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Zorluk: OrtaOhm's Law Calculations and Concepts

An automotive technician tests a fuel level sensor module connected to a 12 V12\text{ V} direct current (DC) supply. An in-line digital multimeter measures a steady current flow of 15 mA15\text{ mA} through the module. What is the electrical resistance of the sensor module?

  1. A
    0.8 Ω0.8\text{ }\Omega
  2. B
    1.25 Ω1.25\text{ }\Omega
  3. 800 Ω800\text{ }\OmegaCevap
  4. D
    180 Ω180\text{ }\Omega

Cevap

The electrical resistance of the sensor module is 800 Ω800\text{ }\Omega.
According to Ohm's law, resistance equals voltage divided by current (R=VIR = \frac{V}{I}). Converting 15 mA15\text{ mA} to amperes gives 0.015 A0.015\text{ A}. Dividing 12 V12\text{ V} by 0.015 A0.015\text{ A} yields 800 Ω800\text{ }\Omega.

Adım Adım Çözüm

1
Convert the measured current from milliamperes (mA) to the base SI unit amperes (A).
I=15 mA=15×10−3 A=0.015 AI = 15\text{ mA} = 15 \times 10^{-3}\text{ A} = 0.015\text{ A}
Standard electrical formulas require quantities in base units (volts, amperes, ohms).
2
State Ohm's law rearranged to solve for resistance (RR).
R=VIR = \frac{V}{I}
Resistance equals electromotive force (voltage) divided by current flow.
3
Substitute the given values into the formula and calculate the resistance.
R=12 V0.015 A=1200015 Ω=800 ΩR = \frac{12\text{ V}}{0.015\text{ A}} = \frac{12000}{15}\text{ }\Omega = 800\text{ }\Omega
Dividing 12 V12\text{ V} by 0.015 A0.015\text{ A} yields the total circuit resistance in ohms.

Anahtar Kavram

Ohm's Law (V=I×RV = I \times R) defines the relationship between voltage, current, and resistance in a DC circuit.
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Ohm's Law Calculations and Concepts

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