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Zorluk: OrtaOhm's Law Calculations and Concepts

Match each direct current (DC) circuit scenario on the left with its corresponding calculated electrical quantity on the right using Ohm's law (V=I×RV = I \times R).

  • A 120 V120\text{ V} line connected across a load with a resistance of 2.4 kΩ2.4\text{ k}\OmegaResulting current of 50 mA50\text{ mA}
  • A 5 V5\text{ V} logic circuit branch drawing a current of 20 mA20\text{ mA}Circuit resistance of 250 Ω250\text{ }\Omega
  • A current of 400 mA400\text{ mA} flowing through a 50 Ω50\text{ }\Omega heating elementVoltage drop of 20 V20\text{ V}
  • A 36 V36\text{ V} industrial sensor loop carrying a current of 3 mA3\text{ mA}Loop resistance of 12 kΩ12\text{ k}\Omega

Cevap

The 120 V120\text{ V} load with 2.4 kΩ2.4\text{ k}\Omega matches the resulting current of 50 mA50\text{ mA}; the 5 V5\text{ V} circuit drawing 20 mA20\text{ mA} matches the circuit resistance of 250 Ω250\text{ }\Omega; the 400 mA400\text{ mA} current through 50 Ω50\text{ }\Omega matches the voltage drop of 20 V20\text{ V}; and the 36 V36\text{ V} loop carrying 3 mA3\text{ mA} matches the loop resistance of 12 kΩ12\text{ k}\Omega.
Each circuit condition correctly maps to its target electrical parameter by converting metric prefixes (1 kΩ=1000 Ω1\text{ k}\Omega = 1000\text{ }\Omega, 1 mA=0.001 A1\text{ mA} = 0.001\text{ A}) and applying the appropriate algebraic form of Ohm's law: I=VRI = \frac{V}{R}, R=VIR = \frac{V}{I}, and V=I×RV = I \times R.

Adım Adım Çözüm

1
Calculate current for the 120 V120\text{ V}, 2.4 kΩ2.4\text{ k}\Omega circuit
I=120 V2400 Ω=0.05 A=50 mAI = \frac{120\text{ V}}{2400\text{ }\Omega} = 0.05\text{ A} = 50\text{ mA}
Ohm's law states I=VRI = \frac{V}{R}, requiring resistance in fundamental ohms (1 kΩ=1000 Ω1\text{ k}\Omega = 1000\text{ }\Omega).
2
Calculate resistance for the 5 V5\text{ V}, 20 mA20\text{ mA} circuit branch
R=5 V0.02 A=250 ΩR = \frac{5\text{ V}}{0.02\text{ A}} = 250\text{ }\Omega
Rearranging Ohm's law gives R=VIR = \frac{V}{I}, requiring current in amperes (20 mA=0.02 A20\text{ mA} = 0.02\text{ A}).
3
Calculate voltage drop across the 50 Ω50\text{ }\Omega element carrying 400 mA400\text{ mA}
V=0.4 A×50 Ω=20 VV = 0.4\text{ A} \times 50\text{ }\Omega = 20\text{ V}
Ohm's law formula V=I×RV = I \times R computes potential difference when current and resistance are known.
4
Calculate total resistance for the 36 V36\text{ V}, 3 mA3\text{ mA} sensor loop
R=36 V0.003 A=12000 Ω=12 kΩR = \frac{36\text{ V}}{0.003\text{ A}} = 12000\text{ }\Omega = 12\text{ k}\Omega
Applying R=VIR = \frac{V}{I} with 3 mA=0.003 A3\text{ mA} = 0.003\text{ A} yields 12000 Ω12000\text{ }\Omega, or 12 kΩ12\text{ k}\Omega.

Anahtar Kavram

Ohm's law mathematically relates voltage (VV), current (II), and resistance (RR) via V=I×RV = I \times R, I=VRI = \frac{V}{R}, and R=VIR = \frac{V}{I}, requiring consistent base metric units.
Tahmini Süre:1m 15s
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