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Zorluk: KolayOhm's Law

An electronics technician is testing an aircraft panel indicator circuit. When connected to a 24 V24\text{ V} DC power supply, the circuit draws a steady current of 4 A4\text{ A}. What is the resistance of the circuit, and what current will flow if the supply voltage is reduced to 12 V12\text{ V}?

Cevap:According to Ohm's Law, the resistance of the circuit is 【6】 Ω\Omega, and when the voltage is decreased to 12 V12\text{ V}, the new current drawn by the circuit is 【2】 A\text{A}.

Cevap

The resistance of the circuit is 6 Ω6\ \Omega and the current under the reduced voltage is 2 A2\text{ A}.
Applying Ohm's Law, the resistance is found by dividing the initial voltage by the initial current (R=24 V4 A=6 ΩR = \frac{24\text{ V}}{4\text{ A}} = 6\ \Omega). Keeping this resistance constant, halving the voltage to 12 V12\text{ V} results in half the current (I=12 V6 Ω=2 AI = \frac{12\text{ V}}{6\ \Omega} = 2\text{ A}).

Adım Adım Çözüm

1
Calculate the circuit resistance using Ohm's Law with the initial parameters (V1=24 VV_1 = 24\text{ V}, I1=4 AI_1 = 4\text{ A}).
R=V1I1=24 V4 A=6 ΩR = \frac{V_1}{I_1} = \frac{24\text{ V}}{4\text{ A}} = 6\ \Omega
Ohm's Law states that resistance equals voltage divided by current (R=VIR = \frac{V}{I}).
2
Determine the new current when the voltage is adjusted to V2=12 VV_2 = 12\text{ V} across the constant 6 Ω6\ \Omega resistance.
I2=V2R=12 V6 Ω=2 AI_2 = \frac{V_2}{R} = \frac{12\text{ V}}{6\ \Omega} = 2\text{ A}
Current is directly proportional to voltage for a fixed resistance (I=VRI = \frac{V}{R}).

Anahtar Kavram

Ohm's Law expresses the fundamental relationship among voltage, current, and resistance: V=I×RV = I \times R, I=VRI = \frac{V}{R}, and R=VIR = \frac{V}{I}.
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Ohm's Law

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