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Zorluk: ZorPascal's Principle and Hydraulics

In a specialized heavy-duty hydraulic system, the master cylinder has a piston diameter of 2 cm2 \text{ cm} and the lifting cylinder has a piston diameter of 10 cm10 \text{ cm}. If the master cylinder piston is pushed through a total stroke distance of 75 cm75 \text{ cm}, how far, in cm, will the lifting cylinder piston move?

Cevap: 3 cm

Cevap

3
In a closed hydraulic system, the volume of fluid displaced by the input piston must equal the volume of fluid that moves the output piston. Because volume is the product of the piston's cross-sectional area and its stroke distance (V=A×dV = A \times d), and area is proportional to the square of the diameter (A∝D2A \propto D^2), the distance moved is inversely proportional to the square of the diameter. The lifting cylinder has a diameter 55 times larger than the master cylinder (10/2=510 / 2 = 5), which means its area is 2525 times larger (52=255^2 = 25). Therefore, to conserve fluid volume, the lifting piston will move 1/251/25 of the distance of the master piston. Dividing the master piston's distance of 75 cm75 \text{ cm} by 2525 gives an output distance of 3 cm3 \text{ cm}.

Adım Adım Çözüm

1
State the principle of volume conservation for incompressible fluids.
Vin=VoutV_{in} = V_{out}
In a closed hydraulic system, the volume of fluid pushed by the input piston must equal the volume displacing the output piston.
2
Express volume in terms of piston diameter and stroke distance.
V∝D2×dV \propto D^2 \times d
Volume equals cross-sectional area times distance, and area is proportional to the square of the diameter.
3
Set up the equation using the given values.
22×75=102×dout2^2 \times 75 = 10^2 \times d_{out}
Substituting Din=2D_{in} = 2, din=75d_{in} = 75, and Dout=10D_{out} = 10 allows us to solve for the unknown output distance.
4
Simplify and solve for the output distance.
300=100×dout→dout=3300 = 100 \times d_{out} \rightarrow d_{out} = 3
Basic algebra isolates the variable to find the final distance.

Anahtar Kavram

Hydraulic volumetric conservation and area-distance tradeoffs
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