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Zorluk: KolayHydrostatic Pressure

A heavy-duty diving bell is being tested in a deep saltwater facility. At a depth of 10 meters10\text{ meters}, the hydrostatic pressure exerted on its exterior is measured to be 100 kilopascals (kPa)100\text{ kilopascals (kPa)}. If the diving bell is lowered further to a depth of 30 meters30\text{ meters}, what will the new hydrostatic pressure be in kPa\text{kPa}, assuming the fluid density remains constant?

Cevap: 300 kPa

Cevap

The new hydrostatic pressure will be 300 kPa.
Because hydrostatic pressure is directly proportional to depth in a fluid of constant density, tripling the depth from 10 meters to 30 meters results in exactly three times the pressure. Thus, 100 kPa multiplied by 3 equals 300 kPa.

Adım Adım Çözüm

1
Identify the relationship between hydrostatic pressure and depth.
Pressure is directly proportional to depth.
This is a fundamental principle of hydrostatic pressure for a fluid with constant density.
2
Calculate the ratio of the new depth to the initial depth.
30 m/10 m=330\text{ m} / 10\text{ m} = 3
This ratio tells us how much the pressure will increase.
3
Calculate the new pressure.
100 kPa×3=300 kPa100\text{ kPa} \times 3 = 300\text{ kPa}
Applying the direct proportion to find the final pressure value.

Anahtar Kavram

Hydrostatic pressure increases in direct proportion to the depth of the fluid, assuming fluid density remains constant.
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Hydrostatic Pressure

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