Experimental Design and Scientific Method

201 soru

Soru 41Soru

Researchers investigated the leaching of calcium ions (Ca2+Ca^{2+}) from sandy loam soil under simulated rainfall conditions. Six soil columns, each containing 500 g500\text{ g} of soil, were prepared. The simulated rainfall rate was held constant at 50 mL/hr50\text{ mL/hr} for 10 hours10\text{ hours}. The leachate was collected and analyzed for total dissolved Ca2+Ca^{2+} concentration (in mg/L\text{mg/L}). The composition of each column and the pH of the simulated rainfall applied are summarized in the table below:

ColumnSoil AmendmentRainfall pH
Column ANone (Untreated)7.0 (Neutral)
Column BNone (Untreated)4.5 (Acidic)
Column C5%5\% Biochar7.0 (Neutral)
Column D5%5\% Biochar4.5 (Acidic)
Column E5%5\% Compost7.0 (Neutral)
Column F5%5\% Compost4.5 (Acidic)

Which columns must be compared to address each research objective while isolating the single variable of interest? Match each research objective on the left with the correct column comparison on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Determine the effect of rain acidity on untreated soil
Determine the effect of biochar amendment on soil leaching under acidic conditions
Determine the effect of compost amendment on soil leaching under neutral conditions
Determine the effect of rain acidity on biochar-amended soil

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

To isolate the effect of a single independent variable, all other variables must be held constant between the experimental setup and its control group. (1) To test rain acidity on untreated soil, compare acidic rain (Column B) with neutral rain (Column A). (2) To test biochar amendment under acidic conditions, compare biochar (Column D) with untreated soil (Column B) under acidic rain. (3) To test compost amendment under neutral conditions, compare compost (Column E) with untreated soil (Column A) under neutral rain. (4) To test rain acidity on biochar soil, compare acidic rain (Column D) with neutral rain (Column C) using biochar-amended soil.
In experimental designs, the effect of an independent variable is isolated by comparing the experimental setup with a baseline setup (control group) that is identical in all aspects except for the variable being tested. To determine rain acidity's effect on untreated soil, compare Column B (untreated, acidic rain) to Column A (untreated, neutral rain). To determine biochar's effect under acidic conditions, compare Column D (biochar, acidic rain) to Column B (untreated, acidic rain). To determine compost's effect under neutral conditions, compare Column E (compost, neutral rain) to Column A (untreated, neutral rain). To determine rain acidity's effect on biochar-amended soil, compare Column D (biochar, acidic rain) to Column C (biochar, neutral rain).

Adım Adım Çözüm

1
Identify the independent variable that is being manipulated for each research objective.
The independent variables are: rainfall pH for objectives evaluating acidity, and soil amendment type for objectives evaluating soil treatments.
Knowing which variable changes allows us to identify the other variables that must remain constant to act as a proper control or baseline.
2
Locate the experimental group and select a control group where all other factors are identical except the independent variable.
For testing rain acidity on untreated soil, compare Column B (pH 4.5, untreated) with Column A (pH 7.0, untreated). For testing biochar under acidic rain, compare Column D (biochar, pH 4.5) with Column B (untreated, pH 4.5). For testing compost under neutral rain, compare Column E (compost, pH 7.0) with Column A (untreated, pH 7.0). For testing rain acidity on biochar, compare Column D (pH 4.5, biochar) with Column C (pH 7.0, biochar).
This establishes variable isolation so that differences in leaching can be confidently attributed to the single changed parameter.

Anahtar Kavram

Determining Control Groups and Baseline Conditions
Soru 42Soru

### Passage

To study the biodegradation of a synthetic polymer, polyethylene terephthalate (PET), by a newly isolated bacterium (*Thermobacillus petrolei*), researchers conducted two experiments.

In Experiment 1, five test tubes were prepared with 10 mL10\text{ mL} of a liquid nutrient medium, 50 mg50\text{ mg} of PET film, and 1.0 mL1.0\text{ mL} of an active *T. petrolei* suspension. The pH and temperature were kept constant. A different concentration of a synthetic surfactant, Surfactant X, was added to Tubes 1–4. Tube 5 did not receive Surfactant X. After 7 days, the remaining mass of PET was measured to evaluate degradation.

In Experiment 2, to determine whether the PET degradation observed in Experiment 1 was due to active bacterial metabolic activity rather than non-biological chemical hydrolysis or passive physical absorption onto the bacterial biomass, the researchers prepared four additional test tubes (Tubes 6–9) under the same environmental conditions as Experiment 1, but modified the tube contents as shown below:

TubeLiquid Nutrient MediumPET Film*T. petrolei* SuspensionSurfactant X
6YesYesNo (sterile water added instead)None
7YesNoYes (active cells)None
8No (sterile water added instead)YesYes (active cells)None
9YesYesYes (heat-killed cells instead)None

To demonstrate that the degradation of PET film in Experiment 1 was specifically caused by the active metabolism of living *T. petrolei* cells rather than passive physical absorption of the polymer by the bacterial biomass, which of the following tubes from Experiment 2 serves as the most appropriate control when compared to Tube 5?

Cevabı ve açıklamayı göster

Cevap: Tube 9, because it contains heat-killed *T. petrolei* cells, allowing researchers to isolate the effect of active bacterial metabolism from passive polymer absorption by the bacterial biomass.

Cevap

The option designating Tube 9, because it contains heat-killed cells which control for passive physical absorption by the bacterial biomass.
To demonstrate that polymer degradation is caused by active bacterial metabolism rather than passive physical adsorption or binding of the polymer to the cell walls, researchers must test a control group containing dead (heat-killed) cells. Comparing Tube 5 (with active cells) to Tube 9 (with heat-killed cells) allows researchers to subtract the passive binding component, thereby isolating the contribution of active metabolism.

Adım Adım Çözüm

1
Analyze the components of the experimental baseline group (Tube 5).
Tube 5 contains liquid nutrient medium, PET film, and active *T. petrolei* cells without Surfactant X.
This establishes the biological reference condition to evaluate PET degradation without the chemical agent (Surfactant X).
2
Determine the confounding factor that needs to be isolated.
Passive physical absorption (binding of the PET polymer to the cell structure) must be separated from active biological metabolism.
Both active cells and dead cells can physically bind substances, but only active cells perform metabolic degradation.
3
Select the tube from Experiment 2 that isolates this factor.
Tube 9, which contains inactive (heat-killed) cells, keeping the biomass quantity the same while stopping metabolism.
Comparing Tube 5 (active cells) to Tube 9 (inactive cells) reveals the portion of PET loss caused specifically by metabolic processes.

Anahtar Kavram

Identifying control groups to isolate specific biological mechanisms from physical artifacts (metabolic activity vs. physical absorption).
Tahmini Süre:1m 30s
Soru 43Soru

A biology lab group investigated how wind speed affects the rate of water loss in *Phaseolus vulgaris* (common bean) plants. The group initially hypothesized that transpiration rates would increase continuously and linearly across all wind speeds due to the constant removal of the boundary layer of water vapor.

They recorded the transpiration rates at different wind speeds in a wind tunnel and compiled the data in the table below:

Wind Speed (m/s\text{m/s})Transpiration Rate (mgdm2min1\text{mg}\cdot\text{dm}^{-2}\cdot\text{min}^{-1})
0.00.01.81.8
1.01.03.53.5
2.02.05.25.2
3.03.06.86.8
4.04.07.07.0
5.05.06.96.9

Based on the results in the table, which of the following statements represents the most accurate modification of the group's initial hypothesis?

Cevabı ve açıklamayı göster

Cevap: The transpiration rate increases with wind speed up to a threshold of approximately 3.0 m/s3.0\text{ m/s}, after which it plateaus and remains relatively constant.

Cevap

The transpiration rate increases with wind speed up to a threshold of approximately 3.0 m/s3.0\text{ m/s}, after which it plateaus and remains relatively constant.
The correct option correctly describes the two distinct phases of the data trend: a steady rise in the transpiration rate up to about 3.0 m/s3.0\text{ m/s}, followed by a plateau where the rate remains constant. This modification reflects the physical limits of the system, such as stomatal closure in high winds, which prevent a continuous linear increase.

Adım Adım Çözüm

1
Analyze the change in transpiration rate values as wind speed increases from 0.0 m/s0.0\text{ m/s} to 3.0 m/s3.0\text{ m/s}.
The rate increases steadily from 1.81.8 to 6.8 mgdm2min16.8\text{ mg}\cdot\text{dm}^{-2}\cdot\text{min}^{-1}.
This establishes that there is an initial positive relationship between wind speed and transpiration rate, supporting the direction of the initial hypothesis in this range.
2
Analyze the transpiration rate values as wind speed increases further from 3.0 m/s3.0\text{ m/s} to 5.0 m/s5.0\text{ m/s}.
The rate changes minimally from 6.86.8 to 7.07.0 and then slightly drops to 6.9 mgdm2min16.9\text{ mg}\cdot\text{dm}^{-2}\cdot\text{min}^{-1}.
This shows that the rate levels off and no longer increases, indicating a threshold effect or plateau.
3
Combine these observations to formulate a modified hypothesis that matches the overall data trend.
The rate increases initially but plateaus after a threshold of approximately 3.0 m/s3.0\text{ m/s}.
A modified hypothesis must reflect both trends observed in the experimental data to be scientifically valid.

Anahtar Kavram

Formulating and Modifying Hypotheses
Tahmini Süre:1m 30s
Soru 44Soru

An environmental chemist studies the capture of carbon dioxide (CO2CO_2) by a newly synthesized metal-organic framework (MOF) at different temperatures. The chemist proposes the following hypothesis:

*Hypothesis*: As the temperature of the system increases, the amount of CO2CO_2 gas adsorbed by the MOF at any given pressure will increase, because the increased kinetic energy of the gas molecules will enhance their interaction with the MOF's pore surface.

The chemist measures the mass of CO2CO_2 adsorbed per gram of MOF (madsm_{ads}, in mg/gmg/g) at three different temperatures across a range of pressures, as shown in the table below:

Pressure (bar)madsm_{ads} at 273 K273\text{ K} (mg/g)madsm_{ads} at 298 K298\text{ K} (mg/g)madsm_{ads} at 323 K323\text{ K} (mg/g)
1.01208550
3.021015095
5.0260190120
7.0290215140
10.0320240160

Based on the experimental results, which of the following describes how the hypothesis should be modified?

Cevabı ve açıklamayı göster

Cevap: The hypothesis should be modified to state that as temperature increases, the amount of CO2CO_2 adsorbed decreases, indicating that the adsorption process is weakened by higher thermal energy.

Cevap

The hypothesis should be modified to state that as temperature increases, the amount of CO2CO_2 adsorbed decreases, indicating that the adsorption process is weakened by higher thermal energy.
The correct answer states that the hypothesis should be modified to show that adsorption decreases as temperature increases. Comparing the columns at any given pressure (horizontal rows) reveals that madsm_{ads} consistently drops as temperature rises from 273 K273\text{ K} to 323 K323\text{ K}. For instance, at 1.0 bar1.0\text{ bar}, the adsorption goes from 120 mg/g120\text{ mg/g} to 85 mg/g85\text{ mg/g} and then to 50 mg/g50\text{ mg/g}. This inverse relationship directly refutes the chemist's proposal that higher temperatures would increase adsorption, requiring a complete reversal of the hypothesized trend.

Adım Adım Çözüm

1
Identify the variable relationships in the hypothesis.
The hypothesis predicts a direct relationship: increasing temperature increases the mass of gas adsorbed (madsm_{ads}) at any constant pressure.
To evaluate the hypothesis, we must first define the expected trend it predicts.
2
Analyze the experimental data for temperature effects at a constant pressure.
At a constant pressure of 5.0 bar5.0\text{ bar}, madsm_{ads} is 260 mg/g260\text{ mg/g} at 273 K273\text{ K}, 190 mg/g190\text{ mg/g} at 298 K298\text{ K}, and 120 mg/g120\text{ mg/g} at 323 K323\text{ K}. This represents an inverse relationship.
Comparing values across a single row isolates the effect of temperature on adsorption while keeping pressure constant.
3
Determine the necessary modification to the hypothesis.
Since the actual trend is opposite to the prediction (adsorption decreases as temperature increases), the hypothesis must be modified to reflect this inverse relationship.
Scientific hypotheses must be updated or discarded when they are contradicted by empirical data.

Anahtar Kavram

Formulating and Modifying Hypotheses
Soru 45Soru

A student proposed the following hypothesis regarding the behavior of crickets:

*Hypothesis*: As the surrounding temperature increases, the chirping rate of crickets will decrease because lower temperatures stimulate metabolic activity.

The student measured the chirping rate of a group of crickets at different temperatures and recorded the results in the table below:

Temperature (°C)Average chirps per minute
1560
2080
25100
30120

Based on the data, how should the student modify the hypothesis?

Cevabı ve açıklamayı göster

Cevap: Modify the hypothesis to state that as the temperature increases, the average chirping rate increases.

Cevap

Modify the hypothesis to state that as the temperature increases, the average chirping rate increases.
The correct option states that the hypothesis should be modified to show that as temperature increases, the average chirping rate increases. This is supported by the data table: as the temperature rises from 15°C to 30°C, the average chirping rate steadily increases from 60 to 120 chirps per minute.

Adım Adım Çözüm

1
Analyze the original hypothesis and compare it with the collected data.
The original hypothesis states that as temperature increases, chirping rate decreases. The data table shows that at 15°C, the chirping rate is 60; at 20°C, it is 80; at 25°C, it is 100; and at 30°C, it is 120.
To determine how to modify the hypothesis, we must first compare the initial prediction to the actual experimental observations.
2
Identify the relationship between temperature and chirping rate shown in the data.
Both temperature and average chirping rate increase together, showing a direct relationship.
This relationship directly contradicts the original hypothesis, which predicted an inverse relationship.
3
Formulate a modified hypothesis that accurately reflects the observed direct relationship.
The modified hypothesis must state that as temperature increases, the average chirping rate increases.
A scientific hypothesis must be revised or replaced when experimental evidence contradicts its predictions.

Anahtar Kavram

A hypothesis is a testable statement that must be modified or rejected if it is contradicted by experimental evidence. When data shows that a dependent variable increases as the independent variable increases, the hypothesis must reflect this direct relationship.
Tahmini Süre:1m 0s
Soru 46Soru

### Passage

To study the biodegradation of polyethylene terephthalate (PET) by a newly engineered strain of *Pseudomonas putida*, researchers set up several liquid culture vessels containing a baseline mineral medium (M9M9), a fixed concentration of PET film (0.5% w/v0.5\%\text{ w/v}), and varying combinations of additional factors. The strain normally requires a co-substrate, such as succinate, to support growth during PET degradation. The researchers tested the effects of adding 10 mM10\text{ mM} succinate, adding 50 μM50\text{ }\mu\text{M} of cadmium (Cd2+Cd^{2+}, a heavy metal inhibitor), and incubating at different temperatures. Each vessel was inoculated with 106 cells/mL10^6\text{ cells/mL} of *P. putida* and incubated for 7 days.

The setups for the groups are described in the table below:

GroupMineral MediumPET FilmSuccinate (10 mM10\text{ mM})Cadmium (50 μM50\text{ }\mu\text{M})Temperature (°C)
1YesYesNoNo30
2YesYesYesNo30
3YesYesYesYes30
4YesYesYesNo37
5YesNoYesNo30
6YesYesNoYes30

The researchers measured the dry weight loss percentage of the PET film after 7 days to evaluate PET-degrading activity.

To isolate and determine the specific inhibitory effect of cadmium (Cd2+Cd^{2+}) on PET biodegradation at the standard growth temperature of 30 °C30\text{ °C}, the researchers must compare the PET weight loss of Group 3 to the PET weight loss of which of the following groups?

Cevabı ve açıklamayı göster

Cevap: Group 2, because it is identical to Group 3 in all conditions except it lacks cadmium, isolating cadmium as the single variable.

Cevap

Group 2, because it is identical to Group 3 in all conditions except it lacks cadmium, isolating cadmium as the single variable.
To isolate the effect of cadmium (Cd2+Cd^{2+}) on PET biodegradation at 30 °C30\text{ °C}, the researchers must compare the experimental group containing cadmium to a control group that is identical in every way except for the presence of cadmium. Group 3 contains mineral medium, PET, succinate, cadmium, and is incubated at 30 °C30\text{ °C}. The group that matches all of these conditions but lacks cadmium is Group 2. Therefore, comparing Group 3 to Group 2 isolates cadmium as the single independent variable.

Adım Adım Çözüm

1
Identify the treatment group of interest and its parameters.
Group 3 contains mineral medium, PET film, succinate, and cadmium, incubated at 30 °C30\text{ °C}.
This establishes the active experimental group containing the independent variable (cadmium) whose effect we want to isolate.
2
Determine the single independent variable being investigated.
The target variable to isolate is the presence of cadmium (Cd2+Cd^{2+}) at a temperature of 30 °C30\text{ °C}.
A controlled experiment requires keeping all other variables constant to ensure any change in the dependent variable is due to the single manipulated variable.
3
Scan the table for a group that is identical to Group 3 in all parameters (medium, PET, succinate, temperature) except for the presence of cadmium.
Group 2 matches Group 3 in all conditions (incubation at 30 °C30\text{ °C} with mineral medium, PET, and succinate) but does not contain cadmium.
Comparing Group 3 directly to Group 2 isolates cadmium as the only variable that differs, establishing Group 2 as the proper control group.

Anahtar Kavram

Determining Control Groups and Baseline Conditions
Tahmini Süre:1m 30s
Soru 47Soru

A student investigates the rate of an enzyme-catalyzed reaction. The student proposed the following hypothesis:

*Hypothesis*: The rate of the reaction is directly proportional to the enzyme concentration at all temperatures, meaning that doubling the enzyme concentration will double the reaction rate regardless of the temperature.

To test this hypothesis, the student measured the reaction rate (in μmol/min\mu\text{mol/min}) at enzyme concentrations of 1.0 g/L1.0\text{ g/L} and 2.0 g/L2.0\text{ g/L} across four different temperatures. The results are shown in the table below:

Temperature (C^\circ\text{C})Reaction rate at 1.0 g/L1.0\text{ g/L} enzyme (μmol/min\mu\text{mol/min})Reaction rate at 2.0 g/L2.0\text{ g/L} enzyme (μmol/min\mu\text{mol/min})
151512.412.424.824.8
252522.122.144.244.2
353531.531.563.063.0
454510.210.212.112.1

Which of the following statements best explains whether the data support the student's hypothesis, and how the hypothesis should be modified?

Cevabı ve açıklamayı göster

Cevap: The data do not support the hypothesis, because doubling the enzyme concentration did not double the reaction rate at 45C45^\circ\text{C}; the hypothesis should be modified to state that the direct proportion only holds below the temperature at which the enzyme denatures.

Cevap

The data do not support the hypothesis, because doubling the enzyme concentration did not double the reaction rate at 45C45^\circ\text{C}; the hypothesis should be modified to state that the direct proportion only holds below the temperature at which the enzyme denatures.
The correct answer is that the data do not support the hypothesis because doubling the enzyme concentration did not double the reaction rate at 45C45^\circ\text{C}. The hypothesis must be modified to state that the direct proportion only holds below the temperature at which the enzyme denatures. This is supported by the data: at 15C15^\circ\text{C}, 25C25^\circ\text{C}, and 35C35^\circ\text{C}, the rate doubled exactly, but at 45C45^\circ\text{C}, the rate only increased slightly (from 10.210.2 to 12.112.1). This deviation indicates the hypothesis is incorrect as written and requires a temperature limit.

Adım Adım Çözüm

1
Identify the core prediction made by the student's hypothesis.
The hypothesis predicts that doubling the enzyme concentration will double the reaction rate at all temperatures.
This establishes the mathematical relationship that must be tested against the experimental data.
2
Analyze the experimental data for each temperature to determine if the rate doubles when enzyme concentration increases from 1.0 g/L1.0\text{ g/L} to 2.0 g/L2.0\text{ g/L}.
At 15C15^\circ\text{C}, 12.4×2=24.812.4 \times 2 = 24.8 (doubled). At 25C25^\circ\text{C}, 22.1×2=44.222.1 \times 2 = 44.2 (doubled). At 35C35^\circ\text{C}, 31.5×2=63.031.5 \times 2 = 63.0 (doubled). At 45C45^\circ\text{C}, 10.2×2=20.410.2 \times 2 = 20.4, but the actual rate at 2.0 g/L2.0\text{ g/L} is only 12.112.1 (not doubled).
Checking each individual temperature test condition determines if the hypothesis holds under all circumstances.
3
Determine if the hypothesis is supported and how it should be modified.
Since the rate did not double at 45C45^\circ\text{C}, the hypothesis is not supported. It must be modified to include a temperature limitation, recognizing that the direct proportion fails at higher temperatures (such as 45C45^\circ\text{C}) where enzymes typically undergo thermal denaturation.
A scientific hypothesis must be revised or restricted when experimental evidence contradicts its predictions.

Anahtar Kavram

Evaluating and modifying a scientific hypothesis based on experimental results that contradict the initial prediction.
Soru 48Soru

To investigate the effect of wind speed on the rate of transpiration, students placed four identical oak saplings in potometers. Each sapling was exposed to a fan at a different distance to vary the wind speed, with Trial 4 serving as the control group (no fan). The trials were conducted sequentially inside a greenhouse, and the ambient temperature, relative humidity, and transpiration rate were recorded for each 1-hour trial. The results are shown in the table below.

TrialDistance from fan (m\text{m})Time of dayTemperature (C^\circ\text{C})Relative Humidity (%\%)Transpiration rate (mL/m2/hr\text{mL/m}^2/\text{hr})
10.50.510:00 AM – 11:00 AM222260604.24.2
21.01.011:00 AM – 12:00 PM252550504.84.8
31.51.512:00 PM – 1:00 PM282842425.15.1
4No fan1:00 PM – 2:00 PM303035353.93.9

Based on these results, the students concluded that a wind speed corresponding to a distance of 1.5 m1.5\text{ m} from the fan maximizes the rate of transpiration in oak saplings. Which of the following statements identifies the primary flaw in this conclusion?

Cevabı ve açıklamayı göster

Cevap: The sequential execution of the trials allowed ambient temperature to rise and relative humidity to fall over time, both of which independently increase transpiration rates and obscure the true effect of wind speed.

Cevap

The correct answer states that the sequential execution of the trials allowed ambient temperature to rise and relative humidity to fall over time, both of which independently increase transpiration rates and obscure the true effect of wind speed.
The correct option is correct because conducting the trials sequentially throughout the day allowed ambient temperature to rise and relative humidity to fall. Both higher temperatures and lower relative humidity increase the rate of transpiration by increasing the rate of water evaporation from the leaves. Because these environmental factors changed systematically alongside the distance from the fan, they act as confounding variables, making it impossible to determine whether the differences in transpiration rate were caused by the change in wind speed or the changes in temperature and humidity.

Adım Adım Çözüm

1
Identify the independent variable and the dependent variable in the experiment.
The independent variable is the distance from the fan (representing wind speed). The dependent variable is the measured transpiration rate of the oak saplings.
Establishing the variables is the first step in assessing the validity of an experimental design.
2
Examine the environmental conditions (temperature and relative humidity) recorded across the trials to see if they were controlled.
The temperature systematically increased from 22C22^\circ\text{C} in Trial 1 to 30C30^\circ\text{C} in Trial 4, while relative humidity systematically fell from 60%60\% to 35%35\%.
To isolate the effect of the independent variable, all other variables that could influence the outcome must be kept constant.
3
Determine how these uncontrolled environmental variables affect the dependent variable.
Higher temperatures and lower relative humidity increase the atmospheric vapor pressure deficit, which accelerates evaporation and increases transpiration rates in plants.
This establishes that the environmental changes act as confounding variables that favor higher transpiration rates in later trials, regardless of the wind speed.
4
Evaluate the validity of the students' conclusion that transpiration is maximized at 1.5 m1.5\text{ m}.
Because temperature and humidity were not controlled and varied in a way that increases transpiration, the peak transpiration observed in Trial 3 (1.5 m1.5\text{ m}) cannot be uniquely attributed to the wind speed.
A scientific conclusion is invalid when confounding variables are allowed to vary systematically alongside the independent variable.

Anahtar Kavram

Identifying Confounding Variables
Tahmini Süre:2m 30s
Soru 49Soru

### Passage

An environmental scientist investigated the efficiency of sunflower plants (*Helianthus annuus*) in phytoremediation—the process of using living plants to remove heavy metals from contaminated soil. Sunflowers were grown in pots containing soil with a baseline lead (Pb2+Pb^{2+}) concentration of 500 mg/kg500\text{ mg/kg} under controlled greenhouse conditions. The scientist set up several experimental groups to evaluate how two soil amendments—biochar and arbuscular mycorrhizal fungi (AMF)—affect the rate of Pb2+Pb^{2+} uptake by the plants.

The experimental groups were designed as follows:
* Group A: Soil with 0 mg/kg0\text{ mg/kg} of Pb2+Pb^{2+}, no biochar, no AMF.
* Group B: Soil with 500 mg/kg500\text{ mg/kg} of Pb2+Pb^{2+}, no biochar, no AMF.
* Group C: Soil with 500 mg/kg500\text{ mg/kg} of Pb2+Pb^{2+}, biochar added (5% w/w5\%\text{ w/w}), no AMF.
* Group D: Soil with 500 mg/kg500\text{ mg/kg} of Pb2+Pb^{2+}, no biochar, AMF added.
* Group E: Soil with 500 mg/kg500\text{ mg/kg} of Pb2+Pb^{2+}, biochar added (5% w/w5\%\text{ w/w}), AMF added.

All groups were watered daily with 100 mL100\text{ mL} of distilled water and kept at a constant temperature of 24C24^\circ\text{C} under a 14-hour14\text{-hour} light/10-hour10\text{-hour} dark cycle. After 6 weeks6\text{ weeks}, the dry biomass of the plants and the concentration of Pb2+Pb^{2+} in the plant tissues were measured.

To evaluate the specific influence of each experimental variable, the scientist must compare the results of a test group to a corresponding control or baseline group. Match each of the following experimental objectives with the group that serves as the most appropriate control or baseline.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Determine the baseline growth of the plants in the absence of lead contamination.
Isolate the effect of the biochar amendment on lead accumulation in the absence of AMF.
Isolate the specific effect of biochar when AMF is already present in the soil.
Isolate the specific effect of AMF when biochar is already present in the soil.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

To isolate a specific variable, the control group must keep all other variables identical to the test group except for the one being tested. The baseline growth of plants without contamination is established by Group A. The isolated effect of biochar in the absence of AMF is found by comparing Group C to Group B. The isolated effect of biochar in the presence of AMF is found by comparing Group E to Group D. The isolated effect of AMF in the presence of biochar is found by comparing Group E to Group C.
To isolate the effect of a single independent variable, you compare the experimental group (which contains the variable) to a control group that is identical in every way except it lacks that specific variable. Group A acts as the baseline for non-contaminated growth. Group B acts as the baseline for contaminated growth without amendments. Comparing Group E to Group D isolates the effect of biochar, since Group D already has AMF. Comparing Group E to Group C isolates the effect of AMF, since Group C already has biochar.

Adım Adım Çözüm

1
Identify the independent variables in the experiment.
The independent variables are lead concentration (00 vs. 500 mg/kg500\text{ mg/kg}), biochar amendment (none vs. 5% w/w5\%\text{ w/w}), and AMF inoculation (none vs. added).
Understanding the variables is essential to determining which ones must be held constant to isolate the target effect.
2
Determine the control needed for baseline growth.
Group A has no lead, no biochar, and no AMF, which represents the background growth rate of sunflowers.
To see the effect of lead itself, plants must be grown without lead and without any remedial amendments.
3
Isolate biochar alone without AMF.
Comparing Group C (lead + biochar) to Group B (lead + no biochar) isolates biochar since AMF is absent in both.
Group B serves as the control because it has the same lead contamination level and lacks the biochar amendment.
4
Isolate biochar in the presence of AMF.
Comparing Group E (lead + biochar + AMF) to Group D (lead + no biochar + AMF) isolates biochar because AMF is held constant.
To see the effect of adding biochar when AMF is present, the control group must have AMF but not biochar.
5
Isolate AMF in the presence of biochar.
Comparing Group E (lead + biochar + AMF) to Group C (lead + biochar + no AMF) isolates AMF because biochar is held constant.
To see the effect of adding AMF when biochar is present, the control group must have biochar but not AMF.

Anahtar Kavram

Determining Control Groups and Baseline Conditions
Tahmini Süre:2m 0s
Soru 50Soru

A student wanted to test how temperature affects the rate of a chemical reaction between baking soda and vinegar. The student performed two trials:

* Trial 1: 10 g10\text{ g} of baking soda was mixed with 50 mL50\text{ mL} of vinegar at 20C20^\circ\text{C} in a beaker, and the mixture was stirred.
* Trial 2: 10 g10\text{ g} of baking soda was mixed with 50 mL50\text{ mL} of vinegar at 40C40^\circ\text{C} in an identical beaker, and the mixture was not stirred.

The reaction rate was determined by measuring the volume of carbon dioxide gas produced. Which of the following describes a flaw in this experimental design?

Cevabı ve açıklamayı göster

Cevap: Stirring the mixture in only one of the trials introduces a confounding variable.

Cevap

Stirring the mixture in only one of the trials introduces a confounding variable.
Stirring affects how quickly baking soda and vinegar mix and react. By stirring only the first trial, the student introduced an uncontrolled variable (stirring), making it impossible to determine if the difference in reaction rate was caused by the temperature difference or the stirring.

Adım Adım Çözüm

1
Identify the goal of the experiment and the independent variable.
The goal is to test the effect of temperature (independent variable) on the reaction rate.
Understanding what is being tested helps separate the variable that should change from those that should be controlled.
2
Examine the experimental setup of both trials to see if any other variables changed.
In Trial 1, the mixture was stirred, but in Trial 2, it was not stirred. Both temperature and stirring differed between the trials.
A valid experiment must only vary the independent variable while keeping all other potential variables constant.
3
Determine the impact of the uncontrolled variable on the conclusion.
Stirring is a confounding variable because it changes between the trials and affects reaction rate, meaning any difference in results cannot be solely attributed to temperature.
This identifies the experimental flaw and the source of error.

Anahtar Kavram

An experimental design must control all variables except the independent variable to prevent confounding results.
Soru 51Soru

### Passage
A team of geobiologists investigated the role of the soil bacterium *Bacillus subtilis* and soil humic acids on the dissolution rate of calcite (CaCO3CaCO_3), a common carbonate mineral. Five experimental trials were conducted at 25C25^\circ\text{C} for 14 days. In each trial, 10.0 grams of calcite was placed in a reaction vessel containing 500 mL of an aqueous solution. The dissolution rate was determined by measuring the cumulative concentration of calcium ions (Ca2+Ca^{2+}) released into the solution. The experimental setups are detailed below:

* Trial 1: Sterile deionized water (pH 7.07.0), no bacteria.
* Trial 2: Aqueous solution containing 10 mg/L10\text{ mg/L} of humic acids (pH 5.55.5), no bacteria.
* Trial 3: Sterile deionized water (pH 7.07.0) inoculated with 106 cells/mL10^6\text{ cells/mL} of living *B. subtilis*.
* Trial 4: Aqueous solution containing 10 mg/L10\text{ mg/L} of humic acids (pH 5.55.5) inoculated with 106 cells/mL10^6\text{ cells/mL} of living *B. subtilis*.
* Trial 5: Aqueous solution containing 10 mg/L10\text{ mg/L} of humic acids (pH 5.55.5) inoculated with 106 cells/mL10^6\text{ cells/mL} of heat-killed *B. subtilis*.

To determine if the enhancement of calcite dissolution in the presence of humic acids is specifically driven by the active metabolic processes of living *B. subtilis* rather than the passive physical presence of bacterial cell structures, researchers must compare Trial 4 to a control group. Which trial serves as the most appropriate control group for this comparison, and why?

Cevabı ve açıklamayı göster

Cevap: Trial 5, because it contains heat-killed bacteria in humic acids, isolating the effect of active metabolic processes from the physical presence of bacterial cell structures.

Cevap

The trial with heat-killed bacteria in humic acids serves as the most appropriate control group because it keeps the physical presence of bacterial cells and the humic acid medium constant, leaving the viability of the bacteria as the only variable that differs.
The correct option is the one stating that Trial 5 serves as the control group because it contains heat-killed bacteria in humic acids, isolating the effect of active metabolic processes from the physical presence of bacterial cell structures. By keeping the chemical environment (humic acids at pH 5.5) and the physical presence of the cells constant, any difference in calcite dissolution between the two trials can be attributed solely to the active metabolic processes of the living bacteria.

Adım Adım Çözüm

1
Identify the experimental group under investigation.
The experimental group contains living *B. subtilis* in a humic acid solution (pH 5.5).
This defines the conditions containing the active variable of interest: metabolic processes in an acidic medium.
2
Determine the specific factor to be isolated.
The active metabolic processes of the bacteria must be isolated from the passive physical presence of the bacterial cell structures in the humic acid environment.
To determine if metabolic processes are the cause, the control must include the physical cells and the chemical medium but exclude metabolic activity.
3
Select the trial that holds the medium and presence of cells constant while removing cell viability.
The trial containing heat-killed bacteria (non-viable cells) in a humic acid solution is chosen.
Comparing these two setups isolates the variable of cell viability (living vs. dead), showing whether active metabolism is responsible for the difference in dissolution rates.

Anahtar Kavram

Determining Control Groups and Baseline Conditions
Tahmini Süre:2m 0s
Soru 52Soru

A geologist conducted an experiment to test the following hypothesis:

*Hypothesis*: Basalt rocks subjected to freeze-thaw cycles will experience a greater percentage loss in mass when saturated with water of lower salinity, because lower salinity water expands more upon freezing, exerting greater pressure within rock pores.

Identical basalt rock samples of the same initial mass were saturated with water of three different salinity levels: 0 g/L0\text{ g/L} (freshwater), 15 g/L15\text{ g/L} (brackish water), and 35 g/L35\text{ g/L} (ocean water). The samples were then subjected to 5050 freeze-thaw cycles between 10C-10^\circ\text{C} and 20C20^\circ\text{C}. The average percentage loss in mass for each group of samples was calculated and recorded in the table below:

Water salinity (g/L\text{g/L})Average mass loss (\%)
004.84.8
15153.23.2
35351.51.5

Do the results of the experiment support the geologist's hypothesis?

Cevabı ve açıklamayı göster

Cevap: Yes, because the average mass loss was greatest for the basalt samples saturated with the lowest salinity water (0 g/L0\text{ g/L}).

Cevap

The results support the hypothesis because the average mass loss was greatest for the basalt samples saturated with the lowest salinity water (0 g/L0\text{ g/L}).
The geologist's hypothesis predicts that basalt rocks saturated with water of lower salinity will experience a greater percentage mass loss. According to the table, the basalt samples saturated with water at 0 g/L0\text{ g/L} salinity (the lowest salinity tested) had an average mass loss of 4.8%4.8\%, which is the highest mass loss recorded. As salinity increases to 15 g/L15\text{ g/L} and then 35 g/L35\text{ g/L}, the mass loss decreases to 3.2%3.2\% and 1.5%1.5\%, respectively. This trend demonstrates that lower salinity corresponds to greater mass loss, thereby supporting the geologist's hypothesis.

Adım Adım Çözüm

1
Identify the geologist's hypothesis.
The hypothesis predicts that lower salinity water leads to a greater percentage mass loss in basalt rocks during freeze-thaw cycles.
This establishes the expected relationship between salinity (independent variable) and mass loss (dependent variable).
2
Analyze the experimental data in the table.
At 0 g/L0\text{ g/L} salinity, mass loss is 4.8%4.8\%. At 15 g/L15\text{ g/L}, mass loss is 3.2%3.2\%. At 35 g/L35\text{ g/L}, mass loss is 1.5%1.5\%.
This identifies the actual relationship between water salinity and average mass loss.
3
Compare the data trend to the hypothesis.
As salinity decreases (from 35 g/L35\text{ g/L} to 0 g/L0\text{ g/L}), the average mass loss increases (from 1.5%1.5\% to 4.8%4.8\%, with the lowest salinity yielding the greatest loss). This matches the hypothesis.
This determines whether the experimental results support or refute the geologist's hypothesis.

Anahtar Kavram

Evaluating a hypothesis against experimental data
Tahmini Süre:1m 15s
Soru 53Soru

An experiment is conducted to study how the concentration of dissolved oxygen in an aquarium affects the respiration rate of a specific fish species. A researcher predicts that if the dissolved oxygen concentration increases, the respiration rate (measured in gill flares per minute) of the fish will decrease. The table below displays the results:

Dissolved Oxygen (mg/Lmg/L)Respiration Rate (gill flares/min)
4.04.08282
6.06.06868
8.08.05454
10.010.04141

Based on the table, does the experimental data support the researcher's prediction?

Cevabı ve açıklamayı göster

Cevap: Yes, because as the dissolved oxygen concentration increased, the respiration rate decreased.

Cevap

Yes, because as the dissolved oxygen concentration increased, the respiration rate decreased.
The correct option states that the data supports the prediction because as the dissolved oxygen concentration increased, the respiration rate decreased. This matches the researcher's prediction that respiration rate would decrease as dissolved oxygen concentration increased.

Adım Adım Çözüm

1
Identify the researcher's prediction.
The researcher predicted that as dissolved oxygen concentration increases, the respiration rate will decrease.
To evaluate the hypothesis, we first need to know what trend is being predicted.
2
Analyze the trend in the data table.
As the dissolved oxygen concentration increases from 4.0 mg/L4.0\text{ mg/L} to 10.0 mg/L10.0\text{ mg/L}, the respiration rate decreases from 8282 to 41 gill flares/min41\text{ gill flares/min}.
To see if the prediction is correct, we must determine the actual relationship shown by the data.
3
Compare the predicted trend with the actual trend.
The predicted trend (increase in oxygen leads to decrease in respiration) matches the actual trend (as oxygen increases, respiration decreases). Therefore, the data supports the prediction.
This comparison allows us to make the final determination.

Anahtar Kavram

Evaluating a hypothesis using experimental data
Tahmini Süre:45s
Soru 54Soru

A student hypothesized that as the concentration of dissolved carbon dioxide (CO2\text{CO}_2) in water increases, the pH of the solution will increase. To test this, the student bubbled different volumes of CO2\text{CO}_2 gas into 100 mL samples of distilled water at 25C25^\circ\text{C} and measured the pH of each sample. The results are shown in the table below:

SampleVolume of CO2\text{CO}_2 bubbled (mL)pH of solution
107.0
2106.2
3205.8
4305.5
5405.3

Based on these results, which of the following represents the most appropriate modification to the student's hypothesis?

Cevabı ve açıklamayı göster

Cevap: Modify the hypothesis to state that as the concentration of dissolved CO2\text{CO}_2 increases, the pH of the solution decreases.

Cevap

Modify the hypothesis to state that as the concentration of dissolved carbon dioxide increases, the pH of the solution decreases.
The correct answer is correct because the experimental data in the table demonstrate a clear trend: as the volume of carbon dioxide bubbled into the water increases from 0 mL to 40 mL, the pH of the solution decreases from 7.0 to 5.3. Since bubbling carbon dioxide increases the dissolved concentration of the gas, the student must modify the hypothesis to reflect this inverse relationship.

Adım Adım Çözüm

1
Analyze the student's initial hypothesis regarding the relationship between carbon dioxide concentration and pH.
The initial hypothesis states that an increase in dissolved carbon dioxide concentration will cause the pH of the solution to increase.
Establishing the initial prediction allows for a direct comparison with the collected data to see if a modification is necessary.
2
Examine the experimental data in the table to determine the actual relationship between the independent variable (volume of bubbled carbon dioxide) and the dependent variable (pH).
As the volume of bubbled carbon dioxide increases from 0 mL to 40 mL, the measured pH of the solution decreases from 7.0 to 5.3.
Determining the observed relationship from the data provides the basis for correcting the hypothesis.
3
Compare the initial hypothesis to the observed trend and formulate the correct modification.
The hypothesis predicted a direct relationship (pH increases as concentration increases), but the data show an inverse relationship (pH decreases as concentration increases). Thus, the student should modify the hypothesis to state that increasing dissolved carbon dioxide concentration decreases the pH.
A scientific hypothesis must be modified to align with the empirical evidence obtained from the experiment.

Anahtar Kavram

Formulating and Modifying Hypotheses
Tahmini Süre:1m 0s
Soru 55Soru

A student proposed the following hypothesis regarding planetary atmospheres:

*Hypothesis*: The rate of atmospheric escape of a gas from a planet's atmosphere is determined solely by the planet's surface temperature, such that planets with higher surface temperatures will experience higher rates of escape for all gases, regardless of the gravity of the planet or the molar mass of the gas.

To test this hypothesis, scientists measured the escape rates of helium (HeHe, molar mass 4 g/mol\approx 4\text{ g/mol}) and xenon (XeXe, molar mass 131 g/mol\approx 131\text{ g/mol}) from three different planets. The surface temperature, surface gravity (measured in units of gg, where 1 g=9.8 m/s21\text{ }g = 9.8\text{ m/s}^2), and escape rates of the gases are shown in the table below:

PlanetSurface Temperature (KK)Surface Gravity (gg)Helium (HeHe) Escape Rate (kg/s)Xenon (XeXe) Escape Rate (kg/s)
Planet X3003000.400.401.2×1031.2 \times 10^30.00.0
Planet Y5005000.900.904.5×1024.5 \times 10^20.00.0
Planet Z5005000.400.408.8×1048.8 \times 10^41.1×1011.1 \times 10^1

Based on these results, which of the following modifications to the student's hypothesis is best supported by the data?

Cevabı ve açıklamayı göster

Cevap: The escape rate of a gas depends on both the planet's surface gravity and the molar mass of the gas, with lower surface gravity and lower molar mass leading to higher escape rates.

Cevap

The escape rate of a gas depends on both the planet's surface gravity and the molar mass of the gas, with lower surface gravity and lower molar mass leading to higher escape rates.
The correct option correctly states that the escape rate depends on both surface gravity and molar mass, with lower gravity and lower molar mass promoting higher escape rates. This is supported by comparing Planet X and Planet Y, where the higher gravity of Planet Y results in a lower helium escape rate despite its higher temperature, and by comparing the escape rates of Helium and Xenon on Planet Z, where the lighter gas (Helium) escapes at a much faster rate.

Adım Adım Çözüm

1
Analyze the student's initial hypothesis.
The hypothesis claims that atmospheric escape rate depends solely on surface temperature, and is independent of gravity or molar mass.
To evaluate or modify a hypothesis, we must first understand its core assumptions.
2
Compare the Helium escape rates of Planet X and Planet Y to test if temperature is the sole factor.
Planet Y has a higher temperature (500 K500\text{ K}) than Planet X (300 K300\text{ K}), but a lower Helium escape rate (4.5×102 kg/s4.5 \times 10^2\text{ kg/s} vs. 1.2×103 kg/s1.2 \times 10^3\text{ kg/s}). This difference corresponds to Planet Y's higher surface gravity (0.90 g0.90\text{ }g vs. 0.40 g0.40\text{ }g).
This demonstrates that surface gravity is a confounding factor that must be included in the hypothesis, and that higher gravity decreases the escape rate.
3
Compare the escape rates of Helium and Xenon on Planet Z to evaluate the effect of molar mass.
On Planet Z, Helium (molar mass 4 g/mol\approx 4\text{ g/mol}) has a much higher escape rate (8.8×104 kg/s8.8 \times 10^4\text{ kg/s}) than Xenon (molar mass 131 g/mol\approx 131\text{ g/mol}, escape rate 1.1×101 kg/s1.1 \times 10^1\text{ kg/s}).
This shows that the molar mass of the gas also affects the escape rate, with lighter gases escaping more readily, which invalidates the claim that escape rate is independent of molar mass.
4
Synthesize these findings to identify the correct modification.
The hypothesis must be modified to include both surface gravity (inversely related to escape rate) and gas molar mass (inversely related to escape rate).
This directly addresses all the contradictions found between the original hypothesis and the experimental data.

Anahtar Kavram

Evaluating and modifying a hypothesis based on multi-variable experimental data.
Tahmini Süre:2m 30s
Soru 56Soru

A group of students investigated the catalytic decomposition of hydrogen peroxide (H2O2H_2O_2) into water and oxygen gas using yeast as a source of the enzyme catalase:

2H2O2(aq)catalase2H2O(l)+O2(g)2H_2O_2(aq) \xrightarrow{\text{catalase}} 2H_2O(l) + O_2(g)

In Study 1, they mixed 10 mL10\text{ mL} of 3% H2O23\%\ H_2O_2 with 2 mL2\text{ mL} of a 5%5\% yeast suspension in a sealed flask at 20C20^\circ\text{C} and recorded the volume of O2O_2 gas collected in a gas syringe over 5 minutes. They repeated this procedure using 10%10\%, 15%15\%, and 20%20\% yeast suspensions.

In Study 2, they used a 10%10\% yeast suspension and repeated the procedure at temperatures of 10C10^\circ\text{C}, 30C30^\circ\text{C}, 40C40^\circ\text{C}, and 50C50^\circ\text{C}. The volume of O2O_2 collected at 5 minutes increased with temperature up to 40C40^\circ\text{C} but was extremely low at 50C50^\circ\text{C}.

The students want to perform a follow-up experiment to determine if the low O2O_2 production at 50C50^\circ\text{C} is due to the permanent thermal denaturation of catalase, or if the enzyme is simply temporarily less active at 50C50^\circ\text{C} but remains functional when returned to a lower temperature. Which of the following procedures would best allow the students to test this hypothesis?

Cevabı ve açıklamayı göster

Cevap: Preheat a sample of the 10%10\% yeast suspension to 50C50^\circ\text{C} for 10 minutes, cool the sample back to 20C20^\circ\text{C}, and then mix it with 3% H2O23\%\ H_2O_2 at 20C20^\circ\text{C} to measure the volume of O2O_2 produced over 5 minutes.

Cevap

Preheat a sample of the 10%10\% yeast suspension to 50C50^\circ\text{C} for 10 minutes, cool the sample back to 20C20^\circ\text{C}, and then mix it with 3% H2O23\%\ H_2O_2 at 20C20^\circ\text{C} to measure the volume of O2O_2 produced over 5 minutes.
The correct procedure targets the yeast suspension containing the catalase enzyme, subjects it to the high temperature of 50C50^\circ\text{C}, and cools it back down to the baseline temperature of 20C20^\circ\text{C} before mixing it with fresh H2O2H_2O_2 substrate. If the enzyme is permanently denatured, it will remain inactive at 20C20^\circ\text{C} and produce little to no O2O_2. If the inactivation is temporary, the rate will recover to normal levels. By keeping the reactants separate during heating, this method avoids the confounding effect of reactant depletion.

Adım Adım Çözüm

1
Identify the source of the enzyme (catalase) within the experimental setup.
The catalase enzyme is in the yeast suspension, not in the hydrogen peroxide substrate.
To test the thermal denaturation of catalase, the heat treatment must target the yeast suspension.
2
Formulate a method to test the reversibility of the high-temperature inactivation.
The yeast suspension must be heated to the target high temperature (50C50^\circ\text{C}) and then returned to a lower baseline temperature (20C20^\circ\text{C}) where it normally functions well.
If the inactivation is temporary, activity will recover at 20C20^\circ\text{C}; if it is permanent (denaturation), activity will not recover.
3
Isolate the heat treatment phase from the reaction phase to control for confounding variables.
Keep the yeast suspension separate from the hydrogen peroxide while heating and cooling, and only mix them once the temperature is back to 20C20^\circ\text{C}.
Mixing them during the heating phase would consume the substrate, introducing reactant depletion as a confounding variable that could explain the lack of subsequent gas production.

Anahtar Kavram

Isolating variables and controlling for reactant depletion when designing follow-up experiments to test the reversibility of temperature-induced enzyme inactivation.
Tahmini Süre:3m 0s
Soru 57Soru

A group of students designed experiments to study yeast fermentation under various conditions. During their planning, they identified several procedural issues. Match each experimental procedure to the primary source of error or confounding variable it introduces.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Testing the fermentation rate of different sugars using different brands of yeast for each sugar type.
Measuring the volume of carbon dioxide gas produced using a beaker with 50 mL50\text{ mL} markings instead of a graduated cylinder with 1 mL1\text{ mL} markings.
Placing the yeast mixture in direct sunlight for Trial 1 but in a dark drawer for Trial 2 when testing the effect of temperature.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Testing the fermentation rate with different brands of yeast matches introducing biological variability; measuring gas volume using a beaker matches using a measurement tool with low precision; and placing trials in different light conditions matches failing to control external environmental conditions.
The correct pairings connect each experimental flaw to its specific category of error: varying the yeast source introduces biological variability; using a beaker instead of a graduated cylinder limits measurement precision; and varying light exposure fails to control external environmental conditions.

Adım Adım Çözüm

1
Analyze the yeast brand procedure.
Using different brands of yeast introduces potential biological differences in yeast activity and concentration.
This corresponds to introducing biological variability in the test organism.
2
Analyze the beaker measurement procedure.
Using 50 mL50\text{ mL} markings instead of 1 mL1\text{ mL} markings limits the resolution of the volume measurement.
This corresponds to using a measurement tool with low precision.
3
Analyze the sunlight exposure procedure.
Trial 1 is exposed to ambient light and radiant heat while Trial 2 is in a dark drawer, which is a difference in environmental factors.
This corresponds to a failure to control external environmental conditions.

Anahtar Kavram

Identifying sources of error and confounding variables in an experimental design.
Soru 58Soru

A student proposed the following hypothesis regarding liquid evaporation:

*Hypothesis*: The rate of evaporation of a liquid is directly proportional to its boiling point because liquids with stronger intermolecular forces evaporate more rapidly at a constant temperature of 25C25^\circ\text{C}.

To test this hypothesis, the student placed equal volumes of three different liquids in identical open beakers. The beakers were kept in a temperature-controlled room at 25C25^\circ\text{C} and 1 atm1\text{ atm} of pressure. The volume of liquid remaining in each beaker was measured over a 2424-hour period to determine the average evaporation rate. The boiling points and measured evaporation rates are shown in the table below.

LiquidBoiling Point (C^\circ\text{C})Average Evaporation Rate (mL/hr)
Acetone56564.24.2
Ethanol78781.81.8
Water1001000.50.5

Based on these results, which of the following statements best describes how the student should modify their hypothesis?

Cevabı ve açıklamayı göster

Cevap: The hypothesis should be modified to state that the rate of evaporation is inversely related to the boiling point of the liquid, because the liquid with the highest boiling point had the slowest evaporation rate.

Cevap

The hypothesis should be modified to state that the rate of evaporation is inversely related to the boiling point of the liquid, because the liquid with the highest boiling point had the slowest evaporation rate.
The experimental results show an inverse relationship between a liquid's boiling point and its evaporation rate: as the boiling point increases from 56C56^\circ\text{C} to 100C100^\circ\text{C}, the evaporation rate decreases from 4.2 mL/hr4.2\text{ mL/hr} to 0.5 mL/hr0.5\text{ mL/hr}. This contradicts the student's original hypothesis of a direct relationship. Therefore, the hypothesis must be modified to state that the rate of evaporation is inversely related to the boiling point, which is supported by the fact that water has the highest boiling point and the slowest evaporation rate.

Adım Adım Çözüm

1
Analyze the student's original hypothesis and identify what it predicts.
The hypothesis predicts a direct relationship: higher boiling point leads to a faster evaporation rate.
Understanding the hypothesis is necessary to determine if the experimental data supports or refutes it.
2
Examine the relationship between boiling point and evaporation rate in the provided data table.
As the boiling point increases from 56C56^\circ\text{C} to 78C78^\circ\text{C} to 100C100^\circ\text{C}, the evaporation rate decreases from 4.2 mL/hr4.2\text{ mL/hr} to 1.8 mL/hr1.8\text{ mL/hr} to 0.5 mL/hr0.5\text{ mL/hr}.
This step determines the actual trend shown by the empirical data.
3
Compare the data trend with the original hypothesis to formulate a modified hypothesis.
Because the evaporation rate decreases as the boiling point increases, the relationship is inverse, not direct. Water (highest boiling point) has the slowest evaporation rate, so the hypothesis must be modified to state that the evaporation rate is inversely related to the boiling point.
This allows selecting the statement that correctly describes the necessary modification and aligns with the data.

Anahtar Kavram

Evaluating and modifying a hypothesis based on experimental trends in data
Tahmini Süre:1m 30s
Soru 59Soru

A student proposed the following hypothesis regarding electromagnetism:

*Hypothesis*: The magnetic field strength of an electromagnet, as measured by the number of steel paperclips it can lift, is directly proportional to the number of wire coils wrapped around its core.

To test this hypothesis, the student wrapped varying numbers of wire coils around an iron nail core, connected the coils to a constant power source, and recorded the average number of paperclips lifted over 55 trials. The results are shown in the table below:

Number of wire coilsAverage number of paperclips lifted
101044
202088
30301212
40401313
50501313

Which of the following modifications to the hypothesis is best supported by the experimental results?

Cevabı ve açıklamayı göster

Cevap: The magnetic field strength is directly proportional to the number of coils only up to 3030 coils, after which additional coils do not further increase the strength.

Cevap

The magnetic field strength is directly proportional to the number of coils only up to 3030 coils, after which additional coils do not further increase the strength.
The correct answer is correct because the ratio of paperclips to coils is constant at 0.40.4 from 1010 to 3030 coils, confirming a direct proportion in this range. However, at 4040 and 5050 coils, the number of paperclips lifted plateaus at 1313, indicating that wrapping more than 3030 coils does not produce a proportional increase in magnetic strength.

Adım Adım Çözüm

1
Analyze the student's initial hypothesis.
The hypothesis states that the number of paperclips lifted (representing magnetic field strength) is directly proportional to the number of wire coils. Mathematically, this means the ratio of paperclips to coils should remain constant.
Establishing the mathematical definition of direct proportionality allows us to test it against the data.
2
Calculate the ratio of paperclips lifted to wire coils for each data point in the table.
For 1010 coils, 410=0.4\frac{4}{10} = 0.4. For 2020 coils, 820=0.4\frac{8}{20} = 0.4. For 3030 coils, 1230=0.4\frac{12}{30} = 0.4. For 4040 coils, 1340=0.325\frac{13}{40} = 0.325. For 5050 coils, 1350=0.26\frac{13}{50} = 0.26.
Comparing these ratios identifies where the linear relationship holds and where it breaks down.
3
Identify the trend and determine how to modify the hypothesis.
The ratio is constant at 0.40.4 up to 3030 coils, but it decreases at 4040 and 5050 coils as the average number of paperclips lifted plateaus at 1313. Thus, the direct proportionality is valid only up to 3030 coils, and the hypothesis must be restricted to this range.
A modified scientific hypothesis must align with all observed experimental facts.

Anahtar Kavram

Formulating and Modifying Hypotheses
Soru 60Soru

### Passage

Astrophysicists and astrobiologists simulated Martian surface environments to evaluate the survival and methane (CH4\text{CH}_4) production of the methanogenic archaeon *Methanosarcina barkeri*. Under optimal laboratory conditions, *M. barkeri* is cultured anaerobically in a liquid medium under an atmosphere of 80% H280\%\ \text{H}_2 and 20% CO220\%\ \text{CO}_2 at 37C37^\circ\text{C} (Standard Growth Condition).

In the Martian simulation experiments, the researchers varied three main environmental variables:
1. Atmosphere: Standard Growth atmosphere vs. Simulated Martian Atmosphere (SMA: 95.3% CO295.3\%\ \text{CO}_2, 2.7% N22.7\%\ \text{N}_2, 1.6% Ar1.6\%\ \text{Ar}, and 0.13% O20.13\%\ \text{O}_2).
2. Substrate: No substrate (liquid medium only) vs. Inert quartz sand vs. Simulated Martian Regolith (SMR) containing 1.0% Mg(ClO4)21.0\%\ \text{Mg(ClO}_4)_2 (perchlorate salt, a strong oxidizing agent).
3. Radiation: Shielded (no UV exposure) vs. UV-irradiated (exposure to 200400 nm200\text{--}400\text{ nm} UV flux).

To evaluate the specific effect of each environmental variable on the growth rate and CH4\text{CH}_4 production of *M. barkeri*, the researchers prepared multiple experimental setups. To validate their conclusions, each test setup must be compared against a specific control or baseline setup that isolates the variable of interest.

Match each research goal with the appropriate control or baseline setup needed to isolate the variable of interest.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Identify the control setup to isolate the toxicity of 1.0% Mg(ClO4)21.0\%\ \text{Mg(ClO}_4)_2 when *M. barkeri* is grown on SMR in the simulated Martian atmosphere (SMA) with UV shielding.
Identify the control setup to isolate the effect of UV radiation when *M. barkeri* is grown in liquid medium (no substrate) in the simulated Martian atmosphere (SMA).
Identify the baseline setup to isolate the effect of the simulated Martian atmosphere (SMA) on methane production when *M. barkeri* is grown in liquid medium (no substrate) with UV shielding.

Eşleşmeler

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Cevap

Matching the SMR perchlorate toxicity isolation goal with the inert quartz sand setup in SMA; matching the UV radiation isolation goal in liquid medium with the UV-shielded liquid medium setup in SMA; and matching the SMA atmosphere isolation goal with the Standard Growth atmosphere setup in liquid medium with UV shielding.
The correct matches pair each specific research goal with the control or baseline setup that differs from the test condition by only the single variable being investigated, thereby successfully isolating its effect.

Adım Adım Çözüm

1
Identify the independent variable being tested for each research goal.
For Goal 1, the variable is the presence of perchlorates in the substrate. For Goal 2, the variable is the presence of UV radiation. For Goal 3, the variable is the composition of the atmosphere.
Isolating a variable requires comparing a test setup containing the variable to a control setup that is identical except for that single variable.
2
Determine the control setup for Goal 1 (perchlorate toxicity) by holding other conditions constant.
The test setup has Simulated Martian Regolith (SMR, containing perchlorates) under SMA with UV shielding. The control setup must keep SMA and UV shielding but replace SMR with an inert control substrate (quartz sand), matching the setup cultured on inert quartz sand under SMA with UV shielding.
Replacing the perchlorate-containing SMR with inert quartz sand removes the independent variable (perchlorate toxicity) while maintaining all other physical and atmospheric parameters.
3
Determine the control setup for Goal 2 (UV radiation effects) by keeping substrate and atmosphere constant.
The test setup has liquid medium (no substrate) in SMA with UV irradiation. The control setup must keep liquid medium and SMA but eliminate the UV radiation (UV-shielded), matching the setup cultured in liquid medium under SMA with UV shielding.
UV shielding serves as the baseline to compare against the UV-irradiated setup, isolating the impact of radiation on cell survival.
4
Determine the baseline setup for Goal 3 (SMA atmosphere comparison to standard conditions).
The test setup has liquid medium in SMA with UV shielding. To compare SMA against optimal laboratory conditions, the baseline setup must keep the liquid medium and UV shielding but change the atmosphere to Standard Growth conditions, matching the setup cultured in liquid medium under Standard Growth conditions with UV shielding.
This baseline isolates the general biological effect of the Martian atmosphere gaseous mixture compared to the optimal laboratory gas mixture.

Anahtar Kavram

Identifying proper control groups by keeping all variables constant except for the single independent variable under investigation.
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