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Zorluk: KolayOhm's Law

A technician measures a steady current of 50 mA50\text{ mA} flowing through a 120 Ω120\ \Omega fixed resistor in a signal conditioning module. What is the voltage drop across the resistor?

  1. A
    2.4 V2.4\text{ V}
  2. 6 V6\text{ V}Cevap
  3. C
    6000 V6{}000\text{ V}
  4. D
    0.6 V0.6\text{ V}

Cevap

6 V6\text{ V}
According to Ohm's law, the voltage drop across a component is determined by multiplying current by resistance (V=I×RV = I \times R). Converting 50 mA50\text{ mA} to 0.05 A0.05\text{ A} and multiplying by 120 Ω120\ \Omega gives 6 V6\text{ V}.

Adım Adım Çözüm

1
Convert the current from milliamperes (mA) to amperes (A).
50 mA=0.05 A50\text{ mA} = 0.05\text{ A}
Standard electrical formulas require current in amperes.
2
Apply Ohm's law formula for voltage (V=I×RV = I \times R).
V=0.05 A×120 Ω=6 VV = 0.05\text{ A} \times 120\ \Omega = 6\text{ V}
Voltage across a resistor equals the product of current and resistance.

Anahtar Kavram

Ohm's Law states that voltage is equal to current multiplied by resistance (V=I×RV = I \times R).
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Ohm's Law

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