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Zorluk: OrtaCircuit Faults and Troubleshooting

A technician is troubleshooting a circuit where two identical heating elements, R1R_1 and R2R_2, are connected in series across a 120 V120\text{ V} AC supply. When the circuit is energized, neither element produces heat. Using a digital multimeter set to AC voltage, the technician measures 0 V0\text{ V} across R1R_1 and 120 V120\text{ V} across R2R_2. Based on these measurements, which of the following is the most likely fault in the circuit?

  1. A
    R1R_1 has developed a short circuit.
  2. R2R_2 has developed an open circuit.Cevap
  3. C
    R2R_2 has developed a short circuit.
  4. D
    R1R_1 has developed excessive contact resistance.

Cevap

The heating element R2R_2 has an open circuit.
In a series circuit containing an open fault, the current drops to zero throughout the loop. According to Ohm's Law (V=I×RV = I \times R), any intact component drops 0 V0\text{ V} because no current flows through it. Consequently, the entire source potential of 120 V120\text{ V} appears directly across the terminals of the open element (R2R_2).

Adım Adım Çözüm

1
Analyze current flow in the series circuit based on operating symptoms.
Because neither series element produces heat, the total circuit current is zero (I=0 AI = 0\text{ A}).
In a series circuit, any break in continuity stops current through all components.
2
Apply Ohm's Law to the intact component R1R_1.
VR1=I×R1=0 A×R1=0 VV_{R1} = I \times R_1 = 0\text{ A} \times R_1 = 0\text{ V}.
Without current flow, no potential difference develops across an intact resistor.
3
Evaluate the voltage drop across the faulted component R2R_2.
VR2=120 VV_{R2} = 120\text{ V} (entire supply voltage).
An open component represents infinite resistance, placing the multimeter in series with the line voltage across the open gap, thereby reading full source voltage.

Anahtar Kavram

In a series circuit, an open component prevents current flow through all other components and drops the entire applied source voltage across the open point.
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