Examkin

Soru

Zorluk: OrtaPascal's Principle and Hydraulics

Match each modification made to a standard closed hydraulic lift system with its resulting effect on the output piston. Assume the applied input force remains constant unless otherwise specified.

  • Doubling the cross-sectional area of the output piston onlyOutput lifting force doubles, but output travel distance is halved.
  • Doubling the cross-sectional area of the input piston onlyOutput lifting force is halved, but output travel distance doubles.
  • Doubling the cross-sectional area of both pistons equallyOutput lifting force and output travel distance remain unchanged.
  • Doubling the travel distance of the input pistonOutput lifting force remains unchanged, but output travel distance doubles.

Cevap

Modifications changing the area ratio affect force and distance inversely; proportional area modifications maintain the status quo; and input distance modifications only affect output distance.
Each correct match applies Pascal's Principle (F2=F1×A2A1F_2 = F_1 \times \frac{A_2}{A_1}) and the principle of work conservation (F1×d1=F2×d2F_1 \times d_1 = F_2 \times d_2). Changing the area ratio inversely affects force and distance. Changing only input distance affects fluid volume displaced, altering output distance without changing force.

Adım Adım Çözüm

1
Analyze modifications changing a single piston area.
Doubling output area doubles force but halves distance; doubling input area halves force but doubles distance.
Pascal's principle states F2=F1×A2A1F_2 = F_1 \times \frac{A_2}{A_1}, and conservation of work states d2=d1×A1A2d_2 = d_1 \times \frac{A_1}{A_2}.
2
Analyze modifications changing both piston areas.
Doubling both areas keeps the ratio A2/A1A_2/A_1 constant, resulting in no change to force or distance.
The mechanical advantage depends strictly on the ratio of the areas, not their absolute sizes.
3
Analyze modifications changing only input distance.
Doubling input distance doubles output distance without affecting force.
Volume displaced (V=A1×d1V = A_1 \times d_1) doubles, so output distance doubles. Force depends only on the area ratio, which is unchanged.

Anahtar Kavram

Pascal's Principle and Conservation of Energy in Hydraulics
Bu soruyu puanla

Konular

Pascal's Principle and Hydraulics

Bu konudan daha fazla soru