Pre-Algebra

419 soru

Soru 361Soru

An electric vehicle charging station delivers energy at a constant rate of kk kilowatt-hours (kWh) per hour. If a vehicle receives a total of 48 kWh48\text{ kWh} of energy after charging for 1.51.5 hours, which of the following equations can be solved to find kk?

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Cevap: 1.5k=481.5k = 48

Cevap

1.5k=481.5k = 48
Multiplying the charging rate of kk kWh per hour by the charging duration of 1.51.5 hours yields the total energy of 4848 kWh. Thus, 1.5k=481.5k = 48 correctly models the situation.

Adım Adım Çözüm

1
Identify the relationship between rate, time, and total amount.
Total energy = (charging rate) ×\times (time in hours)
The unit rate in kWh per hour multiplied by hours yields total kWh.
2
Substitute the given values into the relationship.
48=k×1.548 = k \times 1.5, or 1.5k=481.5k = 48
The total energy is 4848, the rate is kk, and time is 1.51.5 hours.

Anahtar Kavram

Formulating one-step multiplication equations from unit rate scenarios
Tahmini Süre:1m 0s
Soru 362Soru

At a community theater performance, the ratio of adult tickets sold to student tickets sold was 5:35 : 3. After 1212 additional student tickets were sold and no additional adult tickets were sold, the ratio of adult tickets to student tickets became 4:34 : 3. How many total tickets (adult and student combined) were sold originally?

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Cevap: 128

Cevap

128 total tickets were sold originally.
Let the original number of adult tickets be 5x5x and student tickets be 3x3x. After 12 student tickets are added, the new ratio is frac5x3x+12=frac43\\frac{5x}{3x + 12} = \\frac{4}{3}. Cross-multiplying gives 15x=12x+4815x = 12x + 48, which simplifies to 3x=483x = 48 and x=16x = 16. The original total number of tickets is 5x+3x=8x=8(16)=1285x + 3x = 8x = 8(16) = 128.

Adım Adım Çözüm

1
Define variables for the original quantities based on the initial ratio.
Let the original number of adult tickets be 5x5x and the original number of student tickets be 3x3x, where xx is a common multiplier. The original total is 5x+3x=8x5x + 3x = 8x.
Representing a ratio 5:35 : 3 with a multiplier allows algebraic manipulation when quantities change.
2
Set up an equation representing the new ratio after adding 12 student tickets.
frac5x3x+12=frac43\\frac{5x}{3x + 12} = \\frac{4}{3}
The number of adult tickets remains 5x5x, while student tickets increase by 12 to 3x+123x + 12.
3
Solve for the multiplier xx using cross-multiplication.
3(5x)=4(3x+12)implies15x=12x+48implies3x=48impliesx=163(5x) = 4(3x + 12) \\implies 15x = 12x + 48 \\implies 3x = 48 \\implies x = 16.
Equating cross-products isolates xx to find the value of one ratio unit.
4
Calculate the original total number of tickets.
textOriginalTotal=8x=8(16)=128\\text{Original Total} = 8x = 8(16) = 128.
Multiplying the common multiplier by 8 yields the combined original total.

Anahtar Kavram

Solving multi-step proportion problems involving changing part-to-part ratios.
Tahmini Süre:1m 15s
Soru 363Soru

A nursery technician prepares a liquid fertilizer mixture using nitrogen, phosphorus, and potassium in a volume ratio of 4:2:14 : 2 : 1, respectively. A storage tank currently holds 35 liters35\text{ liters} of this mixture. If the technician adds 6 liters6\text{ liters} of pure nitrogen to the tank, what is the ratio of nitrogen to phosphorus in the resulting mixture?

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Cevap: 13:513 : 5

Cevap

The ratio of nitrogen to phosphorus in the resulting mixture is 13:513 : 5.
The original 35 liters35\text{ liters} contains 77 equal parts of 5 liters5\text{ liters} each. Nitrogen represents 44 parts (20 liters20\text{ liters}) and phosphorus represents 22 parts (10 liters10\text{ liters}). Adding 6 liters6\text{ liters} of nitrogen brings the nitrogen amount to 26 liters26\text{ liters}. Comparing 26 liters26\text{ liters} of nitrogen to 10 liters10\text{ liters} of phosphorus yields the ratio 26:1026 : 10, which simplifies to 13:513 : 5.

Adım Adım Çözüm

1
Find the total number of parts in the original ratio.
4+2+1=7 total parts4 + 2 + 1 = 7\text{ total parts}.
To determine the volume of each component, calculate the total proportion of the mixture.
2
Calculate the initial volume of nitrogen and phosphorus in 35 liters35\text{ liters} of solution.
\text{Nitrogen} = \frac{4}{7} \times 35 = 20\text{ liters}; \quad \text{Phosphorus} = \frac{2}{7} \times 35 = 10\text{ liters}.
Multiply each component's fraction by the total volume of 35 liters35\text{ liters}.
3
Add 6 liters6\text{ liters} to the initial volume of nitrogen.
\text{New Nitrogen volume} = 20 + 6 = 26\text{ liters}.
Only nitrogen is added to the tank, while phosphorus remains unchanged at 10 liters10\text{ liters}.
4
Write and simplify the new ratio of nitrogen to phosphorus.
\frac{26}{10} = \frac{13}{5} \implies 13 : 5.
Divide both terms by their greatest common factor, 22.

Anahtar Kavram

Partitioning a total quantity into parts using extended ratios and adjusting part quantities.
Soru 364Soru

A technology firm allocated its annual equipment budget among three divisions. The engineering division received 38\frac{3}{8} of the total budget, and the operations division received 30%30\% of the total budget. The remaining $52,000\$52,000 was allocated to the design division. What was the total equipment budget, in dollars, for the technology firm?

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Cevap: 160000

Cevap

The total equipment budget for the technology firm was $160,000 dollars.
Converting both allocated parts into decimals gives 38=0.375\frac{3}{8} = 0.375 for engineering and 30%=0.3030\% = 0.30 for operations. Combined, these two divisions account for 0.375+0.30=0.6750.375 + 0.30 = 0.675 (or 67.5%67.5\%) of the total budget. The remaining fraction for the design division is 10.675=0.3251 - 0.675 = 0.325 (or 32.5%32.5\%). Dividing the design budget of $52,000\$52,000 by 0.3250.325 yields the total budget of $160,000\$160,000.

Adım Adım Çözüm

1
Convert the percentage and fraction to equivalent decimal values.
Engineering receives 38=0.375\frac{3}{8} = 0.375, and operations receives 30%=0.3030\% = 0.30.
Expressing all portions in decimal form allows for straightforward addition and subtraction.
2
Sum the portions allocated to the engineering and operations divisions.
0.375+0.30=0.6750.375 + 0.30 = 0.675.
This finds the total proportion of the budget that has already been accounted for.
3
Determine the remaining decimal portion allocated to the design division.
10.675=0.3251 - 0.675 = 0.325.
The complete budget represents 1 whole (100%). Subtracting the allocated portions yields the design division's share.
4
Divide the dollar amount of the design division by its decimal portion to calculate the total budget.
52,0000.325=160,000\frac{52,000}{0.325} = 160,000.
Since Design Portion×Total Budget=Design Amount\text{Design Portion} \times \text{Total Budget} = \text{Design Amount}, dividing the amount by the decimal portion gives the total budget.

Anahtar Kavram

Solving multi-step applied word problems by converting between fractions, decimals, and percentages to determine an unknown total value.
Soru 365Soru

A security system requires a 4-digit passcode created using the digits 1,2,3,4,5,6,1, 2, 3, 4, 5, 6, and 77. No digit may be repeated in a passcode. If the first digit and the last digit must both be odd numbers, how many different passcodes can be formed?

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Cevap: 240

Cevap

240 passcodes can be formed under the given conditions.
To form a 4-digit passcode with distinct digits where the first and last digits are odd: first choose the first digit from the 4 available odd digits (1,3,5,71, 3, 5, 7). Next, choose the fourth digit from the remaining 3 odd digits. Then, choose the second digit from the remaining 5 available digits in the full set, and the third digit from the remaining 4 available digits. Multiplying these choices gives 4×5×4×3=2404 \times 5 \times 4 \times 3 = 240.

Adım Adım Çözüm

1
Categorize available digits into odd and even sets
4 odd digits ({1, 3, 5, 7}) and 3 even digits ({2, 4, 6}) out of 7 total digits
The first and last positions require odd digits, so we need to track odd digits separately.
2
Determine options for the first and last positions
4 options for position 1; 3 options for position 4
Position 1 must be odd (4 choices). Because digits cannot repeat, position 4 has 3 remaining odd choices.
3
Determine options for the second and third positions
5 options for position 2; 4 options for position 3
Two digits have already been assigned. Out of 7 total digits, 5 remain for position 2, leaving 4 for position 3.
4
Multiply choices across all positions
4 * 5 * 4 * 3 = 240
By the Fundamental Counting Principle, the total number of combinations is the product of the number of choices at each step.

Anahtar Kavram

Fundamental Counting Principle with Position Restrictions and Non-Replacement
Soru 366Soru

An electric commuter train consumes energy at a constant rate of 450 kilowatt-hours (kWh)450\text{ kilowatt-hours (kWh)} for every 120 miles120\text{ miles} it travels. Electricity costs $0.14\$0.14 per kWh\text{kWh}. What is the total cost of the electricity consumed by the train during a 320 mile320\text{ mile} trip?

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Cevap: $168.00\$168.00

Cevap

The total cost of electricity consumed during the trip is $168.00\$168.00.
To solve this problem, first determine the energy consumed per mile by dividing 450 kWh450\text{ kWh} by 120 miles120\text{ miles}, which equals 3.75 kWh/mile3.75\text{ kWh/mile}. Next, multiply this unit rate by 320 miles320\text{ miles} to find the total energy required for the trip, which is 1,200 kWh1,200\text{ kWh}. Finally, multiply 1,200 kWh1,200\text{ kWh} by the cost of $0.14\$0.14 per kWh\text{kWh} to get the total cost of $168.00\$168.00.

Adım Adım Çözüm

1
Calculate the unit rate of energy consumption per mile
450 kWh120 miles=3.75 kWh per mile\frac{450\text{ kWh}}{120\text{ miles}} = 3.75\text{ kWh per mile}
Determining the energy consumption rate per mile allows us to calculate energy used for any distance.
2
Find the total energy consumed for 320320 miles
320 miles×3.75 kWh/mile=1,200 kWh320\text{ miles} \times 3.75\text{ kWh/mile} = 1,200\text{ kWh}
Multiply total distance by rate per mile to find total electricity required.
3
Calculate the total electricity cost
1,200 kWh×$0.14/kWh=$168.001,200\text{ kWh} \times \$0.14\text{/kWh} = \$168.00
Multiply total kilowatt-hours by the cost per kilowatt-hour.

Anahtar Kavram

Unit rates and multi-step proportional reasoning
Tahmini Süre:1m 30s
Soru 367Soru

At a university, three sections of an introductory chemistry course took the same midterm examination. Section 1 has 1515 students with a mean score of 8080 points, Section 2 has 2525 students with a mean score of 8888 points, and Section 3 has 1010 students with a mean score of 7474 points. What is the overall mean score for all 5050 students combined?

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Cevap: 82.882.8

Cevap

The overall mean score for all 5050 students combined is 82.882.8.
To find the combined mean score for all 5050 students, calculate the total points earned across all three sections and divide by the total number of students. Section 1 contributes 15×80=1,20015 \times 80 = 1,200 points, Section 2 contributes 25×88=2,20025 \times 88 = 2,200 points, and Section 3 contributes 10×74=74010 \times 74 = 740 points. Summing these yields 4,1404,140 total points. Dividing 4,1404,140 by the total student count of 5050 gives an overall mean of 82.882.8.

Adım Adım Çözüm

1
Calculate the total number of points earned by each section.
Section 1: 15×80=1,20015 \times 80 = 1,200 points. Section 2: 25×88=2,20025 \times 88 = 2,200 points. Section 3: 10×74=74010 \times 74 = 740 points.
The total points in a group equals the number of items multiplied by the mean of that group.
2
Sum the total points from all three sections to find the combined total points.
1,200+2,200+740=4,1401,200 + 2,200 + 740 = 4,140 total points.
To find the overall mean, we need the total score across all students.
3
Divide the total points by the total number of students.
4,14050=82.8\frac{4,140}{50} = 82.8.
The weighted mean is the total accumulated score divided by the total sample size (15+25+10=5015 + 25 + 10 = 50).

Anahtar Kavram

Weighted Mean
Tahmini Süre:1m 15s
Soru 368Soru

A botanical garden conservatory uses a specialized organic fertilizer mixture containing ff pounds of nutrient concentrate. The concentrate is divided equally into 1414 separate watering reservoirs. If each reservoir receives exactly 2.52.5 pounds of concentrate, which of the following equations correctly models this situation?

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Cevap: f14=2.5\frac{f}{14} = 2.5

Cevap

The equation f14=2.5\frac{f}{14} = 2.5 correctly models the situation.
Dividing the total amount of nutrient concentrate (ff) equally into 1414 reservoirs means dividing ff by 1414. Setting this equal to the amount per reservoir (2.52.5 pounds) yields f14=2.5\frac{f}{14} = 2.5.

Adım Adım Çözüm

1
Identify the total quantity and how it is shared or split.
The total amount of nutrient concentrate is ff pounds, divided equally into 1414 reservoirs.
Equal sharing or division of a total quantity ff into 1414 equal parts is expressed algebraically as f14\frac{f}{14}.
2
Equate the expression for one part to the given value per reservoir.
f14=2.5\frac{f}{14} = 2.5
Each reservoir gets 2.52.5 pounds, so the portion in one reservoir, f14\frac{f}{14}, must equal 2.52.5.

Anahtar Kavram

Translating verbal descriptions of equal division into one-step algebraic equations
Soru 369Soru

A long-distance runner is training for an upcoming race. On Monday, she completed 25\frac{2}{5} of her total weekly distance goal. On Tuesday, she completed 0.350.35 of her total weekly distance goal. If she has 1212 miles left to complete her weekly goal, what is her total weekly goal distance, in miles?

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Cevap: 48

Cevap

48 miles
Converting 25\frac{2}{5} to 0.400.40 gives a total completed portion of 0.40+0.35=0.750.40 + 0.35 = 0.75 of the goal. The remaining portion is 10.75=0.251 - 0.75 = 0.25 of the total goal. Setting 0.25×total goal=120.25 \times \text{total goal} = 12 miles gives a total weekly goal of 120.25=48\frac{12}{0.25} = 48 miles.

Adım Adım Çözüm

1
Convert the fraction completed on Monday to a decimal
25=0.40\frac{2}{5} = 0.40
Converting all completed portions to decimals allows for direct addition.
2
Calculate the total portion of the weekly goal completed on Monday and Tuesday
0.40+0.35=0.750.40 + 0.35 = 0.75
Summing Monday's and Tuesday's completed portions gives the total completed fraction of the goal.
3
Determine the remaining fraction of the weekly goal
10.75=0.251 - 0.75 = 0.25
Subtracting the completed portion from the total whole (1.00) yields the fraction remaining.
4
Set up an equation relating the remaining fraction to the remaining miles to find the total goal distance xx
0.25x=12    x=120.25=480.25x = 12 \implies x = \frac{12}{0.25} = 48
Dividing the remaining distance by the remaining fraction yields the total weekly goal distance.

Anahtar Kavram

Combining fractions and decimals to determine a total quantity from a remaining part
Tahmini Süre:1m 15s
Soru 370Soru

A craft workshop instructor purchases a large spool of decorative ribbon of length LL meters. She cuts the entire spool into 1515 equal-length pieces to make banners for an art project. If each piece measures 2.42.4 meters, which of the following equations can be solved to find the total length LL, in meters, of the spool of ribbon?

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Cevap: L15=2.4\frac{L}{15} = 2.4

Cevap

The equation that can be solved to find the total length LL is L15=2.4\frac{L}{15} = 2.4.
When a total quantity LL is divided equally into 1515 pieces, the length of each individual piece is found by dividing LL by 1515. Setting this quotient equal to the given single piece length of 2.42.4 meters yields L15=2.4\frac{L}{15} = 2.4.

Adım Adım Çözüm

1
Identify the relationship between total length, number of pieces, and length per piece.
Total Length ÷\div Number of Pieces == Length per Piece
Dividing a total quantity into equal parts corresponds to mathematical division.
2
Substitute the given values and variables into the relationship.
L15=2.4\frac{L}{15} = 2.4
The total length is represented by LL, the number of pieces is 1515, and each piece is 2.42.4 meters long.

Anahtar Kavram

Translating equal sharing or division word problems into one-step linear equations
Tahmini Süre:1m 0s
Soru 371Soru

An artisan bakery prepared a total batch of dough weighing 6060 pounds. In the morning, the baker used 25\frac{2}{5} of the total dough to make loaves of bread. In the afternoon, the baker used 35%35\% of the remaining dough to make pastries. How many pounds of dough from the initial batch were left unused at the end of the day?

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Cevap: 23.423.4

Cevap

The weight of the dough left unused at the end of the day is 23.423.4 pounds.
First, calculate the dough used in the morning: 25\frac{2}{5} of 6060 pounds is 2424 pounds. The remaining dough is 6024=3660 - 24 = 36 pounds. Next, 35%35\% of 3636 pounds is 0.35×36=12.60.35 \times 36 = 12.6 pounds used for pastries. Subtracting this from 3636 pounds gives 3612.6=23.436 - 12.6 = 23.4 pounds remaining unused.

Adım Adım Çözüm

1
Calculate the weight of dough used in the morning.
25×60=24\frac{2}{5} \times 60 = 24 pounds
The bakery used 25\frac{2}{5} of the total 6060-pound batch.
2
Find the dough remaining after the morning baking.
6024=3660 - 24 = 36 pounds
Subtract the amount used in the morning from the initial batch weight.
3
Calculate the percentage of dough remaining after the afternoon baking.
100%35%=65%100\% - 35\% = 65\% of the remaining dough
Since 35%35\% of the remaining dough was used for pastries, 65%65\% remained unused.
4
Calculate the final unused weight of dough.
0.65×36=23.40.65 \times 36 = 23.4 pounds
Multiply the remaining weight (3636 pounds) by the percentage left unused (65%65\%).

Anahtar Kavram

Multistep calculation involving fractional parts of a whole followed by percentage parts of a remainder.
Tahmini Süre:1m 30s
Soru 372Soru

A local wildlife sanctuary maintains a specialized feeding program for rehabilitated hawks. Each hawk receives pp pounds of meat mixture per week. If the sanctuary cares for 1818 hawks and uses a total of 4545 pounds of meat mixture per week, which of the following equations can be used to find pp?

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Cevap: 18p=4518p = 45

Cevap

18p=4518p = 45
The total amount of meat mixture used (4545 pounds) is equal to the number of hawks (1818) multiplied by the amount of meat mixture each hawk receives (pp pounds). Setting up this relationship gives the equation 18p=4518p = 45.

Adım Adım Çözüm

1
Identify the relationship between total quantity, number of groups, and quantity per group.
Total meat mixture = (Number of hawks) ×\times (Pounds per hawk)
Equal groups being combined call for multiplication.
2
Substitute the given values into the relationship.
45=18×p45 = 18 \times p, which simplifies to 18p=4518p = 45.
The total is 45 pounds, the number of hawks is 18, and the rate per hawk is pp.

Anahtar Kavram

Formulating one-step multiplication equations from real-world contexts
Tahmini Süre:1m 0s
Soru 373Soru

A high-speed digital camera records 480480 frames every 33 seconds. The camera operator increases the recording rate by 25%25\%. At this new recording rate, how many total frames will the camera record in 1414 seconds?

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Cevap: 2,8002,800

Cevap

The camera will record 2,800 frames in 14 seconds at the new recording rate.
To solve this problem, first determine the initial frame rate: 480480 frames divided by 33 seconds equals 160160 frames per second. Increasing this rate by 25%25\% produces 160×1.25=200160 \times 1.25 = 200 frames per second. Multiplying the new rate by 1414 seconds results in 200×14=2,800200 \times 14 = 2,800 frames.

Adım Adım Çözüm

1
Calculate the original unit rate in frames per second.
480 frames3 seconds=160 frames per second\frac{480 \text{ frames}}{3 \text{ seconds}} = 160 \text{ frames per second}
Dividing the number of frames by the elapsed time yields the frame rate per second.
2
Determine the new unit rate after a 25%25\% increase.
160×(1+0.25)=160×1.25=200 frames per second160 \times (1 + 0.25) = 160 \times 1.25 = 200 \text{ frames per second}
Increasing a value by 25%25\% is equivalent to multiplying the original value by 1.251.25.
3
Calculate total frames recorded in 1414 seconds at the new rate.
200 frames per second×14 seconds=2,800 frames200 \text{ frames per second} \times 14 \text{ seconds} = 2,800 \text{ frames}
Multiplying the new rate by the given duration yields the total frame count.

Anahtar Kavram

Unit rates and percentage adjustment in rates
Soru 374Soru

A bookstore received a shipment of 5050 new books. Among these books, 2424 are fiction, 2020 are hardcover, and 88 are hardcover fiction books. If 11 book is selected at random from the shipment, what is the probability that the selected book is either a fiction book or a hardcover book?

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Cevap: 1825\frac{18}{25}

Cevap

1825\frac{18}{25}
To find the probability that a randomly chosen book is either fiction or hardcover, calculate the total number of books satisfying at least one condition. By the Principle of Inclusion-Exclusion, the number of favorable books is 24+208=3624 + 20 - 8 = 36. Dividing this by the total of 5050 books yields 3650\frac{36}{50}, which simplifies to 1825\frac{18}{25}.

Adım Adım Çözüm

1
Identify the total number of items in the sample space and the counts for each event.
Total books N=50N = 50, Fiction N(F)=24N(F) = 24, Hardcover N(H)=20N(H) = 20, Both N(FH)=8N(F \cap H) = 8.
The sample space consists of all 50 shipment books.
2
Apply the Inclusion-Exclusion Principle to find the number of favorable outcomes.
N(FH)=N(F)+N(H)N(FH)=24+208=36N(F \cup H) = N(F) + N(H) - N(F \cap H) = 24 + 20 - 8 = 36.
Hardcover fiction books are counted in both individual totals, so their intersection must be subtracted once to avoid double-counting.
3
Calculate the probability and simplify the fraction.
P(FH)=3650=1825P(F \cup H) = \frac{36}{50} = \frac{18}{25}.
Probability is the ratio of favorable outcomes to total outcomes.

Anahtar Kavram

Probability of non-mutually exclusive events using the Addition Rule: P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B).
Tahmini Süre:1m 0s
Soru 375Soru

During a laboratory experiment, a liquid cooling solution's temperature dropped by a total of 14.4C14.4^\circ\text{C} over a duration of tt minutes. If the temperature decreased at a constant rate of 1.8C1.8^\circ\text{C} per minute, which of the following equations can be solved to find tt?

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Cevap: 1.8t=14.41.8t = 14.4

Cevap

The equation 1.8t=14.41.8t = 14.4 correctly models the situation.
Because the cooling rate is constant at 1.8C1.8^\circ\text{C} per minute, the total temperature change over tt minutes is found by multiplying the rate by time (1.8t1.8 \cdot t). Setting this equal to the total drop of 14.4C14.4^\circ\text{C} gives 1.8t=14.41.8t = 14.4.

Adım Adım Çözüm

1
Identify the given quantities and their relationship.
Rate of change = 1.8C/min1.8^\circ\text{C/min}, Time = tt minutes, Total change = 14.4C14.4^\circ\text{C}.
The total change in a constant rate scenario is the product of the rate and the time duration.
2
Set up the one-step algebraic equation.
Rate×Time=Total Change    1.8×t=14.4\text{Rate} \times \text{Time} = \text{Total Change} \implies 1.8 \times t = 14.4
Translating the verbal relationship into an algebraic equation yields 1.8t=14.41.8t = 14.4.

Anahtar Kavram

Translating constant rate scenarios into one-step linear multiplication equations
Tahmini Süre:1m 0s
Soru 376Soru

A commercial bakery makes a specialty flour blend using whole wheat flour, rye flour, and white flour in a ratio of 3:2:53 : 2 : 5 by weight, respectively. To prepare a batch for a large order, a baker uses 36 pounds36\text{ pounds} of whole wheat flour. If rye flour costs $1.50\$1.50 per pound and white flour costs $0.80\$0.80 per pound, what is the total cost of the rye flour and white flour needed for this batch?

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Cevap: $84.00\$84.00

Cevap

The total cost of the rye flour and white flour needed for this batch is $84.00\$84.00.
To find the cost, first determine the weight per ratio part. Whole wheat represents 33 parts out of 3:2:53 : 2 : 5, so 33 parts equal 36 pounds36\text{ pounds}, making 1 part=12 pounds1\text{ part} = 12\text{ pounds}. Thus, the batch requires 2×12=24 pounds2 \times 12 = 24\text{ pounds} of rye flour and 5×12=60 pounds5 \times 12 = 60\text{ pounds} of white flour. At $1.50\$1.50 per pound, the rye flour costs 24×$1.50=$36.0024 \times \$1.50 = \$36.00. At $0.80\$0.80 per pound, the white flour costs 60×$0.80=$48.0060 \times \$0.80 = \$48.00. Adding these together gives a total cost of $36.00+$48.00=$84.00\$36.00 + \$48.00 = \$84.00.

Adım Adım Çözüm

1
Determine the weight represented by one ratio part
Since whole wheat flour represents 33 parts of the ratio and equals 36 pounds36\text{ pounds}, 1 part=363=12 pounds1\text{ part} = \frac{36}{3} = 12\text{ pounds}.
Dividing the known quantity by its corresponding ratio weight finds the unit multiplier for the proportional relationship.
2
Calculate the weight of rye flour and white flour needed
Rye flour (22 parts) =2×12=24 pounds= 2 \times 12 = 24\text{ pounds}. White flour (55 parts) =5×12=60 pounds= 5 \times 12 = 60\text{ pounds}.
Multiply each component's ratio value by the single-part weight value.
3
Calculate the cost of each ingredient and sum them
Cost of rye flour =24×$1.50=$36.00= 24 \times \$1.50 = \$36.00. Cost of white flour =60×$0.80=$48.00= 60 \times \$0.80 = \$48.00. Total cost =$36.00+$48.00=$84.00= \$36.00 + \$48.00 = \$84.00.
Multiply the weight of each ingredient by its unit price and add the totals together.

Anahtar Kavram

Solving multi-part ratio problems by finding a common multiplier and using unit rates.
Tahmini Süre:1m 15s
Soru 377Soru

A nutritionist analyzed the proportion of daily recommended fiber provided by four different snack bars. The proportions were recorded as follows: Fruit Bar (58%58\%), Oat Bar (712\frac{7}{12}), Nut Bar (0.5850.585), and Seed Bar (35\frac{3}{5}). Arrange the four snack bars in order from the LEAST proportion of daily recommended fiber to the GREATEST proportion of daily recommended fiber.

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Cevap

Fruit Bar (58%58\%), Oat Bar (712\frac{7}{12}), Nut Bar (0.5850.585), Seed Bar (35\frac{3}{5})
To order the values from least to greatest, convert each representation into a standard decimal form: Fruit Bar = 58%=0.58058\% = 0.580, Oat Bar = 7120.5833\frac{7}{12} \approx 0.5833, Nut Bar = 0.58500.5850, and Seed Bar = 35=0.6000\frac{3}{5} = 0.6000. Arranging these decimals in increasing order yields 0.5800<0.5833<0.5850<0.60000.5800 < 0.5833 < 0.5850 < 0.6000, which corresponds to Fruit Bar, Oat Bar, Nut Bar, and Seed Bar.

Adım Adım Çözüm

1
Convert each numerical value into a common format (decimal representation) to allow direct comparison.
Fruit Bar: 58%=58100=0.58058\% = \frac{58}{100} = 0.580; Oat Bar: 712=7÷120.5833\frac{7}{12} = 7 \div 12 \approx 0.5833; Nut Bar: 0.5850.585; Seed Bar: 35=610=0.600\frac{3}{5} = \frac{6}{10} = 0.600.
Converting all numbers to decimals makes it straightforward to compare place values from left to right.
2
Compare the resulting decimal values up to the thousandths place: 0.58000.5800, 0.58330.5833, 0.58500.5850, and 0.60000.6000.
In order from smallest to largest decimal value: 0.5800<0.5833<0.5850<0.60000.5800 < 0.5833 < 0.5850 < 0.6000.
Comparing the hundredths and thousandths digits shows that 0.5800.580 is smallest, followed by 0.58330.5833, then 0.5850.585, and finally 0.6000.600.
3
Map the ordered decimals back to their original snack bar representations.
Fruit Bar (58%58\%) < Oat Bar (712\frac{7}{12}) < Nut Bar (0.5850.585) < Seed Bar (35\frac{3}{5}).
This establishes the exact required sequence from least to greatest fiber proportion.

Anahtar Kavram

Converting and Comparing Mixed Numerical Representations (Fractions, Decimals, and Percentages)
Tahmini Süre:1m 15s
Soru 378Soru

A box contains red, blue, and yellow game tokens. The probability of randomly selecting a red token is 38\frac{3}{8}, and the probability of randomly selecting a blue token is 13\frac{1}{3}. If the box contains exactly 1414 yellow tokens, how many total tokens are in the box?

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Cevap: 4848

Cevap

There are 48 total tokens in the box.
The total probability of all outcomes in the box must equal 11. Combining the given probabilities for red and blue tokens yields 38+13=924+824=1724\frac{3}{8} + \frac{1}{3} = \frac{9}{24} + \frac{8}{24} = \frac{17}{24}. The remaining probability representing the yellow tokens is 11724=7241 - \frac{17}{24} = \frac{7}{24}. Since the box contains 1414 yellow tokens, setting 724\frac{7}{24} of the total number of tokens equal to 1414 gives 724N=14\frac{7}{24} N = 14, which simplifies to N=48N = 48.

Adım Adım Çözüm

1
Find the probability of selecting a red or blue token.
38+13=924+824=1724\frac{3}{8} + \frac{1}{3} = \frac{9}{24} + \frac{8}{24} = \frac{17}{24}
Since selecting a red token and a blue token are mutually exclusive events, add their probabilities using a common denominator of 2424.
2
Calculate the probability of selecting a yellow token.
11724=7241 - \frac{17}{24} = \frac{7}{24}
The sum of the probabilities of all possible outcomes (red, blue, yellow) must equal 11.
3
Set up and solve the equation for the total number of tokens NN.
724N=14    N=14×247=2×24=48\frac{7}{24} N = 14 \implies N = 14 \times \frac{24}{7} = 2 \times 24 = 48
Multiply the count of yellow tokens (1414) by the reciprocal of the yellow token probability (247\frac{24}{7}).

Anahtar Kavram

Determining total sample size using complementary probabilities of mutually exclusive events
Tahmini Süre:1m 15s
Soru 379Soru

A high school planning committee needs to select a subcommittee of 33 people from a pool of 55 teachers and 44 students. How many different subcommittees can be formed consisting of exactly 22 teachers and 11 student?

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Cevap: 40

Cevap

The total number of different subcommittees that can be formed is 40.
To find the number of unique subcommittees with 2 teachers and 1 student, calculate the combination for choosing 2 teachers from 5, which equals 10, and 1 student from 4, which equals 4. Multiplying these independent choices together results in 40 possible subcommittees.

Adım Adım Çözüm

1
Calculate the number of ways to select 2 teachers from the pool of 5 teachers.
(52)=5×42×1=10\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10 ways
Selection order does not matter for committee members, so combinations are used.
2
Calculate the number of ways to select 1 student from the pool of 4 students.
(41)=4\binom{4}{1} = 4 ways
Choosing 1 item from a set of 4 offers 4 distinct possibilities.
3
Apply the Fundamental Counting Principle to determine total combinations.
10×4=4010 \times 4 = 40 subcommittees
Multiply the number of choices for teachers by the number of choices for students.

Anahtar Kavram

Combinations and Fundamental Counting Principle
Tahmini Süre:1m 0s
Soru 380Soru

An urban hydroponic farm uses a liquid nutrient mixture containing nitrogen, potassium, and calcium in a mass ratio of 3:5:83 : 5 : 8, respectively. A technician prepares a batch of solution where the amount of calcium exceeds the amount of nitrogen by exactly 15 grams15\text{ grams}. How many total grams of nutrient solution will be prepared?

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Cevap: 48 grams48\text{ grams}

Cevap

The total mass of the nutrient solution prepared is 48 grams48\text{ grams}.
The given ratio of nitrogen to potassium to calcium is 3:5:83 : 5 : 8. The difference between calcium and nitrogen in the ratio is 83=58 - 3 = 5 parts. Since calcium exceeds nitrogen by 15 grams15\text{ grams}, each ratio part corresponds to 15÷5=3 grams15 \div 5 = 3\text{ grams}. The total mixture consists of 3+5+8=163 + 5 + 8 = 16 parts, so the total mass is 16×3 grams=48 grams16 \times 3\text{ grams} = 48\text{ grams}.

Adım Adım Çözüm

1
Determine the difference in ratio parts between calcium and nitrogen
Calcium has 88 parts and nitrogen has 33 parts, so calcium exceeds nitrogen by 83=58 - 3 = 5 ratio parts.
The problem states that calcium exceeds nitrogen by 15 grams15\text{ grams}, which corresponds to the difference between their ratio values.
2
Calculate the mass represented by a single ratio part
15 grams5 parts=3 grams per part\frac{15\text{ grams}}{5\text{ parts}} = 3\text{ grams per part}.
Dividing the total difference in grams by the difference in ratio parts gives the value of one part.
3
Find the total number of ratio parts and compute the total mass
Total ratio parts = 3+5+8=163 + 5 + 8 = 16 parts. Total mass = 16 parts×3 grams per part=48 grams16 \text{ parts} \times 3\text{ grams per part} = 48\text{ grams}.
Multiplying the single part mass by the sum of all components yields the total mass of the solution.

Anahtar Kavram

Solving multi-part ratio problems by finding the value of one ratio unit using given part-to-part differences.
Tahmini Süre:1m 15s
ÖncekiSayfa 19 / 21Sonraki
Pre-Algebra Alıştırma Soruları — ACT — Sayfa 19 | Examkin