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Zorluk: OrtaEvaluating Algebraic Expressions

Calculate the result of the following algebraic fraction when x=−2x = -2 and y=2y = 2.

Cevap:The evaluated value of the expression 4x3+2y2x−y\frac{4x^3 + 2y^2}{x - y} is 【6】.

Cevap

6
The correct answer is 6 because substituting the values x=−2x = -2 and y=2y = 2 into the expression yields a numerator of −24-24 and a denominator of −4-4. Dividing a negative by a negative results in a positive 6.

Adım Adım Çözüm

1
Substitute the given values for xx and yy into the expression.
4(−2)3+2(2)2−2−2\frac{4(-2)^3 + 2(2)^2}{-2 - 2}
Variable substitution is the first required step in evaluating any algebraic expression.
2
Evaluate the terms with exponents in the numerator.
(−2)3=−8(-2)^3 = -8 and 22=42^2 = 4
According to the order of operations (PEMDAS), exponents must be resolved before multiplication.
3
Perform the multiplication operations in the numerator.
4(−8)=−324(-8) = -32 and 2(4)=82(4) = 8
Multiplication is performed after exponents.
4
Add the resulting terms in the numerator and subtract the terms in the denominator.
Numerator: −32+8=−24-32 + 8 = -24. Denominator: −2−2=−4-2 - 2 = -4.
Simplify the numerator and denominator completely before dividing.
5
Divide the simplified numerator by the simplified denominator.
−24−4=6\frac{-24}{-4} = 6
Dividing a negative number by a negative number results in a positive quotient.

Anahtar Kavram

Evaluating algebraic expressions with negative integers and exponents
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