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Zorluk: OrtaScale Drawings and Map Measurements

Calculate the actual length of the property line based on the given scale and enter the exact numerical value.

Cevap:A city surveyor is examining a property deed map that uses a scale of 112 inches=40 feet1\frac{1}{2}\text{ inches} = 40\text{ feet}. If the eastern boundary line measures 514 inches5\frac{1}{4}\text{ inches} on this map, the actual length of the boundary line is 【140】 feet.

Cevap

140
The correct answer is found by setting up a direct proportion based on the scale: 1.5 inches40 feet=5.25 inchesx feet\frac{1.5\text{ inches}}{40\text{ feet}} = \frac{5.25\text{ inches}}{x\text{ feet}}. Cross-multiplying gives 1.5x=2101.5x = 210, and dividing by 1.51.5 gives an actual length of 140140 feet.

Adım Adım Çözüm

1
Convert the mixed fractions into decimals for easier algebraic calculation.
The map scale is 1.5 inches=40 feet1.5\text{ inches} = 40\text{ feet}. The measured boundary is 5.25 inches5.25\text{ inches}.
Working with decimals simplifies the process of setting up and solving a proportion.
2
Set up a direct proportion comparing the map distance to the actual distance.
1.5 inches40 feet=5.25 inchesx feet\frac{1.5\text{ inches}}{40\text{ feet}} = \frac{5.25\text{ inches}}{x\text{ feet}}
A map's scale establishes a consistent ratio between the dimensions on the drawing and the true physical dimensions.
3
Cross-multiply the terms to isolate the unknown variable xx.
1.5x=40×5.251.5x = 40 \times 5.25
Cross-multiplication transforms the proportion into a linear equation that is easy to solve.
4
Multiply the values on the right side of the equation.
40×5.25=21040 \times 5.25 = 210
Simplifying the right side to 210210 leaves a basic one-step algebraic equation: 1.5x=2101.5x = 210.
5
Divide both sides by 1.51.5 to solve for xx.
x=2101.5=140x = \frac{210}{1.5} = 140
Dividing by the coefficient isolates xx, revealing the actual length of the boundary line in feet.

Anahtar Kavram

Using proportional reasoning and cross-multiplication to convert map measurements to real-world distances.
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