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Zorluk: ZorSolving One-Variable Inequalities

Which of the following represents the correct solution set for the inequality below?

4(x−3)−3(2x+5)≥x−124(x - 3) - 3(2x + 5) \geq x - 12
  1. x≤−5x \leq -5Cevap
  2. B
    x≥−5x \geq -5
  3. C
    x≤5x \leq 5
  4. D
    x≥5x \geq 5

Cevap

The correct solution is x≤−5x \leq -5.
The correct answer is derived by carefully distributing the values across the parentheses (yielding 4x−12−6x−15≥x−124x - 12 - 6x - 15 \geq x - 12), combining the like terms to form −2x−27≥x−12-2x - 27 \geq x - 12, and isolating xx to get −3x≥15-3x \geq 15. Crucially, dividing both sides by −3-3 requires reversing the direction of the inequality, which correctly results in x≤−5x \leq -5.

Adım Adım Çözüm

1
Distribute the coefficients outside the parentheses into the terms inside.
4x−12−6x−15≥x−124x - 12 - 6x - 15 \geq x - 12
This removes the parentheses. Care must be taken to multiply -3 by +5 correctly to get -15.
2
Combine the like terms on the left side of the inequality.
−2x−27≥x−12-2x - 27 \geq x - 12
Simplifying both sides makes it easier to isolate the variable.
3
Move all terms containing xx to one side and all constant terms to the other side.
−3x≥15-3x \geq 15
Subtracting xx from both sides gives −3x-3x, and adding 2727 to both sides gives 1515.
4
Divide both sides by -3 and reverse the inequality symbol.
x≤−5x \leq -5
Whenever you multiply or divide an inequality by a negative number, the direction of the inequality sign must be flipped to maintain a true mathematical statement.

Anahtar Kavram

Solving multi-step linear inequalities involving distribution and the inequality sign flip rule.
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