y) gives 18x3+15x2y-18x^3 + 15x^2y. Combining the x2yx^2y terms gives 12x2y+15x2y=3x2y-12x^2y + 15x^2y = 3x^2y, meaning the coefficient is 33.

Adım Adım Çözüm

1
Expand the squared binomial term (3xy)2(3x - y)^2 using the algebraic identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
(3xy)2=9x26xy+y2(3x - y)^2 = 9x^2 - 6xy + y^2
This is necessary to remove the parentheses before distributing the outer variable.
2
Multiply the term 2x2x by each term inside the expanded binomial expression: 2x(9x26xy+y2)2x(9x^2 - 6xy + y^2).
18x312x2y+2xy218x^3 - 12x^2y + 2xy^2
Applying the distributive property expands the first part of the expression.
3
Distribute x2-x^2 to the terms inside the parentheses (18x15y)(18x - 15y), paying close attention to the signs.
18x3+15x2y-18x^3 + 15x^2y
This expands the third part of the expression and correctly distributes the negative sign.
4
Identify and combine the like terms of the form x2yx^2y from the expanded parts of the expression.
12x2y+15x2y=3x2y-12x^2y + 15x^2y = 3x^2y
To find the coefficient of x2yx^2y, we only need to sum the coefficients of the terms that contain exactly x2yx^2y.

Anahtar Kavram

Simplifying Expressions and Combining Like Terms
Tahmini Süre:1m 30s
Soru 1857Soru

An electronics retailer sells tablet computers. The retailer's weekly revenue from tablets, in thousands of dollars, is modeled by the expression 25(3x4)\frac{2}{5}(3x - 4), where xx represents the average number of tablets sold per day. The weekly operating costs, in thousands of dollars, are modeled by the expression 13(2x12)\frac{1}{3}\left(2x - \frac{1}{2}\right). The retailer's weekly profit is equal to the profit of a competitor, which is modeled by 14(x+5)116\frac{1}{4}(x + 5) - \frac{11}{6} thousand dollars. If the retailer and the competitor earn the same weekly profit, what is the value of 12x512x - 5?

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Cevap: 31

Cevap

31
The correct answer is 31. By equating the profit models, we get 25(3x4)13(2x0.5)=14(x+5)116\frac{2}{5}(3x - 4) - \frac{1}{3}(2x - 0.5) = \frac{1}{4}(x + 5) - \frac{11}{6}. Multiplying the entire equation by the least common multiple of the denominators (60) yields 24(3x4)20(2x0.5)=15(x+5)11024(3x - 4) - 20(2x - 0.5) = 15(x + 5) - 110. Expanding the terms gives 72x9640x+10=15x+7511072x - 96 - 40x + 10 = 15x + 75 - 110, which simplifies to 32x86=15x3532x - 86 = 15x - 35. Solving for xx gives 17x=5117x = 51, or x=3x = 3. Evaluating the required expression 12x512x - 5 for x=3x = 3 gives 12(3)5=3112(3) - 5 = 31.

Adım Adım Çözüm

1
Set up the equation equating the retailer's profit (revenue minus cost) to the competitor's profit.
25(3x4)13(2x12)=14(x+5)116\frac{2}{5}(3x - 4) - \frac{1}{3}\left(2x - \frac{1}{2}\right) = \frac{1}{4}(x + 5) - \frac{11}{6}
Profit is calculated as revenue minus operating costs. Since the retailer and the competitor earn the same profit, their profit models are equal.
2
Multiply the entire equation by 60 to eliminate all fractional denominators.
24(3x4)20(2x12)=15(x+5)10(11)24(3x - 4) - 20\left(2x - \frac{1}{2}\right) = 15(x + 5) - 10(11)
The least common multiple (LCM) of 5, 3, 4, and 6 is 60. Multiplying both sides by 60 simplifies the equation into integer terms.
3
Distribute the coefficients to remove parentheses, taking care with the negative signs.
72x9640x+10=15x+7511072x - 96 - 40x + 10 = 15x + 75 - 110
Distributing 20-20 across (2x12)\left(2x - \frac{1}{2}\right) yields 40x+10-40x + 10, and distributing 2424 across (3x4)(3x - 4) yields 72x9672x - 96.
4
Combine like terms on both sides of the equation.
32x86=15x3532x - 86 = 15x - 35
On the left side, 72x40x=32x72x - 40x = 32x and 96+10=86-96 + 10 = -86. On the right side, 75110=3575 - 110 = -35.
5
Isolate the variable term xx on one side and the constants on the other.
17x=51    x=317x = 51 \implies x = 3
Subtracting 15x15x from both sides gives 17x86=3517x - 86 = -35. Adding 8686 to both sides gives 17x=5117x = 51. Dividing by 17 yields x=3x = 3.
6
Substitute x=3x = 3 into the requested expression 12x512x - 5 to find the final value.
12(3)5=3112(3) - 5 = 31
The question asks for the value of the expression 12x512x - 5 rather than just the variable xx.

Anahtar Kavram

Solving multi-step linear equations containing fractions by clearing denominators and distributing terms correctly.
Soru 1858Soru

For all non-zero real numbers xx and yy, which of the following is equivalent to the expression (2x1y2+12x1y2)3(x2y3)2\frac{\left( 2x^{-1} y^2 + \frac{1}{2} x^{-1} y^2 \right)^{-3}}{(x^2 y^{-3})^{-2}}?

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Cevap: 8x7125y12\frac{8x^7}{125y^{12}}

Cevap

8x7125y12\frac{8x^7}{125y^{12}}
To find the equivalent expression, we first combine the like terms inside the parentheses in the numerator to get 52x1y2\frac{5}{2} x^{-1} y^2. Raising this product to the power of 3-3 yields (52)3(x1)3(y2)3=8125x3y6\left(\frac{5}{2}\right)^{-3} (x^{-1})^{-3} (y^2)^{-3} = \frac{8}{125} x^3 y^{-6}. Next, the denominator simplifies to (x2y3)2=x4y6(x^2 y^{-3})^{-2} = x^{-4} y^6. Dividing the numerator by the denominator requires subtracting the exponents of like bases: for xx, we have 3(4)=73 - (-4) = 7, and for yy, we have 66=12-6 - 6 = -12. This results in 8125x7y12\frac{8}{125} x^7 y^{-12}, which is equivalent to the correct expression 8x7125y12\frac{8x^7}{125y^{12}}.

Adım Adım Çözüm

1
Combine the like terms inside the parentheses in the numerator.
2x1y2+12x1y2=(2+12)x1y2=52x1y22x^{-1} y^2 + \frac{1}{2} x^{-1} y^2 = \left(2 + \frac{1}{2}\right) x^{-1} y^2 = \frac{5}{2} x^{-1} y^2
Before applying the outer negative exponent, it is mathematically simpler to combine the like terms inside the grouping.
2
Apply the power of 3-3 to the term in the numerator.
(52x1y2)3=(52)3(x1)3(y2)3=8125x3y6\left(\frac{5}{2} x^{-1} y^2\right)^{-3} = \left(\frac{5}{2}\right)^{-3} (x^{-1})^{-3} (y^2)^{-3} = \frac{8}{125} x^3 y^{-6}
The power of a product rule (ab)n=anbn(ab)^n = a^n b^n and the power of a power rule (am)n=amn(a^m)^n = a^{mn} are applied to expand the term.
3
Simplify the denominator by applying the power of 2-2.
(x2y3)2=(x2)2(y3)2=x4y6(x^2 y^{-3})^{-2} = (x^2)^{-2} (y^{-3})^{-2} = x^{-4} y^6
The power of a product rule is applied to the denominator to resolve the outer exponent.
4
Divide the simplified numerator by the simplified denominator using the quotient rule for exponents.
8125x3y6x4y6=8125x3(4)y66=8125x7y12=8x7125y12\frac{\frac{8}{125} x^3 y^{-6}}{x^{-4} y^6} = \frac{8}{125} x^{3 - (-4)} y^{-6 - 6} = \frac{8}{125} x^7 y^{-12} = \frac{8x^7}{125y^{12}}
The quotient rule am/an=amna^m / a^n = a^{m-n} is used to subtract the exponents of the corresponding variables, and negative exponents are rewritten in the denominator.

Anahtar Kavram

Properties of Exponents in Algebraic Expressions

Alternatif Yöntem

Alternatively, you can write out all variables with positive exponents before simplifying. Rewrite the term in the numerator as 2y2x+y22x=5y22x\frac{2y^2}{x} + \frac{y^2}{2x} = \frac{5y^2}{2x}. Raising this to the 3-3 power flips the fraction and cubes it, yielding (2x5y2)3=8x3125y6\left(\frac{2x}{5y^2}\right)^3 = \frac{8x^3}{125y^6}. Simplifying the denominator yields 1(x2y3)2=1x4y6=y6x4\frac{1}{(x^2 y^{-3})^2} = \frac{1}{x^4 y^{-6}} = \frac{y^6}{x^4}. Dividing the numerator by the denominator yields 8x3125y6÷y6x4=8x3125y6x4y6=8x7125y12\frac{8x^3}{125y^6} \div \frac{y^6}{x^4} = \frac{8x^3}{125y^6} \cdot \frac{x^4}{y^6} = \frac{8x^7}{125y^{12}}.
Tahmini Süre:2m 0s
Soru 1859Soru

A dog-walking service charges a flat fee of 1010 dollars per visit plus 2020 dollars for each dog walked. If a client was charged a total of 9090 dollars for a single visit, how many dogs were walked during that visit?

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Cevap: 4

Cevap

4
The correct answer is 44. The relation between the total cost and the number of dogs walked is 10+20d=9010 + 20d = 90. Subtracting 1010 from both sides yields 20d=8020d = 80, and dividing by 2020 yields d=4d = 4.

Adım Adım Çözüm

1
Set up the equation based on the scenario details.
Let dd be the number of dogs walked. The total cost is represented by the equation 10+20d=9010 + 20d = 90.
The total cost of 9090 dollars consists of a flat fee of 1010 dollars plus 2020 dollars per dog walked.
2
Subtract the flat fee from both sides of the equation.
20d=8020d = 80
Subtracting 1010 from both sides isolates the cost of walking the dogs.
3
Divide both sides by the per-dog rate to solve for dd.
d=4d = 4
Dividing by 2020 yields the number of dogs walked.

Anahtar Kavram

Translating verbal descriptions of multi-step scenarios into linear equations and solving them.
Soru 1860Soru

For all non-zero real numbers xx, the expression x4(x3)kx^4 \cdot (x^3)^k is equivalent to x10x^{10}. What is the value of the integer kk?

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Cevap: 2

Cevap

The correct answer is 2.
First, use the power of a power property to write (x3)k(x^3)^k as x3kx^{3k}. The expression then becomes x4x3kx^4 \cdot x^{3k}. Next, use the product of powers property to combine the terms into x4+3kx^{4+3k}. Since the expression is equivalent to x10x^{10}, set the exponents equal: 4+3k=104 + 3k = 10. Solving this equation gives 3k=63k = 6, which simplifies to k=2k = 2.

Adım Adım Çözüm

1
Apply the power of a power rule (xa)b=xab(x^a)^b = x^{ab} to simplify (x3)k(x^3)^k.
x3kx^{3k}
To raise a power to another power, multiply the exponents.
2
Apply the product of powers rule xaxb=xa+bx^a \cdot x^b = x^{a+b} to combine the terms x4x3kx^4 \cdot x^{3k}.
x4+3kx^{4+3k}
When multiplying exponential terms with the same base, add their exponents.
3
Set the combined exponent 4+3k4+3k equal to the target exponent 1010 and solve for kk.
k=2k = 2
Since the bases are equal and non-zero, their exponents must be equal.

Anahtar Kavram

Properties of exponents in algebraic expressions (power of a power rule and product of powers rule)
Tahmini Süre:45s
ÖncekiSayfa 93 / 278Sonraki
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