Triangle Properties and Angle Theorems

46 soru

Soru 41Soru

A triangle has side lengths of xx, 2x2x, and 1515, where xx is an integer. What is the total number of possible values for xx?

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Cevap: 9

Cevap

9
Applying the Triangle Inequality Theorem yields three inequalities: x+2x>15x + 2x > 15 (which simplifies to x>5x > 5), x+15>2xx + 15 > 2x (which simplifies to x<15x < 15), and 2x+15>x2x + 15 > x (which is always true since xx is positive). Combining these results in 5<x<155 < x < 15. The integers in this range are {6,7,8,9,10,11,12,13,14}\{6, 7, 8, 9, 10, 11, 12, 13, 14\}. Counting them gives 9 possible values.

Adım Adım Çözüm

1
Set up the three inequalities using the Triangle Inequality Theorem for the sides xx, 2x2x, and 1515.
The inequalities are x+2x>15x + 2x > 15, x+15>2xx + 15 > 2x, and 2x+15>x2x + 15 > x.
The sum of the lengths of any two sides of a triangle must be strictly greater than the length of the third side.
2
Solve each inequality for xx.
3x>15    x>53x > 15 \implies x > 5, and 15>x    x<1515 > x \implies x < 15. The third inequality x>15x > -15 is always true for positive side lengths.
To find the range of valid values for xx.
3
Combine the inequalities and count the possible integer values for xx.
The combined range is 5<x<155 < x < 15. The integer values are {6,7,8,9,10,11,12,13,14}\{6, 7, 8, 9, 10, 11, 12, 13, 14\}, which gives 146+1=914 - 6 + 1 = 9 values.
Since xx is specified as an integer, we must identify and count all integers strictly between 5 and 15.

Anahtar Kavram

Triangle Inequality Theorem

Alternatif Yöntem

Instead of algebraic manipulation, we can test values of xx directly. For x=5x=5, the sides are 5,10,155, 10, 15, but 5+10=155+10=15, which does not form a triangle. For x=15x=15, the sides are 15,30,1515, 30, 15, but 15+15=3015+15=30, which also does not form a triangle. Testing integer values between 55 and 1515 confirms they all satisfy the triangle inequality, resulting in 9 valid integers.
Tahmini Süre:1m 0s
Soru 42Soru

In the figure, line L1L_1 is parallel to line L2L_2. Vertex AA of ABC\triangle ABC lies on L1L_1, and vertices BB and CC lie on L2L_2. Side ABAB is perpendicular to L2L_2. Point DD lies on L2L_2 such that CC is between BB and DD. If the measure of the exterior angle ACD\angle ACD is 132132^\circ, what is the measure, in degrees, of BAC\angle BAC?

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Cevap: 42

Cevap

42
The correct answer is 4242. Because ABAB is perpendicular to L2L_2, ABC\angle ABC is 9090^\circ. The exterior angle ACD\angle ACD is given as 132132^\circ, which means the adjacent interior angle ACB\angle ACB must be supplementary to it: 180132=48180^\circ - 132^\circ = 48^\circ. Since the interior angles of a triangle always sum to 180180^\circ, the remaining angle BAC\angle BAC is 180(90+48)=42180^\circ - (90^\circ + 48^\circ) = 42^\circ. Alternatively, applying the Exterior Angle Theorem, the exterior angle is equal to the sum of the two remote interior angles: ACD=ABC+BAC\angle ACD = \angle ABC + \angle BAC, so 132=90+BAC132^\circ = 90^\circ + \angle BAC, which simplifies to BAC=42\angle BAC = 42^\circ.

Adım Adım Çözüm

1
Determine the measure of interior angle ABC\angle ABC.
ABC=90\angle ABC = 90^\circ
Since side ABAB is perpendicular to L2L_2, the angle it makes with L2L_2 at vertex BB is 9090^\circ.
2
Find the measure of interior angle ACB\angle ACB.
ACB=48\angle ACB = 48^\circ
The interior angle ACB\angle ACB and the exterior angle ACD\angle ACD form a linear pair along line L2L_2, making them supplementary: ACB=180132=48\angle ACB = 180^\circ - 132^\circ = 48^\circ.
3
Calculate the measure of BAC\angle BAC using the angle sum of a triangle.
4242^\circ
The interior angles of ABC\triangle ABC sum to 180180^\circ. Subtracting the known angles gives BAC=180(90+48)=42\angle BAC = 180^\circ - (90^\circ + 48^\circ) = 42^\circ.

Anahtar Kavram

Triangle Angle Sum Theorem and Supplementary Angle Relationships
Soru 43Soru

In ABC\triangle ABC, the lengths of the sides are AB=8AB = 8, BC=11BC = 11, and AC=14AC = 14. Which of the following inequalities correctly compares the measures of the interior angles of ABC\triangle ABC?

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Cevap: mC<mA<mBm\angle C < m\angle A < m\angle B

Cevap

The correct inequality is mC<mA<mBm\angle C < m\angle A < m\angle B.
In any triangle, the order of the measures of the interior angles matches the order of the lengths of their opposite sides. Since the side lengths are ordered AB<BC<ACAB < BC < AC (8<11<148 < 11 < 14), their opposite angles must be ordered in the same way. The angle opposite side ABAB is C\angle C, the angle opposite side BCBC is A\angle A, and the angle opposite side ACAC is B\angle B. Therefore, the correct relationship is mC<mA<mBm\angle C < m\angle A < m\angle B.

Adım Adım Çözüm

1
Identify the theorem relating triangle side lengths to their opposite angles.
The Side-Angle Relationship Theorem states that in any triangle, the order of the measures of the angles is the same as the order of the lengths of the sides opposite to those angles.
This establishes the rule needed to compare the angle measures based on the given side lengths.
2
Determine the opposite angle for each side length in ABC\triangle ABC.
The angle opposite side ABAB is C\angle C. The angle opposite side BCBC is A\angle A. The angle opposite side ACAC is B\angle B.
This maps each side length to the correct angle it controls.
3
Order the side lengths and apply the mapping to order the angle measures.
Since 8<11<148 < 11 < 14, we write the side inequality as AB<BC<ACAB < BC < AC. Substituting the corresponding opposite angles gives mC<mA<mBm\angle C < m\angle A < m\angle B.
This yields the final correct inequality comparing the angle measures.

Anahtar Kavram

Triangle Side-Angle Relationship Theorem

Alternatif Yöntem

Another way to solve this is to sketch the triangle to scale. By drawing the longest side AC=14AC = 14 as the horizontal base, the shortest side AB=8AB = 8 on the left, and the side BC=11BC = 11 on the right, it becomes visually apparent that the angle opposite the longest side (B\angle B at the top vertex) is the largest angle, and the angle opposite the shortest side (C\angle C at the bottom-right vertex) is the smallest angle.
Tahmini Süre:1m 0s
Soru 44Soru

In ABC\triangle ABC, the measure of A\angle A is 4040^\circ. The measure of B\angle B is three times the measure of C\angle C. What is the measure, in degrees, of B\angle B?

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Cevap: 105

Cevap

The measure of angle B is 105 degrees.
The sum of the interior angles in any triangle is 180180^\circ. By setting the measure of C\angle C to xx and the measure of B\angle B to 3x3x, we can write the equation 40+3x+x=18040 + 3x + x = 180. Solving for xx yields 4x=1404x = 140, which simplifies to x=35x = 35. The measure of B\angle B is 3x3x, which is 3×35=1053 \times 35 = 105^\circ.

Adım Adım Çözüm

1
Set up the equation using the fact that the sum of angles in a triangle is 180 degrees.
mA+mB+mC=180m\angle A + m\angle B + m\angle C = 180^\circ
The angles of any triangle in plane geometry sum to 180 degrees.
2
Represent the unknown angles algebraically.
Let mC=xm\angle C = x, then mB=3xm\angle B = 3x. Substitute mA=40m\angle A = 40^\circ.
This allows solving for the unknown angles with a single-variable equation.
3
Solve the equation for xx.
40+4x=180    4x=140    x=3540 + 4x = 180 \implies 4x = 140 \implies x = 35
To find the measure of angle C.
4
Calculate the measure of angle B.
mB=3(35)=105m\angle B = 3(35) = 105^\circ
Angle B is three times angle C, and we need to find the measure of angle B.

Anahtar Kavram

The sum of the interior angles of a triangle is always 180 degrees.
Soru 45Soru

The measures of the three interior angles of a triangle are in the ratio 2:3:42:3:4. What is the measure, in degrees, of the smallest angle of the triangle?

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Cevap: 40

Cevap

40
The interior angles of any triangle sum to 180180^\circ. Given the ratio of the angles is 2:3:42:3:4, the total number of ratio parts is 2+3+4=92 + 3 + 4 = 9. Dividing the total degree sum by the number of parts gives 1809=20\frac{180^\circ}{9} = 20^\circ per part. Since the smallest angle corresponds to the smallest part of the ratio, we multiply 22 by 2020^\circ to get 4040^\circ.

Adım Adım Çözüm

1
Find the total number of parts in the ratio.
The total number of parts is 2+3+4=92 + 3 + 4 = 9.
This determines how the 180180^\circ total sum of a triangle's interior angles is partitioned.
2
Calculate the value of a single part of the ratio.
One part is equal to 1809=20\frac{180^\circ}{9} = 20^\circ.
The sum of the interior angles of any triangle is always 180180^\circ.
3
Find the measure of the smallest angle by multiplying by the smallest part of the ratio.
The smallest angle measures 2×20=402 \times 20^\circ = 40^\circ.
The smallest angle corresponds to the smallest number in the ratio, which is 2.

Anahtar Kavram

Ratio-based angle partitioning in triangles
Soru 46Soru

In ABC\triangle ABC, the measure of angle AA is 4040^\circ. Point DD lies on side ACAC such that segment BDBD bisects angle ABCABC. If the measure of angle BDCBDC is 7575^\circ, what is the measure, in degrees, of angle CC?

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Cevap: 70

Cevap

The measure of angle C is 70 degrees.
The correct measure of angle CC is found by first identifying that angle ADBADB is supplementary to angle BDCBDC, giving a measure of 105105^\circ. Using the triangle angle sum theorem on triangle ABDABD, we find that angle ABDABD is 3535^\circ. Since BDBD bisects angle ABCABC, angle DBCDBC is also 3535^\circ. Finally, applying the triangle angle sum theorem to triangle BCDBCD, we subtract the measures of angles DBCDBC (3535^\circ) and BDCBDC (7575^\circ) from 180180^\circ to get 7070^\circ.

Adım Adım Çözüm

1
Find the measure of angle ADBADB using the supplementary angle relationship with angle BDCBDC.
105105^\circ
Angles ADBADB and BDCBDC form a linear pair along the line segment ACAC, so their sum is 180180^\circ.
2
Find the measure of angle ABDABD using the sum of interior angles in ABD\triangle ABD.
3535^\circ
The sum of interior angles in any triangle is 180180^\circ. Therefore, the measure of angle ABDABD is 180(40+105)=35180^\circ - (40^\circ + 105^\circ) = 35^\circ.
3
Find the measure of angle DBCDBC using the definition of an angle bisector.
3535^\circ
Since segment BDBD bisects angle ABCABC, the measures of angles ABDABD and DBCDBC must be equal.
4
Find the measure of angle CC using the sum of interior angles in BCD\triangle BCD.
7070^\circ
The sum of interior angles in BCD\triangle BCD is 180180^\circ. Therefore, the measure of angle CC is 180(35+75)=70180^\circ - (35^\circ + 75^\circ) = 70^\circ.

Anahtar Kavram

Using the triangle angle sum theorem and angle bisector properties to determine unknown angle measures in a geometric figure.
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Triangle Properties and Angle Theorems Alıştırma Soruları — ACT — Sayfa 3 | Examkin