Solving Linear Inequalities

30 soru

Soru 21Soru →

A laboratory chamber's initial temperature is 72\frac{7}{2} degrees Celsius, and it decreases at a constant rate of 54\frac{5}{4} degrees Celsius per hour. The temperature of the chamber must reach at most −12-\frac{1}{2} degrees Celsius to complete an experiment. Which of the following inequalities represents the number of hours, hh, the experiment must run to reach this temperature?

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Cevap: h≥165h \geq \frac{16}{5}

Cevap

h≥165h \geq \frac{16}{5}
The correct answer is the inequality stating that hh must be greater than or equal to sixteen-fifths. This is found by setting up the linear inequality 72−54h≤−12\frac{7}{2} - \frac{5}{4}h \leq -\frac{1}{2}, subtracting 72\frac{7}{2} from both sides to get −54h≤−4-\frac{5}{4}h \leq -4, and then multiplying by −45-\frac{4}{5} while reversing the inequality sign.

Adım Adım Çözüm

1
Set up the inequality representing the temperature constraint.
72−54h≤−12\frac{7}{2} - \frac{5}{4}h \leq -\frac{1}{2}
The initial temperature is 72\frac{7}{2}, the rate of decrease is 54\frac{5}{4} per hour hh, and the final temperature must be at most −12-\frac{1}{2}.
2
Subtract 72\frac{7}{2} from both sides of the inequality.
−54h≤−4-\frac{5}{4}h \leq -4
This isolates the variable term on the left side of the inequality. The subtraction is −12−72=−82=−4-\frac{1}{2} - \frac{7}{2} = -\frac{8}{2} = -4.
3
Multiply both sides by −45-\frac{4}{5} and reverse the inequality sign.
h≥165h \geq \frac{16}{5}
Multiplying or dividing by a negative number requires reversing the direction of the inequality sign. The calculation is −4×(−45)=165-4 \times \left(-\frac{4}{5}\right) = \frac{16}{5}.

Anahtar Kavram

Solving linear inequalities involving negative coefficients and applying the inequality sign-flip rule.
Tahmini Süre:1m 30s
Soru 22Soru →

For all real values of xx that satisfy the inequality 5−3x−24≥x+625 - \frac{3x - 2}{4} \ge \frac{x + 6}{2}, the solution set is represented by x≤bx \le b. What is the value of bb?

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Cevap: 2

Cevap

The value of bb is 2.
To solve 5−3x−24≥x+625 - \frac{3x - 2}{4} \ge \frac{x + 6}{2}, multiply all terms by 4 to clear the denominators, resulting in 20−(3x−2)≥2(x+6)20 - (3x - 2) \ge 2(x + 6). Carefully distribute the negative sign to obtain 20−3x+2≥2x+1220 - 3x + 2 \ge 2x + 12. Simplifying the left side gives 22−3x≥2x+1222 - 3x \ge 2x + 12. Moving the variable terms to one side yields 10≥5x10 \ge 5x, which simplifies to x≤2x \le 2. Thus, the upper bound value bb is 2.

Adım Adım Çözüm

1
Multiply both sides of the inequality by the least common denominator, which is 4.
20−(3x−2)≥2(x+6)20 - (3x - 2) \ge 2(x + 6)
Multiplying all terms by the common denominator eliminates fractions and simplifies the inequality.
2
Distribute the negative sign to the numerator terms on the left and distribute the 2 on the right.
20−3x+2≥2x+1220 - 3x + 2 \ge 2x + 12
Distributing the negative sign across (3x−2)(3x - 2) changes it to −3x+2-3x + 2. Distributing 2 across (x+6)(x + 6) yields 2x+122x + 12.
3
Combine like terms on the left side of the inequality.
22−3x≥2x+1222 - 3x \ge 2x + 12
Combining the constant terms 2020 and 22 simplifies the expression to 2222.
4
Isolate the variable terms by adding 3x3x and subtracting 12 from both sides.
10≥5x10 \ge 5x
Grouping variables on one side and constants on the other allows us to solve for xx.
5
Divide both sides by 5.
2≥x2 \ge x (or x≤2x \le 2)
Dividing by a positive number isolates the variable without changing the direction of the inequality sign.

Anahtar Kavram

Solving linear inequalities involving fractions and distributing negative coefficients.

Alternatif Yöntem

We can write the inequality by separating each fraction term first: 5−34x+24≥12x+625 - \frac{3}{4}x + \frac{2}{4} \ge \frac{1}{2}x + \frac{6}{2}. This simplifies to 5.5−0.75x≥0.5x+35.5 - 0.75x \ge 0.5x + 3. Subtracting 0.5x0.5x and 5.55.5 from both sides gives −1.25x≥−2.5-1.25x \ge -2.5. Dividing by −1.25-1.25 and reversing the inequality sign gives x≤2x \le 2.
Tahmini Süre:1m 30s
Soru 23Soru →

A chemical solution in a laboratory has an initial volume of 5050 milliliters and evaporates at a rate of 72\frac{7}{2} milliliters per hour. A second chemical solution has an initial volume of 2020 milliliters and evaporates at a rate of 54\frac{5}{4} milliliters per hour. After how many hours, tt, will the volume of the first solution be at most the volume of the second solution?

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Cevap: t≥403t \ge \frac{40}{3}

Cevap

The correct solution is the set of values t≥403t \ge \frac{40}{3}.
Translating the problem statement gives the inequality 50−72t≤20−54t50 - \frac{7}{2}t \le 20 - \frac{5}{4}t. Subtracting 50 from both sides and adding 54t\frac{5}{4}t to both sides results in −94t≤−30-\frac{9}{4}t \le -30. Multiplying both sides by −49-\frac{4}{9} and reversing the inequality sign because of the negative multiplier yields the correct solution, t≥403t \ge \frac{40}{3}.

Adım Adım Çözüm

1
Write the inequality representing the physical situation.
50−72t≤20−54t50 - \frac{7}{2}t \le 20 - \frac{5}{4}t
The volume of the first solution after tt hours is 50−72t50 - \frac{7}{2}t, and the volume of the second solution is 20−54t20 - \frac{5}{4}t. The phrase 'at most' means the first volume must be less than or equal to the second volume.
2
Isolate the variable terms on the left side and the constant terms on the right side.
−72t+54t≤20−50-\frac{7}{2}t + \frac{5}{4}t \le 20 - 50
Grouping like terms makes it possible to simplify both sides of the inequality.
3
Find a common denominator of 4 to combine the fractions on the left side, and simplify the constant terms on the right side.
−94t≤−30-\frac{9}{4}t \le -30
Converting −72t-\frac{7}{2}t to −144t-\frac{14}{4}t allows us to add it to 54t\frac{5}{4}t, resulting in −94t-\frac{9}{4}t.
4
Multiply both sides of the inequality by −49-\frac{4}{9} to solve for tt, reversing the inequality sign because we are multiplying by a negative number.
t≥403t \ge \frac{40}{3}
Multiplying by the reciprocal of the coefficient isolates tt. The inequality sign must be reversed (≤{\le} to ≥{\ge}) because we are multiplying by a negative value.

Anahtar Kavram

Solving Linear Inequalities
Tahmini Süre:1m 30s
Soru 24Soru →

What is the maximum value of xx that satisfies the inequality 2−5x3≥2x+8\frac{2 - 5x}{3} \ge 2x + 8?

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Cevap: -2

Cevap

-2
Solving the inequality by isolating xx leads to x≤−2x \le -2, meaning that any value of xx less than or equal to −2-2 satisfies the inequality. Therefore, the maximum possible value is −2-2.

Adım Adım Çözüm

1
Multiply both sides of the inequality by 3 to clear the denominator.
2−5x≥6x+242 - 5x \ge 6x + 24
Multiplying by a positive number eliminates the fraction without changing the inequality direction.
2
Subtract 6x6x from both sides of the inequality.
2−11x≥242 - 11x \ge 24
This gathers the variable terms on the left side of the inequality.
3
Subtract 2 from both sides of the inequality.
−11x≥22-11x \ge 22
This isolates the variable term on the left side.
4
Divide both sides by −11-11 and reverse the inequality sign.
x≤−2x \le -2
Dividing by a negative number requires reversing the direction of the inequality sign. The resulting inequality defines the upper bound for xx.

Anahtar Kavram

Solving linear inequalities and applying the sign-flip rule when multiplying or dividing by a negative number.
Soru 25Soru →

For all real values of xx, which of the following inequalities represents the complete solution set to 7−3(x−4)≥5x+317 - 3(x - 4) \ge 5x + 31?

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Cevap: x≤−32x \le -\frac{3}{2}

Cevap

The inequality that represents the complete solution set is x≤−32x \le -\frac{3}{2}
The correct answer is the inequality stating that xx is less than or equal to negative three-halves. Simplifying the expression yields −8x≥12-8x \ge 12, and dividing by −8-8 correctly reverses the inequality direction to produce x≤−32x \le -\frac{3}{2}.

Adım Adım Çözüm

1
Distribute −3-3 to both terms inside the parentheses on the left side of the inequality.
7−3x+12≥5x+317 - 3x + 12 \ge 5x + 31
To eliminate the parentheses and prepare the inequality for simplification.
2
Combine the constant terms 77 and 1212 on the left side.
19−3x≥5x+3119 - 3x \ge 5x + 31
To group like terms on the left side.
3
Subtract 5x5x from both sides of the inequality to collect variable terms on one side.
19−8x≥3119 - 8x \ge 31
To isolate the variable term on the left side.
4
Subtract 1919 from both sides of the inequality.
−8x≥12-8x \ge 12
To isolate the variable term completely before division.
5
Divide both sides of the inequality by −8-8 and flip the inequality sign.
x≤−128x \le -\frac{12}{8}, which simplifies to x≤−32x \le -\frac{3}{2}
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality sign.

Anahtar Kavram

Solving multi-step linear inequalities, specifically reversing the inequality sign when multiplying or dividing by a negative number.
Soru 26Soru →

For all real values of nn that satisfy the inequality 3−2n4<3n−225\frac{3 - 2n}{4} < \frac{3n - 22}{5}, what is the smallest possible integer value of nn?

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Cevap: 5

Cevap

The smallest integer value of nn that satisfies the inequality is 5.
Solving the inequality yields n>10322≈4.68n > \frac{103}{22} \approx 4.68. The smallest integer greater than 4.684.68 is 55.

Adım Adım Çözüm

1
Multiply both sides by 20 to clear the denominators.
5(3−2n)<4(3n−22)5(3 - 2n) < 4(3n - 22)
To eliminate the fractions and simplify the inequality.
2
Distribute the constants on both sides.
15−10n<12n−8815 - 10n < 12n - 88
To remove the parentheses.
3
Subtract 12n12n from both sides.
15−22n<−8815 - 22n < -88
To group the terms containing the variable on the left side.
4
Subtract 15 from both sides.
−22n<−103-22n < -103
To isolate the variable term on the left side.
5
Divide both sides by −22-22 and reverse the inequality sign.
n>10322n > \frac{103}{22}
Dividing by a negative number reverses the direction of the inequality sign.
6
Convert the fraction to a decimal to identify the boundary.
n>4.68n > 4.68
To find the smallest integer value that satisfies this condition.
7
Identify the smallest integer greater than 4.684.68.
55
The smallest integer greater than 4.684.68 is 55.

Anahtar Kavram

Solving linear inequalities by applying inverse operations and reversing the inequality sign when multiplying or dividing by a negative number.
Tahmini Süre:1m 30s
Soru 27Soru →

Which of the following inequalities represents the complete solution set for xx in the inequality x3−2x−52≥2\frac{x}{3} - \frac{2x - 5}{2} \ge 2?

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Cevap: x≤34x \le \frac{3}{4}

Cevap

The inequality is satisfied by all values of xx less than or equal to 34\frac{3}{4}.
The correct solution is obtained by rewriting the fractions with a common denominator of 6, which yields 2x−3(2x−5)6≥2\frac{2x - 3(2x - 5)}{6} \ge 2. Distributing the negative sign gives −4x+156≥2\frac{-4x + 15}{6} \ge 2. Multiplying both sides by 6 and subtracting 15 results in −4x≥−3-4x \ge -3. Dividing by −4-4 and reversing the inequality sign yields x≤34x \le \frac{3}{4}.

Adım Adım Çözüm

1
Find a common denominator of 6 for the two fractions on the left side of the inequality.
2x6−3(2x−5)6≥2\frac{2x}{6} - \frac{3(2x - 5)}{6} \ge 2
Finding a common denominator is necessary to combine fractional terms with different denominators.
2
Combine the fractions into a single expression, distributing the subtraction sign to both terms in the numerator of the second fraction.
2x−(6x−15)6≥2  ⟹  −4x+156≥2\frac{2x - (6x - 15)}{6} \ge 2 \implies \frac{-4x + 15}{6} \ge 2
Combining the fractions simplifies the inequality. Distributing the negative sign ensures correct operations on the terms.
3
Multiply both sides of the inequality by 6.
−4x+15≥12-4x + 15 \ge 12
Multiplying by a positive number isolates the numerator without changing the direction of the inequality sign.
4
Subtract 15 from both sides of the inequality.
−4x≥−3-4x \ge -3
This isolates the variable term on the left side.
5
Divide both sides by −4-4 and reverse the direction of the inequality sign.
x≤34x \le \frac{3}{4}
Dividing both sides of an inequality by a negative number requires reversing the inequality sign to maintain the correct relationship.

Anahtar Kavram

Solving linear inequalities requires applying standard algebraic operations while remembering to reverse the inequality sign when multiplying or dividing both sides by a negative number.

Alternatif Yöntem

Instead of combining fractions first, multiply every term on both sides of the inequality by 6 (the least common multiple of the denominators) to eliminate the fractions immediately: 6⋅(x3)−6⋅(2x−52)≥6⋅26 \cdot \left(\frac{x}{3}\right) - 6 \cdot \left(\frac{2x - 5}{2}\right) \ge 6 \cdot 2. This simplifies directly to 2x−3(2x−5)≥122x - 3(2x - 5) \ge 12, which reduces to −4x+15≥12-4x + 15 \ge 12.
Tahmini Süre:1m 30s
Soru 28Soru →

A warehouse is cooling a refrigerated storage room. The initial temperature of the room is 22∘C22^\circ\text{C}. A cooling system lowers the temperature by 1.8∘C1.8^\circ\text{C} per hour. To store a specific vaccine, the temperature of the room must be kept strictly below −5∘C-5^\circ\text{C}. What is the minimum number of whole hours the cooling system must run to reach a safe storage temperature?

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Cevap: 16

Cevap

The minimum number of whole hours the cooling system must run is 16.
To find the minimum number of whole hours, we set up the inequality 22−1.8h<−522 - 1.8h < -5. Subtracting 22 from both sides yields −1.8h<−27-1.8h < -27. Dividing by the negative rate −1.8-1.8 requires reversing the inequality sign, which gives h>15h > 15. The smallest integer greater than 15 is 16.

Adım Adım Çözüm

1
Set up the inequality representing the temperature condition.
22−1.8h<−522 - 1.8h < -5
The initial temperature is 22∘C22^\circ\text{C}, and it decreases by 1.8∘C1.8^\circ\text{C} per hour hh. The temperature must be strictly below −5∘C-5^\circ\text{C}.
2
Isolate the variable term by subtracting 22 from both sides.
−1.8h<−27-1.8h < -27
Subtracting 22 simplifies the left side and groups the constant terms on the right side.
3
Divide both sides by -1.8 and reverse the inequality sign.
h>15h > 15
Dividing both sides of an inequality by a negative number reverses the direction of the inequality sign.
4
Determine the smallest integer value for h that satisfies the inequality.
16
Since the time must be strictly greater than 15 hours, the smallest whole number of hours that satisfies this is 16.

Anahtar Kavram

Solving linear inequalities by isolating the variable and reversing the inequality sign when dividing by a negative number.
Soru 29Soru →

What is the complete set of real values of xx that satisfy the inequality 34−2x3>2\frac{3}{4} - \frac{2x}{3} > 2?

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Cevap: x<−158x < -\frac{15}{8}

Cevap

x<−158x < -\frac{15}{8}
Subtracting 34\frac{3}{4} from both sides of the inequality gives −2x3>54-\frac{2x}{3} > \frac{5}{4}. Multiplying both sides by −32-\frac{3}{2} and reversing the inequality sign from greater than (>>) to less than (<<) yields x<−158x < -\frac{15}{8}.

Adım Adım Çözüm

1
Subtract 34\frac{3}{4} from both sides of the inequality.
−2x3>54-\frac{2x}{3} > \frac{5}{4}
To isolate the term containing the variable xx on one side of the inequality.
2
Multiply both sides of the inequality by −32-\frac{3}{2} and reverse the inequality sign.
x<−158x < -\frac{15}{8}
Multiplying or dividing an inequality by a negative number requires reversing the direction of the inequality sign.

Anahtar Kavram

Solving linear inequalities by isolating the variable and applying the sign reversal rule when multiplying or dividing by a negative value.
Soru 30Soru →

What is the greatest integer value of xx that satisfies the inequality 7−5x3−4≥2(x+6)\frac{7 - 5x}{3} - 4 \ge 2(x + 6)?

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Cevap: -4

Cevap

The greatest integer value of xx that satisfies the inequality is −4-4.
To find the greatest integer value of xx that satisfies the inequality, solve the inequality algebraically. First, clear the fraction by multiplying all terms by 3: 7−5x−12≥6(x+6)7 - 5x - 12 \ge 6(x + 6). Simplify the left side to −5x−5-5x - 5 and distribute the right side to get 6x+366x + 36. Move variables to the left side by subtracting 6x6x to get −11x−5≥36-11x - 5 \ge 36. Add 5 to both sides to get −11x≥41-11x \ge 41. Finally, divide by −11-11 and reverse the inequality sign, yielding x≤−4111x \le -\frac{41}{11}, which is approximately x≤−3.73x \le -3.73. The greatest integer less than or equal to −3.73-3.73 is −4-4.

Adım Adım Çözüm

1
Multiply the entire inequality by 3 to clear the fraction
7−5x−12≥6(x+6)7 - 5x - 12 \ge 6(x + 6)
Multiplying by the common denominator eliminates the fraction and simplifies further algebraic steps.
2
Simplify the left side and distribute the right side
−5x−5≥6x+36-5x - 5 \ge 6x + 36
Combines constant terms on the left side and expands the parentheses on the right side.
3
Subtract 6x6x from both sides
−11x−5≥36-11x - 5 \ge 36
Gathers all variable terms on the left side of the inequality.
4
Add 5 to both sides
−11x≥41-11x \ge 41
Isolates the variable term by moving the constant to the right side.
5
Divide by -11 and reverse the inequality sign
x≤−4111x \le -\frac{41}{11}
Isolates the variable xx. Reversing the inequality sign is required when multiplying or dividing both sides by a negative number.
6
Determine the greatest integer satisfying the inequality
x≤−3.73x \le -3.73, so the greatest integer is −4-4
Since −4111≈−3.73-\frac{41}{11} \approx -3.73, the largest integer that is less than or equal to this value is −4-4.

Anahtar Kavram

Solving linear inequalities, applying the sign-flip rule when dividing by a negative number, and identifying integer boundaries.
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Solving Linear Inequalities Alıştırma Soruları — ACT — Sayfa 2 | Examkin