Soru

Zorluk: ZorPascal's Principle and Hydraulics

A mechanical engineer is testing a hydraulic actuation system. The standard baseline configuration features an input piston with an area of 2 in22 \text{ in}^2, an output piston with an area of 20 in220 \text{ in}^2, an applied input force of 50 lbs50 \text{ lbs}, and an input stroke distance of 12 in12 \text{ in}. Match each experimental setup below to its resulting output force and output travel distance.

  • Input area is increased to 4 in24 \text{ in}^2 (all other baseline parameters unchanged)250 lbs250 \text{ lbs} output force; 2.4 in2.4 \text{ in} travel distance
  • Output area is increased to 60 in260 \text{ in}^2 (all other baseline parameters unchanged)1500 lbs1500 \text{ lbs} output force; 0.4 in0.4 \text{ in} travel distance
  • Input force is increased to 100 lbs100 \text{ lbs} and input stroke is reduced to 6 in6 \text{ in} (areas unchanged)1000 lbs1000 \text{ lbs} output force; 0.6 in0.6 \text{ in} travel distance
  • Both input and output areas are tripled to 6 in26 \text{ in}^2 and 60 in260 \text{ in}^2 respectively500 lbs500 \text{ lbs} output force; 1.2 in1.2 \text{ in} travel distance

Cevap

Each setup modifies the mechanical advantage or the input parameters, requiring independent calculations for output force (Fout=Fin×MAF_{out} = F_{in} \times \text{MA}) and output distance (dout=din/MAd_{out} = d_{in} / \text{MA}).
Correct pairings are achieved by systematically calculating the ratio of the new areas (MA), multiplying the corresponding input force by this ratio, and dividing the corresponding input stroke by this ratio. This ensures Pascal's Principle and the conservation of volume are strictly followed.

Adım Adım Çözüm

1
Calculate the Mechanical Advantage (MA) for each experimental setup.
MA is found by dividing the output area by the input area (Aout/AinA_{out} / A_{in}). Setup 1: 20/4=520/4=5; Setup 2: 60/2=3060/2=30; Setup 3: 20/2=1020/2=10; Setup 4: 60/6=1060/6=10.
MA dictates the multiplier for force and the divisor for distance.
2
Determine the resulting output force for each setup.
Multiply the applied input force by the MA. Setup 1: 50×5=250 lbs50 \times 5 = 250 \text{ lbs}; Setup 2: 50×30=1500 lbs50 \times 30 = 1500 \text{ lbs}; Setup 3: 100×10=1000 lbs100 \times 10 = 1000 \text{ lbs}; Setup 4: 50×10=500 lbs50 \times 10 = 500 \text{ lbs}.
According to Pascal's Principle, pressure is transmitted equally, so force scales proportionally with area.
3
Determine the resulting output travel distance for each setup.
Divide the input stroke distance by the MA. Setup 1: 12/5=2.4 in12 / 5 = 2.4 \text{ in}; Setup 2: 12/30=0.4 in12 / 30 = 0.4 \text{ in}; Setup 3: 6/10=0.6 in6 / 10 = 0.6 \text{ in}; Setup 4: 12/10=1.2 in12 / 10 = 1.2 \text{ in}.
Because the fluid is incompressible, work and volume are conserved; travel distance scales inversely to force.

Anahtar Kavram

In hydraulics, Mechanical Advantage (MA) equals the ratio of output to input areas. Output force is multiplied by MA, while output travel distance is divided by MA to conserve work.
Bu soruyu puanla