Soru

Zorluk: OrtaFactoring Polynomials

Pair the given polynomial expressions on the left with their fully factored equivalents on the right.

  • 4x2−254x^2 - 25(2x−5)(2x+5)(2x - 5)(2x + 5)
  • x2−8x+15x^2 - 8x + 15(x−3)(x−5)(x - 3)(x - 5)
  • 3x2+12x−153x^2 + 12x - 153(x+5)(x−1)3(x + 5)(x - 1)
  • 2x3−8x2x^3 - 8x2x(x−2)(x+2)2x(x - 2)(x + 2)

Cevap

The correct pairings are: 4x2−254x^2 - 25 with (2x−5)(2x+5)(2x - 5)(2x + 5); x2−8x+15x^2 - 8x + 15 with (x−3)(x−5)(x - 3)(x - 5); 3x2+12x−153x^2 + 12x - 15 with 3(x+5)(x−1)3(x + 5)(x - 1); and 2x3−8x2x^3 - 8x with 2x(x−2)(x+2)2x(x - 2)(x + 2).
Each polynomial expression was broken down into its fundamental algebraic components by identifying patterns such as the difference of squares, standard trinomial factoring, and extracting the greatest common factor.

Adım Adım Çözüm

1
Analyze the first expression 4x2−254x^2 - 25.
It factors to (2x−5)(2x+5)(2x - 5)(2x + 5).
It follows the difference of squares pattern a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b) with a=2xa = 2x and b=5b = 5.
2
Analyze the second expression x2−8x+15x^2 - 8x + 15.
It factors to (x−3)(x−5)(x - 3)(x - 5).
The constant term is positive and the middle coefficient is negative, so both factors must contain negative constants that multiply to 1515 and add to −8-8.
3
Analyze the third expression 3x2+12x−153x^2 + 12x - 15.
It factors to 3(x+5)(x−1)3(x + 5)(x - 1).
Factoring out the GCF of 33 gives 3(x2+4x−5)3(x^2 + 4x - 5). The resulting quadratic factors into binomials with constants 55 and −1-1.
4
Analyze the fourth expression 2x3−8x2x^3 - 8x.
It factors to 2x(x−2)(x+2)2x(x - 2)(x + 2).
Factoring out the GCF of 2x2x gives 2x(x2−4)2x(x^2 - 4). The expression x2−4x^2 - 4 is a difference of squares that further factors into (x−2)(x+2)(x - 2)(x + 2).

Anahtar Kavram

Factoring Polynomials
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