Soru

Zorluk: OrtaResistors and Potentiometers

A rotary potentiometer has a total resistance of 50 kΩ50\text{ k}\Omega across its two outer fixed terminals (Terminals A and C). If the center wiper (Terminal B) is adjusted so that the resistance between Terminal A and Terminal B is 32 kΩ32\text{ k}\Omega, what is the resistance between Terminal B and Terminal C?

  1. A
    32 kΩ32\text{ k}\Omega
  2. 18 kΩ18\text{ k}\OmegaCevap
  3. C
    82 kΩ82\text{ k}\Omega
  4. D
    1.8 kΩ1.8\text{ k}\Omega

Cevap

The resistance between Terminal B and Terminal C is 18 kΩ18\text{ k}\Omega.
A potentiometer contains a single continuous resistive track between its two outer terminals (AA and CC). The center wiper (BB) contacts this track at an intermediate point, splitting the total resistance into two complementary series sections such that RAC=RAB+RBCR_{AC} = R_{AB} + R_{BC}. Given a total resistance of 50 kΩ50\text{ k}\Omega and a segment of 32 kΩ32\text{ k}\Omega, the remaining segment between the wiper and the other outer terminal must be 50 kΩ−32 kΩ=18 kΩ50\text{ k}\Omega - 32\text{ k}\Omega = 18\text{ k}\Omega.

Adım Adım Çözüm

1
Identify the relationship between the three terminals of a potentiometer.
The total resistance between outer terminals A and C equals the sum of the two sub-segments created by wiper B: RAC=RAB+RBCR_{AC} = R_{AB} + R_{BC}.
A potentiometer consists of a single continuous resistive element where the movable wiper divides the total track into two series-connected resistive portions.
2
Subtract the known segment resistance from the total end-to-end resistance to find RBCR_{BC}.
RBC=50 kΩ−32 kΩ=18 kΩR_{BC} = 50\text{ k}\Omega - 32\text{ k}\Omega = 18\text{ k}\Omega.
Isolating RBCR_{BC} algebraically provides the remaining resistance along the element to the opposite outer terminal.

Anahtar Kavram

Potentiometer resistive track division
Tahmini Süre:45s
Bu soruyu puanla