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Zorluk: OrtaRatios and Proportions

A specialized aerospace alloy is manufactured by combining titanium and aluminum in a ratio of 7:47:4 by weight. If a batch of this alloy contains 140 kilograms140\text{ kilograms} of titanium, what is the total weight of the batch?

  1. A
    80 kg80\text{ kg}
  2. 220 kg220\text{ kg}Cevap
  3. C
    245 kg245\text{ kg}
  4. D
    385 kg385\text{ kg}

Cevap

The total weight of the batch is 220 kg220\text{ kg}.
The given ratio indicates the alloy consists of 77 parts titanium and 44 parts aluminum, making 1111 parts in total. Because the 77 parts of titanium weigh 140 kg140\text{ kg}, each single part weighs 20 kg20\text{ kg} (140÷7140 \div 7). Multiplying the 1111 total parts by 20 kg20\text{ kg} per part results in a total weight of 220 kg220\text{ kg}.

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1
Determine the weight of a single ratio part based on the known titanium content.
140 kg÷7 parts=20 kg per part140\text{ kg} \div 7\text{ parts} = 20\text{ kg per part}
Since the ratio of titanium to aluminum is 7:47:4, the 140 kg140\text{ kg} corresponds exactly to the 77 parts of titanium.
2
Calculate the total number of parts in the alloy mixture.
7 parts (titanium)+4 parts (aluminum)=11 total parts7\text{ parts (titanium)} + 4\text{ parts (aluminum)} = 11\text{ total parts}
The total weight is composed of both the titanium and the aluminum parts combined.
3
Multiply the total number of parts by the weight of a single part.
11 parts×20 kg per part=220 kg11\text{ parts} \times 20\text{ kg per part} = 220\text{ kg}
This yields the combined weight of the entire batch.

Anahtar Kavram

Solving Part-to-Whole Ratio Problems
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