A maintenance worker uses a rigid steel bar to lift one edge of a heavy generator. The fulcrum is positioned at the far end of the bar, and the worker applies an upward force at the opposite end. If the weight of the generator applies a downward force of at a point exactly from the fulcrum, how much upward effort force (in pounds) must the worker apply to maintain static equilibrium?
Cevap: 64 pounds
Cevap
64 pounds
The problem describes a second-class lever setup where the fulcrum is at one end, the effort is at the opposite end, and the resistance (load) is located between them. According to the principle of moments (law of the lever), the system is in static equilibrium when the effort torque equals the resistance torque (). The effort arm length is the total length of the bar (), and the resistance arm length is the distance from the pivot to the load (). Substituting the values gives , which simplifies to . Dividing both sides by 50 yields an effort force of .
Adım Adım Çözüm
Anahtar Kavram
The Law of the Lever (Torque Balance)