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Zorluk: KolayNewton's Second Law (F=ma)

During a manufacturing process, a pneumatic pusher applies a constant net horizontal force of 300 N300 \text{ N} to slide a steel component across a frictionless track. If the component accelerates at 15 m/s215 \text{ m/s}^2, what is the mass of the steel component?

  1. 20 kg20 \text{ kg}Cevap
  2. B
    30 kg30 \text{ kg}
  3. C
    315 kg315 \text{ kg}
  4. D
    4,500 kg4,500 \text{ kg}

Cevap

20 kg20 \text{ kg}
According to Newton's Second Law of Motion, the net force on an object is equal to its mass times its acceleration (F=maF = ma). To find the mass when both force and acceleration are known, the formula must be rearranged to divide the net force by the acceleration (m=Fam = \frac{F}{a}). Dividing the given 300 N300 \text{ N} by 15 m/s215 \text{ m/s}^2 yields a mass of 20 kg20 \text{ kg}.

Adım Adım Çözüm

1
Identify the given variables provided in the scenario.
Force (FF) = 300 N300 \text{ N}, Acceleration (aa) = 15 m/s215 \text{ m/s}^2.
Establishing the known physical quantities is required before selecting and applying the correct formula.
2
State Newton's Second Law of Motion and rearrange it algebraically to solve for mass.
The formula F=maF = ma becomes m=Fam = \frac{F}{a}.
The question asks for the mass of the component, so the standard equation must be isolated for the variable mm.
3
Substitute the known values into the rearranged equation and calculate the final result.
m=30015=20 kgm = \frac{300}{15} = 20 \text{ kg}.
Provides the final mass of the steel component based on the applied force and resulting acceleration.

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Newton's Second Law (F=maF=ma)
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Newton's Second Law (F=ma)

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