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Zorluk: KolayNewton's Second Law (F=ma)

A naval torpedo with a mass of 1,200 kg1,200 \text{ kg} is fired from a submarine. If the propulsion system generates a constant net forward force of 6,000 N6,000 \text{ N}, what is the forward acceleration of the torpedo?

  1. A
    0.2 m/s20.2 \text{ m/s}^2
  2. B
    0.5 m/s20.5 \text{ m/s}^2
  3. 5.0 m/s25.0 \text{ m/s}^2Cevap
  4. D
    50.0 m/s250.0 \text{ m/s}^2

Cevap

The correct answer is 5.0 m/s25.0 \text{ m/s}^2.
According to Newton's Second Law (F=maF = ma), acceleration is calculated by dividing the net force by the mass. Dividing 6,000 N6,000 \text{ N} by 1,200 kg1,200 \text{ kg} yields 5.0 m/s25.0 \text{ m/s}^2.

Adım Adım Çözüm

1
Identify the given values from the problem statement.
Mass (mm) = 1,200 kg1,200 \text{ kg}, Net Force (FF) = 6,000 N6,000 \text{ N}.
Extracting the known variables is necessary to apply the correct physics formula.
2
Apply Newton's Second Law of Motion.
The formula is F=maF = ma. Rearranging to solve for acceleration gives a=Fma = \frac{F}{m}.
Newton's Second Law relates force, mass, and acceleration.
3
Substitute the values into the formula and solve.
a=60001200=5.0 m/s2a = \frac{6000}{1200} = 5.0 \text{ m/s}^2.
Dividing the net force by the mass computes the resulting acceleration.

Anahtar Kavram

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass (F=maF = ma).
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Konular

Newton's Second Law (F=ma)

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