Tüm alıştırma soruları

5556 soru

Soru 1941Soru

Let the functions ff and gg be defined for all real numbers by f(x)=x26x+7f(x) = x^2 - 6x + 7 and g(x)=2x5g(x) = |2x - 5|. What is the sum of all real values of xx for which f(g(x))=14f(g(x)) = 14?

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Cevap: 5

Cevap

The sum of all possible real values of xx is 55.
The correct answer is 55. Setting f(g(x))=14f(g(x)) = 14 yields (g(x))26g(x)+7=14(g(x))^2 - 6g(x) + 7 = 14, which simplifies to (g(x))26g(x)7=0(g(x))^2 - 6g(x) - 7 = 0. Factoring this quadratic gives g(x)=7g(x) = 7 or g(x)=1g(x) = -1. Because g(x)=2x5g(x) = |2x - 5| cannot be negative, we discard the negative case. Solving 2x5=7|2x - 5| = 7 gives 2x5=7x=62x - 5 = 7 \Rightarrow x = 6 and 2x5=7x=12x - 5 = -7 \Rightarrow x = -1. The sum of these values is 6+(1)=56 + (-1) = 5.

Adım Adım Çözüm

1
Set up the composite equation f(g(x))=14f(g(x)) = 14 by substituting g(x)g(x) into f(x)f(x).
(g(x))26g(x)+7=14(g(x))^2 - 6g(x) + 7 = 14
This defines the relation between g(x)g(x) and the target output value.
2
Rearrange the equation into a standard quadratic form and solve for g(x)g(x).
(g(x))26g(x)7=0(g(x)7)(g(x)+1)=0(g(x))^2 - 6g(x) - 7 = 0 \Rightarrow (g(x) - 7)(g(x) + 1) = 0, so g(x)=7g(x) = 7 or g(x)=1g(x) = -1.
Factoring the quadratic equation gives the possible values for the inner function g(x)g(x).
3
Apply the definition of g(x)g(x) to solve for xx and discard invalid cases.
Since g(x)=2x5g(x) = |2x - 5| must be non-negative, the case g(x)=1g(x) = -1 has no real solutions. For the case g(x)=7g(x) = 7, we have 2x5=7|2x - 5| = 7.
The range of an absolute value function is [0,)[0, \infty), making negative outputs impossible.
4
Solve the absolute value equation 2x5=7|2x - 5| = 7 by setting up both positive and negative cases.
Either 2x5=72x=12x=62x - 5 = 7 \Rightarrow 2x = 12 \Rightarrow x = 6, or 2x5=72x=2x=12x - 5 = -7 \Rightarrow 2x = -2 \Rightarrow x = -1.
An absolute value equation u=c|u| = c splits into u=cu = c and u=cu = -c.
5
Sum the valid solutions for xx.
6+(1)=56 + (-1) = 5
The question asks for the sum of all real values of xx that satisfy the equation.

Anahtar Kavram

Solving equations involving composite functions and absolute values
Tahmini Süre:2m 0s
Soru 1942Soru

If a=27a = -27, b=14b = -\frac{1}{4}, and c=2c = -2, what is the value of the algebraic expression a4/3b2c5a^{-4/3} - b^{-2} \cdot c^{-5}?

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Cevap: 83162\frac{83}{162}

Cevap

The correct value of the algebraic expression is 83162\frac{83}{162}.
Evaluating each term of the expression with the given values yields: a4/3=181a^{-4/3} = \frac{1}{81}, b2=16b^{-2} = 16, and c5=132c^{-5} = -\frac{1}{32}. Applying the order of operations, we multiply 1616 by 132-\frac{1}{32} first to obtain 12-\frac{1}{2}. We then subtract this product from 181\frac{1}{81}, which simplifies to 181+12=83162\frac{1}{81} + \frac{1}{2} = \frac{83}{162}.

Adım Adım Çözüm

1
Substitute the given values of aa, bb, and cc into the algebraic expression.
The expression is written as (27)4/3(14)2(2)5(-27)^{-4/3} - (-\frac{1}{4})^{-2} \cdot (-2)^{-5}.
This establishes the numerical expression to be evaluated.
2
Evaluate the first term, (27)4/3(-27)^{-4/3}.
(27)4/3=1(27)4/3=1((27)1/3)4=1(3)4=181(-27)^{-4/3} = \frac{1}{(-27)^{4/3}} = \frac{1}{((-27)^{1/3})^4} = \frac{1}{(-3)^4} = \frac{1}{81}.
A negative exponent indicates a reciprocal, and a fractional exponent of 4/34/3 indicates taking the cube root and then raising to the fourth power.
3
Evaluate the second term, (14)2(-\frac{1}{4})^{-2}.
(14)2=(4)2=16(-\frac{1}{4})^{-2} = (-4)^2 = 16.
Raising a fraction to a negative integer power is equivalent to raising its reciprocal to the corresponding positive integer power.
4
Evaluate the third term, (2)5(-2)^{-5}.
(2)5=1(2)5=132(-2)^{-5} = \frac{1}{(-2)^5} = -\frac{1}{32}.
Evaluating a negative base raised to an odd negative power results in a negative unit fraction.
5
Substitute the evaluated terms back into the original expression and apply the order of operations.
E=18116(132)=181(1632)=181+12=2+81162=83162E = \frac{1}{81} - 16 \cdot \left(-\frac{1}{32}\right) = \frac{1}{81} - \left(-\frac{16}{32}\right) = \frac{1}{81} + \frac{1}{2} = \frac{2 + 81}{162} = \frac{83}{162}.
Multiplication must be performed before subtraction according to standard mathematical order of operations.

Anahtar Kavram

Evaluating expressions containing multiple variables with fractional exponents, negative bases, and standard order of operations.
Tahmini Süre:2m 0s
Soru 1943Soru

A rectangular photograph has a length of xx inches and a width that is 1.51.5 inches shorter than its length. If the area of the photograph is 1010 square inches, what is the length, in inches, of the photograph?

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Cevap: 4

Cevap

4
The correct length is 4. When the length is 4 inches, the width is 1.5 inches shorter, which is 2.5 inches. The area is the product of these dimensions: 4 * 2.5 = 10 square inches, which matches the given condition.

Adım Adım Çözüm

1
Set up the equation for the area of the photograph.
x(x1.5)=10x(x - 1.5) = 10
The area of a rectangle is found by multiplying its length (xx) by its width (x1.5x - 1.5).
2
Distribute the xx and subtract 1010 from both sides to write the equation in standard form.
x21.5x10=0x^2 - 1.5x - 10 = 0
Standard form for a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0.
3
Multiply the entire equation by 22 to clear the decimal coefficient.
2x23x20=02x^2 - 3x - 20 = 0
Working with integer coefficients makes factoring or applying the quadratic formula easier.
4
Factor the quadratic expression.
(2x+5)(x4)=0(2x + 5)(x - 4) = 0
Factoring helps find the roots of the equation directly.
5
Solve for xx by setting each factor to zero.
x=2.5x = -2.5 or x=4x = 4
If the product of two numbers is zero, at least one of the numbers must be zero.
6
Exclude the negative solution.
x=4x = 4
The length of a photograph must be a positive value.

Anahtar Kavram

Solving a quadratic equation by translating a word problem and factoring.
Soru 1944Soru

A large rectangle has a length of 4x+34x + 3 inches and a width of 3x23x - 2 inches. A smaller rectangular region is cut out from the center. The cut-out region has a length of 2x12x - 1 inches and a width of x5x - 5 inches. The area of the remaining region can be written as the polynomial Ax2+Bx+CAx^2 + Bx + C, where AA, BB, and CC are integers. What is the value of the coefficient BB?

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Cevap: 12

Cevap

The correct answer is 12, which is the coefficient of the linear term in the simplified remaining area polynomial.
The remaining area is found by subtracting the area of the smaller rectangle from the area of the larger rectangle. The area of the larger rectangle is (4x+3)(3x2)=12x2+x6(4x + 3)(3x - 2) = 12x^2 + x - 6. The area of the smaller rectangle is (2x1)(x5)=2x211x+5(2x - 1)(x - 5) = 2x^2 - 11x + 5. Subtracting the two yields (12x2+x6)(2x211x+5)=10x2+12x11(12x^2 + x - 6) - (2x^2 - 11x + 5) = 10x^2 + 12x - 11. Matching this to Ax2+Bx+CAx^2 + Bx + C, the coefficient BB of the linear term is 1212.

Adım Adım Çözüm

1
Find the area of the outer rectangle.
Area = 12x2+x612x^2 + x - 6
Multiply the length (4x+3)(4x + 3) and the width (3x2)(3x - 2) using the distributive property.
2
Find the area of the inner rectangle.
Area = 2x211x+52x^2 - 11x + 5
Multiply the length (2x1)(2x - 1) and the width (x5)(x - 5) using the distributive property.
3
Subtract the inner area from the outer area to find the remaining area.
Remaining Area = 10x2+12x1110x^2 + 12x - 11
Subtract the polynomial (2x211x+5)(2x^2 - 11x + 5) from (12x2+x6)(12x^2 + x - 6) by distributing the negative sign and combining like terms.
4
Identify the coefficient BB of the xx term.
B=12B = 12
Match the simplified polynomial 10x2+12x1110x^2 + 12x - 11 with the form Ax2+Bx+CAx^2 + Bx + C.

Anahtar Kavram

Operations on Polynomials (multiplication and subtraction of polynomials)
Soru 1945Soru

A sequence is defined by the formula an=2+32n2n16a_n = 2 + 3 \cdot \frac{2^n \cdot 2^{n-1}}{6} for all integers n1n \geq 1. What is the value of the second term, a2a_2?

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Cevap: 66

Cevap

The value of the second term is 6.
The correct answer is 6. When substituting n=2n = 2 into the formula, the numerator simplifies to 2221=82^2 \cdot 2^1 = 8. The fraction becomes 86=43\frac{8}{6} = \frac{4}{3}. Multiplying by 3 yields 4, and adding 2 yields 6.

Adım Adım Çözüm

1
Substitute n=2n = 2 into the sequence formula.
a2=2+3222216a_2 = 2 + 3 \cdot \frac{2^2 \cdot 2^{2-1}}{6}
To find the second term, we replace nn with 2 throughout the expression.
2
Simplify the exponents in the numerator.
22221=421=42=82^2 \cdot 2^{2-1} = 4 \cdot 2^1 = 4 \cdot 2 = 8
Evaluate the exponential terms in the numerator before performing other operations.
3
Substitute the simplified numerator back and evaluate the fraction.
86=43\frac{8}{6} = \frac{4}{3}
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, 2.
4
Multiply by 3 and add 2 to get the final answer.
2+343=2+4=62 + 3 \cdot \frac{4}{3} = 2 + 4 = 6
Perform multiplication before addition according to the order of operations.

Anahtar Kavram

Evaluating terms of a sequence given by an explicit formula involving exponent rules.
Tahmini Süre:1m 0s
Soru 1946Soru

A local bakery sells two types of muffins: blueberry and bran. Store 1 sells 30 blueberry muffins and 20 bran muffins. Store 2 sells 40 blueberry muffins and 35 bran muffins. Blueberry muffins cost 3each,andbranmuffinscost3 each, and bran muffins cost 2 each. This information is represented by the inventory matrix MM and the price matrix PP:

M=(30204035)M = \begin{pmatrix} 30 & 20 \\ 40 & 35 \end{pmatrix}
P=(32)P = \begin{pmatrix} 3 \\ 2 \end{pmatrix}

Which of the following matrices represents the total revenue from muffin sales for Store 1 and Store 2, calculated using the matrix product MPMP?

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Cevap: (130190)\begin{pmatrix} 130 \\ 190 \end{pmatrix}

Cevap

The column matrix with elements 130 and 190
The correct answer is the column matrix with elements 130 and 190. Multiplying the first row of the inventory matrix by the price column matrix yields the revenue for Store 1 (30×3+20×2=13030 \times 3 + 20 \times 2 = 130). Multiplying the second row by the price column matrix yields the revenue for Store 2 (40×3+35×2=19040 \times 3 + 35 \times 2 = 190). Since the product of a 2 by 2 matrix and a 2 by 1 matrix is a 2 by 1 column matrix, the final result is correctly formatted.

Adım Adım Çözüm

1
Set up the matrix multiplication of the 2 by 2 matrix and the 2 by 1 matrix.
MP=(30204035)(32)MP = \begin{pmatrix} 30 & 20 \\ 40 & 35 \end{pmatrix} \begin{pmatrix} 3 \\ 2 \end{pmatrix}
To calculate total revenue, we multiply the quantity matrix by the price matrix.
2
Calculate the first element of the resulting matrix (Store 1 total revenue) by taking the dot product of the first row of the inventory matrix and the price matrix.
30×3+20×2=90+40=13030 \times 3 + 20 \times 2 = 90 + 40 = 130
This pairs the quantity of each muffin type sold at Store 1 with its respective price.
3
Calculate the second element of the resulting matrix (Store 2 total revenue) by taking the dot product of the second row of the inventory matrix and the price matrix.
40×3+35×2=120+70=19040 \times 3 + 35 \times 2 = 120 + 70 = 190
This pairs the quantity of each muffin type sold at Store 2 with its respective price.
4
Assemble the resulting products into a 2 by 1 column matrix.
(130190)\begin{pmatrix} 130 \\ 190 \end{pmatrix}
The product of a 2 by 2 matrix and a 2 by 1 matrix is a 2 by 1 matrix.

Anahtar Kavram

Matrix multiplication of a 2 by 2 matrix and a 2 by 1 matrix in a real-world context.
Soru 1947Soru

For all real values of tt that satisfy the inequality 12432t812 - 4|3 - 2t| \leq -8, which of the following inequalities represents the complete set of possible values of tt?

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Cevap: t1t \leq -1 or t4t \geq 4

Cevap

t1t \leq -1 or t4t \geq 4
The correct answer is t1t \leq -1 or t4t \geq 4. To solve the inequality, we first subtract 12 from both sides to get 432t20-4|3 - 2t| \leq -20. Next, dividing both sides by 4-4 and reversing the inequality sign gives 32t5|3 - 2t| \geq 5. This absolute value inequality splits into two cases: 32t53 - 2t \geq 5 or 32t53 - 2t \leq -5. Solving the first case, we subtract 3 to get 2t2-2t \geq 2, and dividing by 2-2 while reversing the inequality sign yields t1t \leq -1. Solving the second case, we subtract 3 to get 2t8-2t \leq -8, and dividing by 2-2 while reversing the inequality sign yields t4t \geq 4. Combining these, we obtain the solution set t1t \leq -1 or t4t \geq 4.

Adım Adım Çözüm

1
Isolate the absolute value term by subtracting 12 from both sides of the inequality.
432t20-4|3 - 2t| \leq -20
Before splitting an absolute value inequality, the absolute value expression must be isolated on one side.
2
Divide both sides of the inequality by 4-4 and reverse the inequality sign.
32t5|3 - 2t| \geq 5
Dividing or multiplying an inequality by a negative number requires reversing the direction of the inequality sign.
3
Split the absolute value inequality uc|u| \geq c (where c>0c > 0) into two separate inequalities: ucu \geq c or ucu \leq -c.
32t53 - 2t \geq 5 or 32t53 - 2t \leq -5
An absolute value inequality of the form uc|u| \geq c represents values that are at least cc units away from zero, which lie in two disjoint intervals.
4
Solve the first inequality: 32t53 - 2t \geq 5.
2t2    t1-2t \geq 2 \implies t \leq -1
Subtracting 3 from both sides gives 2t2-2t \geq 2. Dividing by 2-2 and reversing the inequality sign yields t1t \leq -1.
5
Solve the second inequality: 32t53 - 2t \leq -5.
2t8    t4-2t \leq -8 \implies t \geq 4
Subtracting 3 from both sides gives 2t8-2t \leq -8. Dividing by 2-2 and reversing the inequality sign yields t4t \geq 4.
6
Combine the solutions from both cases to express the complete solution set.
t1t \leq -1 or t4t \geq 4
The complete solution set is the union of the solutions to both cases.

Anahtar Kavram

Solving absolute value inequalities of the form ax+bc|ax + b| \geq c by translating them into compound inequalities and carefully reversing the inequality sign when multiplying or dividing by negative numbers.
Soru 1948Soru

Match each of the unsimplified algebraic expressions on the left with its equivalent simplified form on the right. (Assume all variables represent real numbers.)

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

3r(2rs)2s(r3s)3r(2r - s) - 2s(r - 3s)
(2rs)22(r2rs)(2r - s)^2 - 2(r^2 - rs)
12(4r26rs)(rs)(2r+3s)\frac{1}{2}(4r^2 - 6rs) - (r - s)(2r + 3s)
r2(6s)s(r25s)r^2(6 - s) - s(r^2 - 5s)

Eşleşmeler

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Cevap

The correct matches pair the first expression with 6r25rs+6s26r^2 - 5rs + 6s^2, the second expression with 2r22rs+s22r^2 - 2rs + s^2, the third expression with 3s24rs3s^2 - 4rs, and the fourth expression with 6r22r2s+5s26r^2 - 2r^2s + 5s^2.
Each expression is correctly simplified by performing distribution first (carefully tracking negative signs and binomial expansion rules) and then combining terms that share the exact same variable powers.

Adım Adım Çözüm

1
Simplify the expression 3r(2rs)2s(r3s)3r(2r - s) - 2s(r - 3s).
6r25rs+6s26r^2 - 5rs + 6s^2
Distribute 3r3r to get 6r23rs6r^2 - 3rs. Then distribute 2s-2s to get 2rs+6s2-2rs + 6s^2 (noting that a negative times a negative is positive). Combine the like terms 3rs-3rs and 2rs-2rs to get 5rs-5rs.
2
Simplify the expression (2rs)22(r2rs)(2r - s)^2 - 2(r^2 - rs).
2r22rs+s22r^2 - 2rs + s^2
Square the binomial (2rs)2(2r - s)^2 using the formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 to get 4r24rs+s24r^2 - 4rs + s^2. Distribute 2-2 to get 2r2+2rs-2r^2 + 2rs. Combine 4r22r24r^2 - 2r^2 to get 2r22r^2, and 4rs+2rs-4rs + 2rs to get 2rs-2rs.
3
Simplify the expression 12(4r26rs)(rs)(2r+3s)\frac{1}{2}(4r^2 - 6rs) - (r - s)(2r + 3s).
3s24rs3s^2 - 4rs
Distribute 12\frac{1}{2} to get 2r23rs2r^2 - 3rs. Expand the binomial product to get 2r2+3rs2rs3s2=2r2+rs3s22r^2 + 3rs - 2rs - 3s^2 = 2r^2 + rs - 3s^2. Subtract this entire expression: (2r23rs)(2r2+rs3s2)=2r23rs2r2rs+3s2(2r^2 - 3rs) - (2r^2 + rs - 3s^2) = 2r^2 - 3rs - 2r^2 - rs + 3s^2. Combine like terms to get 4rs+3s2-4rs + 3s^2.
4
Simplify the expression r2(6s)s(r25s)r^2(6 - s) - s(r^2 - 5s).
6r22r2s+5s26r^2 - 2r^2s + 5s^2
Distribute r2r^2 to get 6r2r2s6r^2 - r^2s. Distribute s-s to get sr2+5s2-sr^2 + 5s^2. Combine the like terms r2s-r^2s and sr2-sr^2 (since multiplication is commutative) to get 2r2s-2r^2s.

Anahtar Kavram

Simplifying expressions by applying the distributive property, expanding products of binomials, and combining like terms.
Soru 1949Soru

Which of the following represents the completely factored form of the expression 4x416x24x^4 - 16x^2?

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Cevap: 4x2(x2)(x+2)4x^2(x - 2)(x + 2)

Cevap

The completely factored form of the expression is 4x2(x2)(x+2)4x^2(x - 2)(x + 2).
The correct answer is found by first identifying the greatest common factor of the terms in the polynomial 4x416x24x^4 - 16x^2, which is 4x24x^2. Factoring this out results in 4x2(x24)4x^2(x^2 - 4). Next, the binomial x24x^2 - 4 is recognized as a difference of squares and is factored into (x2)(x+2)(x - 2)(x + 2). Putting these together gives the completely factored form 4x2(x2)(x+2)4x^2(x - 2)(x + 2).

Adım Adım Çözüm

1
Identify and factor out the greatest common factor (GCF) of the terms in the expression 4x416x24x^4 - 16x^2.
The GCF of 4x44x^4 and 16x216x^2 is 4x24x^2. Factoring it out yields 4x2(x24)4x^2(x^2 - 4).
Factoring out the greatest common factor simplifies the polynomial and reveals remaining factorable patterns.
2
Factor the remaining binomial expression inside the parentheses, x24x^2 - 4.
Since x24x^2 - 4 is a difference of squares (x222x^2 - 2^2), it factors into (x2)(x+2)(x - 2)(x + 2).
A difference of squares of the form a2b2a^2 - b^2 always factors into (ab)(a+b)(a - b)(a + b).
3
Combine the factored parts to write the completely factored expression.
4x2(x2)(x+2)4x^2(x - 2)(x + 2)
This combines the GCF and the factored difference of squares to represent the original expression in its simplest factored parts.

Anahtar Kavram

Factoring a polynomial completely by first extracting the greatest common factor (GCF) and then applying the difference of squares formula.
Tahmini Süre:1m 0s
Soru 1950Soru

If (x4)2=4x+28(x - 4)^2 = -4x + 28, what is the sum of the solutions to the equation?

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Cevap: 4

Cevap

The sum of the solutions to the equation is 44.
The correct answer of 44 is found by first expanding (x4)2(x - 4)^2 to obtain x28x+16=4x+28x^2 - 8x + 16 = -4x + 28. Setting the equation to zero gives the quadratic equation x24x12=0x^2 - 4x - 12 = 0. Factoring the trinomial yields (x6)(x+2)=0(x - 6)(x + 2) = 0, which results in the solutions x=6x = 6 and x=2x = -2. Adding these solutions together gives 6+(2)=46 + (-2) = 4.

Adım Adım Çözüm

1
Expand the squared binomial on the left side of the equation.
x28x+16=4x+28x^2 - 8x + 16 = -4x + 28
Applying the binomial expansion formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 to (x4)2(x - 4)^2 yields x28x+16x^2 - 8x + 16.
2
Rearrange the equation into standard quadratic form by adding 4x4x and subtracting 2828 from both sides.
x24x12=0x^2 - 4x - 12 = 0
To solve a quadratic equation by factoring, all terms must be moved to one side so that the equation is set to zero.
3
Factor the quadratic expression x24x12x^2 - 4x - 12.
(x6)(x+2)=0(x - 6)(x + 2) = 0
Find two integers that multiply to the constant term 12-12 and add to the linear coefficient 4-4. These numbers are 6-6 and 22.
4
Set each binomial factor to zero and solve for xx.
x=6x = 6 or x=2x = -2
By the zero-product property, if the product of two factors is zero, at least one of the factors must be zero.
5
Find the sum of the solutions.
6+(2)=46 + (-2) = 4
Adding the two individual solutions gives the requested sum.

Anahtar Kavram

Solving quadratic equations by expanding binomials, rearranging terms into standard form, factoring the trinomial, and applying the zero-product property.

Alternatif Yöntem

Once the equation is rewritten in the standard form x24x12=0x^2 - 4x - 12 = 0, Vieta's formulas can be used to find the sum of the solutions directly. For any quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is given by ba-\frac{b}{a}. Substituting a=1a = 1 and b=4b = -4 into the formula gives 41=4-\frac{-4}{1} = 4.
Tahmini Süre:1m 0s
Soru 1951Soru

The first term of an arithmetic sequence is 88, and the second term is 55. What is the 66 th term of this sequence?

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Cevap: -7

Cevap

-7
The correct answer is 7-7. Since the sequence is arithmetic, it changes by a constant common difference, dd, with each step. Calculating dd gives 58=35 - 8 = -3. To find the 66 th term, we start at the first term, 88, and add the common difference 55 times (representing the steps from the first to the sixth term): 8+5(3)=815=78 + 5(-3) = 8 - 15 = -7.

Adım Adım Çözüm

1
Determine the common difference, dd, of the arithmetic sequence.
d=3d = -3
Subtract the first term from the second term: 58=35 - 8 = -3.
2
Set up the equation for the nn th term of an arithmetic sequence, an=a1+(n1)da_n = a_1 + (n-1)d.
a6=8+(61)(3)a_6 = 8 + (6-1)(-3)
We want to find the 6th term (n=6n = 6) starting with a1=8a_1 = 8 and d=3d = -3.
3
Perform the operations to find the final value.
a6=7a_6 = -7
First multiply 5×(3)=155 \times (-3) = -15, then add to 88 to get 815=78 - 15 = -7.

Anahtar Kavram

Finding a specific term of an arithmetic sequence using its first term and common difference.
Tahmini Süre:45s
Soru 1952Soru

A landscaping company charges a flat equipment fee plus a fixed hourly rate for lawn maintenance. For a job that took 44 hours, the company charged a total of $190\$190. For a different job that took 77 hours, the company charged a total of $295\$295. The company also offers a package that includes a 15%15\% discount on the hourly rate, but the flat equipment fee remains the same. Under this discounted package, what is the total charge, in dollars, for a job that takes 88 hours?

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Cevap: 288

Cevap

The total charge for an 88-hour job under the discounted package is 288288 dollars.
By translating the problem into the equations F+4H=190F + 4H = 190 and F+7H=295F + 7H = 295, we find that the hourly rate HH is 3535 dollars and the flat fee FF is 5050 dollars. Applying a 15%15\% discount to the hourly rate yields a new rate of 29.7529.75 dollars per hour. The total cost for 88 hours is then 50+8(29.75)=28850 + 8(29.75) = 288 dollars.

Adım Adım Çözüm

1
Define variables for the flat fee and hourly rate, and translate the given information into a system of linear equations.
F+4H=190F + 4H = 190 and F+7H=295F + 7H = 295, where FF is the flat fee and HH is the hourly rate.
To represent the cost structure algebraically.
2
Solve the system of equations by elimination or substitution.
H=35H = 35 and F=50F = 50.
To determine the individual cost components (flat fee and hourly rate).
3
Apply the 15%15\% discount to the hourly rate.
Hdiscounted=35×(10.15)=29.75H_{\text{discounted}} = 35 \times (1 - 0.15) = 29.75.
To find the new hourly rate under the discounted package.
4
Calculate the total cost for 88 hours of work with the flat fee and the discounted hourly rate.
Total Cost=50+8(29.75)=288\text{Total Cost} = 50 + 8(29.75) = 288.
To answer the question asking for the total charge of an 88-hour job under the discounted package.

Anahtar Kavram

Translating verbal statements into a system of linear equations and solving them to evaluate a modified expression.
Soru 1953Soru

If aa and bb represent positive real numbers, which of the following is an equivalent form of the expression below?

(a1+b1)2ab\frac{(a^{-1} + b^{-1})^{-2}}{ab}
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Cevap: ab(a+b)2\frac{ab}{(a+b)^2}

Cevap

The correct answer is the fraction with abab in the numerator and the square of the sum (a+b)(a+b) in the denominator, which is \frac{ab}{(a+b)^2}.
The correct answer is found by first rewriting a1+b1a^{-1} + b^{-1} as 1a+1b\frac{1}{a} + \frac{1}{b}, which simplifies to a+bab\frac{a+b}{ab} using a common denominator. Raising this to the power of 2-2 gives a2b2(a+b)2\frac{a^2 b^2}{(a+b)^2}. Finally, dividing this expression by abab reduces the exponents of aa and bb by 1, resulting in ab(a+b)2\frac{ab}{(a+b)^2}.

Adım Adım Çözüm

1
Rewrite the negative exponents in the numerator as reciprocals.
The expression inside the parentheses becomes 1a+1b\frac{1}{a} + \frac{1}{b}.
By the definition of negative exponents, x1=1xx^{-1} = \frac{1}{x}.
2
Find a common denominator to add the fractions inside the parentheses.
1a+1b=bab+aab=a+bab\frac{1}{a} + \frac{1}{b} = \frac{b}{ab} + \frac{a}{ab} = \frac{a+b}{ab}.
To add fractions, they must share a common denominator, which is the product of aa and bb.
3
Apply the negative power of 2-2 to the simplified fraction.
(a+bab)2=(aba+b)2=a2b2(a+b)2\left(\frac{a+b}{ab}\right)^{-2} = \left(\frac{ab}{a+b}\right)^2 = \frac{a^2 b^2}{(a+b)^2}.
An expression raised to a negative exponent is equal to the reciprocal of the expression raised to the positive exponent.
4
Divide the result by the denominator abab.
a2b2(a+b)21ab=ab(a+b)2\frac{a^2 b^2}{(a+b)^2} \cdot \frac{1}{ab} = \frac{ab}{(a+b)^2}.
Dividing by a term is equivalent to multiplying by its reciprocal, and applying the exponent quotient rule simplifies a2b2ab\frac{a^2 b^2}{ab} to abab.

Anahtar Kavram

Properties of exponents including negative power rules, quotient rules, and algebraic fraction addition.

Alternatif Yöntem

An alternative method is to substitute small positive integer values for aa and bb. Let a=1a = 1 and b=2b = 2. The expression evaluates to (11+21)212=(1+0.5)22=1.522=(3/2)22=4/92=29\frac{(1^{-1} + 2^{-1})^{-2}}{1 \cdot 2} = \frac{(1 + 0.5)^{-2}}{2} = \frac{1.5^{-2}}{2} = \frac{(3/2)^{-2}}{2} = \frac{4/9}{2} = \frac{2}{9}. Evaluating the correct expression with these values yields 12(1+2)2=29\frac{1 \cdot 2}{(1+2)^2} = \frac{2}{9}, which matches.
Tahmini Süre:2m 0s
Soru 1954Soru

What is the real solution to the equation 3x+1=x3\sqrt{3x + 1} = x - 3?

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Cevap: 8

Cevap

The only real solution is 8.
The correct answer is the single value 8. Squaring both sides of the equation 3x+1=x3\sqrt{3x+1} = x-3 leads to the quadratic equation x29x+8=0x^2-9x+8=0, which factors as (x8)(x1)=0(x-8)(x-1)=0. This yields potential solutions of 8 and 1. Checking 8 in the original equation gives 25=5\sqrt{25} = 5, which is correct. Checking 1 in the original equation gives 4=2\sqrt{4} = -2, which is incorrect because the principal square root must be non-negative. Therefore, 1 is an extraneous solution, and 8 is the only valid solution.

Adım Adım Çözüm

1
Square both sides of the equation to eliminate the radical.
3x+1=(x3)23x + 1 = (x - 3)^2
To clear the square root and obtain a polynomial equation.
2
Expand the right side and move all terms to the right side to set the quadratic equation to zero.
x29x+8=0x^2 - 9x + 8 = 0
Expanding (x3)2(x - 3)^2 gives x26x+9x^2 - 6x + 9. Subtracting 3x3x and 11 from both sides gives the standard form of the quadratic equation.
3
Factor the quadratic equation.
(x8)(x1)=0(x - 8)(x - 1) = 0
Finding two numbers that multiply to 8 and add to -9, which are -8 and -1, allows us to find potential solutions x=8x = 8 and x=1x = 1.
4
Check both potential solutions in the original equation to identify extraneous solutions.
Checking x=8x = 8: 3(8)+1=25=5\sqrt{3(8) + 1} = \sqrt{25} = 5 and 83=58 - 3 = 5 (True). Checking x=1x = 1: 3(1)+1=4=2\sqrt{3(1) + 1} = \sqrt{4} = 2 and 13=21 - 3 = -2 (False).
Squaring both sides of an equation can introduce extraneous solutions that do not satisfy the original equation.

Anahtar Kavram

Solving radical equations and identifying extraneous solutions
Tahmini Süre:1m 30s
Soru 1955Soru

The first three terms of a geometric sequence of positive numbers are xx, yy, and zz, in that order. An arithmetic sequence has first three terms xx, yy, and z4z - 4, in that order. If x=4x = 4, what is the value of yy?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

8
The correct answer is 8. By defining the geometric sequence terms as 4,y,z4, y, z, we have the property y2=4zy^2 = 4z. For the arithmetic sequence 4,y,z44, y, z-4, the common difference property gives y4=z4yy - 4 = z - 4 - y, which simplifies to 2y=z2y = z. Substituting z=2yz = 2y into the first equation yields y2=8yy^2 = 8y. Since all terms must be positive, dividing by yy gives y=8y = 8.

Adım Adım Çözüm

1
Set up the equation for the geometric sequence.
y2=4zy^2 = 4z
Since 4,y,z4, y, z is a geometric sequence, the ratio of consecutive terms must be equal: y4=zy\frac{y}{4} = \frac{z}{y}, which simplifies to y2=4zy^2 = 4z.
2
Set up the equation for the arithmetic sequence.
2y=z2y = z
Since 4,y,z44, y, z - 4 is an arithmetic sequence, the difference between consecutive terms must be equal: y4=(z4)yy - 4 = (z - 4) - y. Simplifying this gives 2y=z2y = z.
3
Substitute the arithmetic equation into the geometric equation.
y2=8yy^2 = 8y
Substituting z=2yz = 2y into y2=4zy^2 = 4z yields y2=4(2y)=8yy^2 = 4(2y) = 8y.
4
Solve for the variable yy.
y=8y = 8
Rearranging the equation gives y28y=0y^2 - 8y = 0, which factors as y(y8)=0y(y - 8) = 0. Since the sequence consists of positive numbers, yy must be positive, so y=8y = 8.

Anahtar Kavram

Relating arithmetic and geometric sequence properties to solve a system of non-linear equations
Soru 1956Soru

A square has a side length of x33x^3 - 3 inches. Which of the following expressions represents the area, in square inches, of the square?

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Cevap: x66x3+9x^6 - 6x^3 + 9

Cevap

The expression x66x3+9x^6 - 6x^3 + 9
To find the area of a square, square its side length: (x33)2(x^3 - 3)^2. Expanding this gives (x3)22(3)(x3)+(3)2=x66x3+9(x^3)^2 - 2(3)(x^3) + (-3)^2 = x^6 - 6x^3 + 9.

Adım Adım Çözüm

1
Write the formula for the area of a square.
A=s2A = s^2, where ss is the side length.
The area of a square is the side length squared.
2
Substitute the given side length s=x33s = x^3 - 3 into the area formula.
A=(x33)2A = (x^3 - 3)^2
We replace ss with the algebraic expression for the side length.
3
Expand the squared binomial (x33)2(x^3 - 3)^2 using the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
(x3)22(x3)(3)+32=x66x3+9(x^3)^2 - 2(x^3)(3) + 3^2 = x^6 - 6x^3 + 9
Expanding the binomial yields the correct simplified polynomial in standard descending order.

Anahtar Kavram

Expanding a squared binomial and applying exponent rules for powers of powers.
Tahmini Süre:1m 0s
Soru 1957Soru

The weight of Box A is 1.51.5 pounds more than 23\frac{2}{3} of the weight of Box B. If the weight of Box A is 13.513.5 pounds, what is the weight of Box B, in pounds?

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Cevap: 18

Cevap

The weight of Box B is 18 pounds.
The weight of 18 pounds is correct. Translating the word problem yields the linear equation A=23B+1.5A = \frac{2}{3}B + 1.5. Substituting the weight of Box A (13.513.5) gives 13.5=23B+1.513.5 = \frac{2}{3}B + 1.5. Subtracting 1.51.5 from both sides results in 12=23B12 = \frac{2}{3}B. Multiplying both sides by the reciprocal 32\frac{3}{2} isolates BB, giving B=12×32=18B = 12 \times \frac{3}{2} = 18.

Adım Adım Çözüm

1
Translate the verbal description into an algebraic equation.
Let AA represent the weight of Box A and BB represent the weight of Box B. The description translates to the equation: A=23B+1.5A = \frac{2}{3}B + 1.5.
This establishes the mathematical relationship between the weights of the two boxes.
2
Substitute the given value for Box A into the equation and isolate the term containing the variable B.
13.5=23B+1.5    12=23B13.5 = \frac{2}{3}B + 1.5 \implies 12 = \frac{2}{3}B.
Substituting 13.513.5 for AA and subtracting 1.51.5 from both sides simplifies the equation to isolate the fraction term.
3
Solve for B by multiplying both sides of the equation by the reciprocal of the coefficient.
B=12×32=18B = 12 \times \frac{3}{2} = 18.
Multiplying by the reciprocal 32\frac{3}{2} isolates BB to find its value.

Anahtar Kavram

Translating real-world descriptions into multi-step linear equations and solving them using inverse operations.
Tahmini Süre:1m 0s
Soru 1958Soru

A digital marketing firm allocates a total monthly advertising budget of BB dollars between search engine ads and social media ads. The amount allocated to social media ads is $800\$800 less than twice the amount allocated to search engine ads. The firm then increases its total monthly budget by 20%20\% and allocates this entire increase to search engine ads. As a result, the new amount allocated to search engine ads is equal to the amount originally allocated to social media ads. What was the firm's original total monthly advertising budget, BB?

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Cevap: $4,000\$4,000

Cevap

The original total monthly advertising budget was $4,000\$4,000.
By defining the original search engine advertising budget as SS, the original social media advertising budget as M=2S800M = 2S - 800, and the original total budget as B=3S800B = 3S - 800, we can set up the equation S+0.20B=MS + 0.20B = M using the condition that the new search engine budget equals the original social media budget. Solving this equation yields S=1600S = 1600. Substituting S=1600S = 1600 into the expression for the total budget gives B=3(1600)800=4000B = 3(1600) - 800 = 4000 dollars.

Adım Adım Çözüm

1
Define the variables representing each budget allocation.
Let SS represent the original amount allocated to search engine ads, and let MM represent the original amount allocated to social media ads. The original total budget is B=S+MB = S + M.
Establishing clear variables is necessary to translate the verbal relationships into equations.
2
Translate the relationship between the two advertising categories into an equation.
M=2S800M = 2S - 800
The problem states that the social media ads budget is $800\$800 less than twice the search engine ads budget.
3
Express the original total budget BB in terms of a single variable, SS.
B=S+(2S800)=3S800B = S + (2S - 800) = 3S - 800
Substituting the expression for MM into the total budget equation simplifies the system to a single variable.
4
Set up the equation for the new budget allocation after the 20%20\% increase.
S+0.20B=MS + 0.20B = M
An increase of 20%20\% of the total budget is 0.20B0.20B, which is added entirely to the search engine ads budget, making it equal to the original social media ads budget.
5
Substitute the expressions for BB and MM in terms of SS into the new budget equation.
S+0.20(3S800)=2S800S + 0.20(3S - 800) = 2S - 800
Substituting the relationships found in steps 2 and 3 allows us to solve for SS directly.
6
Solve the equation for SS.
S+0.60S160=2S8001.60S160=2S800640=0.40SS=1,600S + 0.60S - 160 = 2S - 800 \Rightarrow 1.60S - 160 = 2S - 800 \Rightarrow 640 = 0.40S \Rightarrow S = 1,600
Distributing, combining like terms, and isolating the variable yields the original search engine ads allocation.
7
Calculate the original total budget, BB.
B=3(1,600)800=4,800800=4,000B = 3(1,600) - 800 = 4,800 - 800 = 4,000
The question asks for the original total budget BB, so we must evaluate the expression for BB using the value of SS.

Anahtar Kavram

Translating verbal descriptions of algebraic relationships into systems of linear equations and solving them.
Soru 1959Soru

When the expression (5x28x+2)(2x24x9)(5x^2 - 8x + 2) - (2x^2 - 4x - 9) is written in the standard form ax2+bx+cax^2 + bx + c, where aa, bb, and cc are integers, what is the value of bb?

Cevabı ve açıklamayı göster

Cevap: -4

Cevap

The correct answer is 4-4, which is the coefficient of the xx term after simplifying the expression.
To subtract polynomials, we distribute the negative sign to all terms of the polynomial being subtracted and then combine like terms. Simplifying (5x28x+2)(2x24x9)(5x^2 - 8x + 2) - (2x^2 - 4x - 9) gives 5x28x+22x2+4x+9=3x24x+115x^2 - 8x + 2 - 2x^2 + 4x + 9 = 3x^2 - 4x + 11. Comparing this to ax2+bx+cax^2 + bx + c shows that bb, the coefficient of the xx term, is 4-4.

Adım Adım Çözüm

1
Distribute the subtraction sign to all terms inside the second set of parentheses.
2x2+4x+9-2x^2 + 4x + 9
Subtracting a polynomial is equivalent to adding its opposite, which means changing the sign of every term in that polynomial.
2
Group and combine like terms from both polynomials.
3x24x+113x^2 - 4x + 11
Like terms (terms with the same variable raised to the same power) can be combined by adding or subtracting their coefficients: (5x22x2)=3x2(5x^2 - 2x^2) = 3x^2, (8x+4x)=4x(-8x + 4x) = -4x, and (2+9)=11(2 + 9) = 11.
3
Compare the simplified expression to the standard form ax2+bx+cax^2 + bx + c to identify the value of bb.
b=4b = -4
In the standard form ax2+bx+cax^2 + bx + c, the coefficient of the xx term is represented by bb. In the simplified expression 3x24x+113x^2 - 4x + 11, the coefficient of xx is 4-4.

Anahtar Kavram

Polynomial Subtraction and Combining Like Terms
Soru 1960Soru

If ii represents the imaginary unit, and the complex number zz satisfies the equation z(2+i)5i97=2534iz(2 + i) - 5i^{97} = \frac{25}{3 - 4i}, what is the value of z2z^2?

Cevabı ve açıklamayı göster

Cevap: 18i

Cevap

18i
Simplifying the original equation yields the complex number z=3+3iz = 3 + 3i. Squaring this number gives (3+3i)2=9+18i+9i2=9+18i9=18i(3 + 3i)^2 = 9 + 18i + 9i^2 = 9 + 18i - 9 = 18i.

Adım Adım Çözüm

1
Simplify the fraction on the right side of the equation by multiplying the numerator and denominator by the complex conjugate of the denominator, 3+4i3 + 4i.
The fraction simplifies to 3+4i3 + 4i.
Multiplying by the conjugate rationalizes the denominator: 2534i=25(3+4i)(34i)(3+4i)=25(3+4i)9+16=3+4i\frac{25}{3 - 4i} = \frac{25(3 + 4i)}{(3 - 4i)(3 + 4i)} = \frac{25(3 + 4i)}{9 + 16} = 3 + 4i.
2
Simplify the power of the imaginary unit, i97i^{97}, by dividing the exponent by 4 to find the remainder.
5i97=5i5i^{97} = 5i
Since 97=4×24+197 = 4 \times 24 + 1, the expression simplifies as i97=(i4)24i=124i=ii^{97} = (i^4)^{24} \cdot i = 1^{24} \cdot i = i.
3
Substitute the simplified expressions back into the original equation and isolate the term containing zz.
z(2+i)=3+9iz(2 + i) = 3 + 9i
Substituting gives z(2+i)5i=3+4iz(2 + i) - 5i = 3 + 4i. Adding 5i5i to both sides yields z(2+i)=3+9iz(2 + i) = 3 + 9i.
4
Solve for zz by dividing both sides by 2+i2 + i, then simplify by multiplying by the conjugate of the denominator, 2i2 - i.
z=3+3iz = 3 + 3i
Performing the division: z=3+9i2+i=(3+9i)(2i)(2+i)(2i)=63i+18i9i24i2=15+15i5=3+3iz = \frac{3 + 9i}{2 + i} = \frac{(3 + 9i)(2 - i)}{(2 + i)(2 - i)} = \frac{6 - 3i + 18i - 9i^2}{4 - i^2} = \frac{15 + 15i}{5} = 3 + 3i.
5
Calculate the value of z2z^2 by squaring the complex number 3+3i3 + 3i.
z2=18iz^2 = 18i
Squaring the binomial gives (3+3i)2=9+18i+9i2=9+18i9=18i(3 + 3i)^2 = 9 + 18i + 9i^2 = 9 + 18i - 9 = 18i.

Anahtar Kavram

Solving equations containing complex numbers by performing operations such as multiplication, division using complex conjugates, and simplifying powers of ii.
Tahmini Süre:2m 30s
ÖncekiSayfa 98 / 278Sonraki
Tüm alıştırma soruları — ACT | Examkin