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Zorluk: OrtaVoltage and Electromotive Force (EMF)

A portable emergency radio beacon uses a power source consisting of three series-connected DC cells: a primary lithium cell with an electromotive force (EMF) of 3.6 V3.6\text{ V}, a standard cell with an EMF of 1.5 V1.5\text{ V}, and a photovoltaic booster cell with an EMF of 0.9 V0.9\text{ V}. When all three cells are wired in a series-aiding configuration, what is the total electromotive force supplied to the beacon?

  1. A
    3.6 V3.6\text{ V}
  2. 6.0 V6.0\text{ V}Cevap
  3. C
    6.0 A6.0\text{ A}
  4. D
    1.2 V1.2\text{ V}

Cevap

The total electromotive force supplied to the beacon is 6.0 V6.0\text{ V}.
When multiple direct-current sources are connected in a series-aiding configuration, their individual electromotive forces (EMFs) add algebraically. Summing the three cell ratings gives 3.6 V+1.5 V+0.9 V=6.0 V3.6\text{ V} + 1.5\text{ V} + 0.9\text{ V} = 6.0\text{ V}.

Adım Adım Çözüm

1
Identify the individual electromotive force (EMF) values of the series-connected sources.
E1=3.6 VE_1 = 3.6\text{ V}, E2=1.5 VE_2 = 1.5\text{ V}, and E3=0.9 VE_3 = 0.9\text{ V}.
Extracting the component voltages is necessary to determine the overall potential difference across the power source.
2
Apply the rule for DC voltage sources connected in series-aiding polarity (Etotal=E1+E2+E3E_{\text{total}} = E_1 + E_2 + E_3).
Etotal=3.6 V+1.5 V+0.9 V=6.0 VE_{\text{total}} = 3.6\text{ V} + 1.5\text{ V} + 0.9\text{ V} = 6.0\text{ V}.
When cells are wired series-aiding (positive terminal of one cell connected to the negative terminal of the next), their individual electromotive forces combine additively.

Anahtar Kavram

Series-Aiding Electromotive Force (EMF) Summation
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