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An electronics technician is assembling an energy-storage circuit for an industrial sensor module. The circuit consists of two 100 μF100\text{ }\mu\text{F} capacitors connected in series, and this entire combination is wired in parallel with a single 150 μF150\text{ }\mu\text{F} capacitor. What is the total equivalent capacitance of this circuit in microfarads (μF\mu\text{F})?

Cevap: 200 $\mu\text{F}$

Cevap

The total equivalent capacitance of the circuit is 200 μF200\text{ }\mu\text{F}.
For capacitors in series, total capacitance decreases and is calculated as 1Cseries=1100 μF+1100 μF=2100 μF\frac{1}{C_{\text{series}}} = \frac{1}{100\text{ }\mu\text{F}} + \frac{1}{100\text{ }\mu\text{F}} = \frac{2}{100\text{ }\mu\text{F}}, giving Cseries=50 μFC_{\text{series}} = 50\text{ }\mu\text{F}. When this combination is connected in parallel with the 150 μF150\text{ }\mu\text{F} capacitor, parallel capacitances add directly: Ctotal=50 μF+150 μF=200 μFC_{\text{total}} = 50\text{ }\mu\text{F} + 150\text{ }\mu\text{F} = 200\text{ }\mu\text{F}.

Adım Adım Çözüm

1
Calculate the equivalent capacitance of the two 100 μF100\text{ }\mu\text{F} capacitors connected in series using the reciprocal formula 1Cseries=1C1+1C2\frac{1}{C_{\text{series}}} = \frac{1}{C_1} + \frac{1}{C_2}.
Cseries=50 μFC_{\text{series}} = 50\text{ }\mu\text{F}
Capacitors in series combine inversely, meaning two identical capacitors in series have half the capacitance of one capacitor.
2
Add the capacitance of the parallel branch to the series equivalent: Ctotal=Cseries+C3C_{\text{total}} = C_{\text{series}} + C_3.
Ctotal=50 μF+150 μF=200 μFC_{\text{total}} = 50\text{ }\mu\text{F} + 150\text{ }\mu\text{F} = 200\text{ }\mu\text{F}
Capacitors connected in parallel add directly because their effective plate areas combine, increasing overall charge storage capacity.

Anahtar Kavram

Series and parallel equivalent capacitance rules (series capacitors combine inversely; parallel capacitors add directly).
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