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Zorluk: OrtaElectrical Current and Electron Flow

A continuous direct-current (DC) power feed delivers a steady current of 5 amperes5\text{ amperes} through a heavy-duty copper busbar. Which statement correctly describes the physical flow of charge representing this 5 A5\text{ A} current?

  1. A
    An electromotive force of five volts is continuously exerted across the length of the busbar.
  2. Five coulombs of electric charge pass through a cross-section of the busbar each second.Cevap
  3. C
    Five coulombs of positive charge carriers travel from the negative terminal toward the positive terminal every minute.
  4. D
    Five alternating oscillations of charge direction occur back and forth along the busbar each second.

Cevap

Five coulombs of electric charge pass through a cross-section of the busbar each second.
Electric current (II) measures the rate at which charge passes through a conductor. One ampere (1 A1\text{ A}) is defined as one coulomb (1 C1\text{ C}) of electrical charge passing through a cross-sectional area in one second (1 s1\text{ s}). Therefore, a steady current of 5 A5\text{ A} means that 5 coulombs5\text{ coulombs} of charge pass through the cross-section of the busbar every second.

Adım Adım Çözüm

1
Identify the fundamental definition of electric current and its standard unit.
Current (II) is defined as the rate of transfer of electric charge (QQ) per unit of time (tt), expressed by the formula I=QtI = \frac{Q}{t}.
The ampere is the base SI unit of electrical current, defined as one coulomb of charge passing a point per second (1 A=1 C/s1\text{ A} = 1\text{ C/s}).
2
Apply the given current value of 5 A5\text{ A} to the rate formula.
I=5 A=5 coulombs1 secondI = 5\text{ A} = \frac{5\text{ coulombs}}{1\text{ second}}.
A steady current of 5 A5\text{ A} directly translates to a charge flow rate of 5 coulombs per second5\text{ coulombs per second} through the conductor.

Anahtar Kavram

Electric current is the time rate of charge flow through a conductor, where one ampere equals one coulomb per second (I=Q/tI = Q/t).
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