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Zorluk: OrtaLoad Distribution and Balancing

An irregularly shaped 300300-pound machine casing is 1010 feet long. For maintenance, it is suspended horizontally by two vertical chains, one attached at the extreme left end and one at the extreme right end. The casing's center of gravity is located 22 feet from the left end.

How much weight is supported by the right chain?

  1. 6060 poundsCevap
  2. B
    7575 pounds
  3. C
    150150 pounds
  4. D
    240240 pounds

Cevap

6060 pounds
Because the center of gravity is offset, the weight is not distributed equally. By using the left end as a pivot point, we can balance the torques. The weight of the casing creates a downward torque of 300 lbs×2 ft=600 ft-lbs300 \text{ lbs} \times 2 \text{ ft} = 600 \text{ ft-lbs}. The right chain, pulling upward at a distance of 1010 feet, must create an equal opposite torque. Therefore, Fright×10 ft=600 ft-lbsF_{right} \times 10 \text{ ft} = 600 \text{ ft-lbs}, which means the right chain supports 6060 pounds.

Adım Adım Çözüm

1
Choose a pivot point to set up a torque equation.
Using the left end (where the left chain is attached) as the pivot eliminates the left chain's unknown force from the calculation.
In static equilibrium, the sum of torques around any point must be zero. Choosing one support as the pivot makes it easier to solve for the other support.
2
Calculate the downward torque generated by the casing's weight.
The downward torque is the weight (300300 pounds) multiplied by its distance from the left pivot (22 feet): 300×2=600300 \times 2 = 600 foot-pounds.
Torque is Force multiplied by Distance from the fulcrum.
3
Set the downward torque equal to the upward torque generated by the right chain and solve.
The upward torque is the unknown force of the right chain (FrightF_{right}) multiplied by its distance from the pivot (1010 feet). So, Fright×10=600F_{right} \times 10 = 600. Dividing both sides by 1010 gives Fright=60F_{right} = 60 pounds.
Upward torque must equal downward torque for the casing to remain balanced horizontally.

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Load Distribution and Balancing
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