Soru

Zorluk: ZorVolume and Surface Area of 3D Figures

Match each description of a 3D solid to its corresponding numerical value for volume or total surface area. (Note: All answers are expressed in terms of π\pi.)

  • Volume of a cylinder with a radius of 22 and a height of 121248π48\pi
  • Volume of a sphere with a diameter of 6636π36\pi
  • Total surface area of a closed cylinder with a radius of 33 and a height of 2230π30\pi
  • Surface area of a sphere with a radius of 4464π64\pi

Cevap

The volume of the cylinder matches 48π48\pi, the volume of the sphere matches 36π36\pi, the total surface area of the cylinder matches 30π30\pi, and the surface area of the sphere matches 64π64\pi.
Each correct numerical value is found by identifying the specified 3D solid, recalling its corresponding volume or surface area formula, and accurately substituting the given dimensions into the formula.

Adım Adım Çözüm

1
Calculate the volume of the cylinder.
V=π(22)(12)=48πV = \pi(2^2)(12) = 48\pi
Apply the cylinder volume formula V=πr2hV = \pi r^2 h.
2
Calculate the volume of the sphere.
Radius is 33. V=43π(33)=36πV = \frac{4}{3}\pi(3^3) = 36\pi
Convert diameter to radius, then apply the sphere volume formula V=43πr3V = \frac{4}{3}\pi r^3.
3
Calculate the total surface area of the closed cylinder.
SA=2π(32)+2π(3)(2)=30πSA = 2\pi(3^2) + 2\pi(3)(2) = 30\pi
Apply the cylinder total surface area formula SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh.
4
Calculate the surface area of the sphere.
SA=4π(42)=64πSA = 4\pi(4^2) = 64\pi
Apply the sphere surface area formula SA=4πr2SA = 4\pi r^2.

Anahtar Kavram

Applying appropriate volume and surface area formulas for cylinders and spheres.
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