An automotive spotlight operates on a 12\text{ V} direct current (DC) electrical system an… — Armed Services Vocational Aptitude Battery (ASVAB)

An automotive spotlight operates on a $12\text{ V}$ direct current (DC) electrical system and draws a steady current of $4\text{ A}$ . How much electrical power is consumed by the spotlight?

A
$3\text{ W}$
$48\text{ W}$ Cevap
C
$16\text{ W}$
D
$192\text{ W}$

Cevap

The power consumed by the spotlight is

48\text{ W}

According to Watt's Law, electrical power (

P

) is determined by multiplying voltage (

V

) by current (

I

), using the formula

P = V \times I

. Substituting

12\text{ V}

and

4\text{ A}

gives

P = 12\text{ V} \times 4\text{ A} = 48\text{ W}

Adım Adım Çözüm

Identify the given electrical values from the problem statement.

Voltage (

V

) =

12\text{ V}

, Current (

I

) =

4\text{ A}

Establishing the known quantities determines which form of Watt's Law to apply.

Select the appropriate Watt's Law power formula relating power, voltage, and current.

P = V \times I

Electrical power in watts equals the product of potential difference in volts and current in amperes.

Substitute the values into the formula and calculate.

P = 12\text{ V} \times 4\text{ A} = 48\text{ W}

Carrying out the multiplication yields the total power dissipated.

Anahtar Kavram

Watt's Law relates electrical power (

P

) to voltage (

V

) and current (

I

) through the formula

P = V \times I

Tahmini Süre:45s

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