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Zorluk: OrtaResistors and Potentiometers

A bench technician uses a 100 kΩ100\text{ k}\Omega linear potentiometer as an adjustable control element in a circuit. If the wiper is adjusted to 75%75\% of its full mechanical travel away from the lower reference terminal, what is the resulting resistance between the wiper and the upper terminal in kilo-ohms (kΩ\text{k}\Omega)?

Cevap: 25 k\Omega

Cevap

25 kilo-ohms (25 kΩ25\text{ k}\Omega)
In a linear-taper potentiometer, the total end-to-end resistance (100 kΩ100\text{ k}\Omega) is distributed uniformly across the resistive track between the outer fixed terminals. When the wiper is moved 75%75\% of the travel distance from the lower terminal, the remaining segment between the wiper and the upper terminal comprises 25%25\% (100%−75%100\% - 75\%) of the total resistance. Multiplying 100 kΩ×0.25100\text{ k}\Omega \times 0.25 gives 25 kΩ25\text{ k}\Omega.

Adım Adım Çözüm

1
Find the percentage of the resistive element situated between the wiper contact and the upper terminal.
100%−75%=25%100\% - 75\% = 25\%
The total resistive track spans 100%100\% of the component's resistance between its two outer end terminals.
2
Calculate the resistance across this upper portion of the track.
100 kΩ×0.25=25 kΩ100\text{ k}\Omega \times 0.25 = 25\text{ k}\Omega
Because the potentiometer is linear, resistance is directly proportional to the physical position of the wiper along the track.

Anahtar Kavram

Linear potentiometer terminal division and wiper position relationships

Alternatif Yöntem

Calculate the resistance from the lower terminal to the wiper first (100 kΩ×0.75=75 kΩ100\text{ k}\Omega \times 0.75 = 75\text{ k}\Omega), and subtract that value from the total resistance: 100 kΩ−75 kΩ=25 kΩ100\text{ k}\Omega - 75\text{ k}\Omega = 25\text{ k}\Omega.
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