An avionics technician is analyzing a direct-current (DC) subassembly with an applied volt… — Armed Services Vocational Aptitude Battery (ASVAB)

An avionics technician is analyzing a direct-current (DC) subassembly with an applied voltage of $36\text{ V}$ across a load resistor rated at $1.8\text{ k}\Omega$ . What is the resistance in ohms and the resulting current in milliamperes? Fill in the blanks below to complete the circuit analysis.

Cevap:The total resistance of the load is 【1800】

\Omega

, and the steady current flowing through the circuit is 【20】

\text{mA}

Cevap

The resistance is 1800 Ω and the current is 20 mA.

Converting

1.8\text{ k}\Omega

to base units gives

1800\ \Omega

. Dividing the applied voltage of

36\text{ V}

1800\ \Omega

yields

0.02\text{ A}

, which corresponds to

20\text{ mA}

Adım Adım Çözüm

Convert the load resistance from kilohms (kΩ) to ohms (Ω)

R = 1.8\text{ k}\Omega = 1.8 \times 1000\ \Omega = 1800\ \Omega

Standard electrical calculations using Ohm's Law require base units of ohms, volts, and amperes.

Apply Ohm's Law (

I = \frac{V}{R}

) to calculate the circuit current in amperes

I = \frac{36\text{ V}}{1800\ \Omega} = 0.02\text{ A}

Current is directly proportional to voltage and inversely proportional to resistance.

Convert the current from amperes (A) to milliamperes (mA)

I = 0.02\text{ A} \times 1000\text{ mA/A} = 20\text{ mA}

The required unit for the current blank is milliamperes.

Anahtar Kavram

Ohm's Law (

I = \frac{V}{R}

) and metric prefix conversions (kilo- and milli-).

Tahmini Süre:45s

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