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Zorluk: OrtaGenetics and Heredity

In guinea pigs, the allele for black fur (BB) is dominant over the allele for white fur (bb). If two heterozygous (BbBb) guinea pigs mate, what percentage of their offspring is expected to have white fur?

  1. A
    75%75\%
  2. B
    50%50\%
  3. 25%25\%Cevap
  4. D
    0%0\%

Cevap

25%25\% of the offspring are expected to have white fur.
In a cross between two heterozygous parents (Bb×BbBb \times Bb), each parent contributes a recessive allele (bb) with a probability of 12\frac{1}{2}. The probability of producing a homozygous recessive offspring (bbbb) is 12×12=14\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}, or 25%25\%. Since white fur is recessive, only the bbbb genotype displays white fur.

Adım Adım Çözüm

1
Determine the parental genotypes and possible gametes.
Both parents have the heterozygous genotype BbBb, producing gametes carrying either allele BB or allele bb with equal probability.
Heterozygous organisms possess one dominant allele and one recessive allele for a given gene.
2
Construct a Punnett square to determine all possible offspring genotypes.
The resulting genotypic ratio is 1 BB1\ BB (25%25\%), 2 Bb2\ Bb (50%50\%), and 1 bb1\ bb (25%25\%).
Mendel's Law of Segregation states that allele pairs separate during gamete formation and recombine randomly at fertilization.
3
Determine the phenotype associated with white fur.
Only the homozygous recessive genotype (bbbb) results in white fur, representing 11 out of 44 combinations (25%25\%).
Because the black fur allele (BB) is dominant, any individual with at least one BB allele (BBBB or BbBb) will display black fur.

Anahtar Kavram

Monohybrid cross phenotypic and genotypic ratios in Mendelian inheritance
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