An electronics technician is troubleshooting an NPN bipolar junction transistor (BJT) configured as a solid-state switch. To transition the transistor from the cutoff state into saturation to energize an attached load, which electrical condition must be established at the base-emitter junction?
- AReverse-biasing the base-emitter junction by making the base negative with respect to the emitter
- Forward-biasing the base-emitter junction by applying a positive voltage to the base relative to the emitterCevap
- CMaintaining zero volts across the base-emitter junction while reverse-biasing the collector-base junction
- DApplying a negative voltage to the collector while drawing conventional current out of the base terminal
Cevap
Forward-biasing the base-emitter junction by applying a positive voltage to the base relative to the emitter causes the NPN transistor to transition into saturation.
In an NPN bipolar junction transistor, the base is composed of P-type semiconductor material while the emitter is N-type. To turn the transistor ON and enter saturation, the base-emitter junction must be forward-biased with a positive base voltage that exceeds the silicon barrier potential (). This introduces base current, which allows heavy electron flow from emitter to collector, effectively closing the circuit across the load.
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Anahtar Kavram
Transistor Biasing and Solid-State Switching States
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