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Zorluk: KolayOhm's Law

A DC cooling fan installed in an equipment enclosure has an internal resistance of 16 Ω16\ \Omega and draws a steady current of 1.5 A1.5\text{ A} during normal operation. According to Ohm's law, what is the voltage drop across the fan in volts (V\text{V})?

Cevap: 24 V

Cevap

24 V
According to Ohm's law, voltage (VV) is found by multiplying current (II) by resistance (RR). With a current of 1.5 A1.5\text{ A} and a resistance of 16 Ω16\ \Omega, the voltage is 1.5×16=24 V1.5 \times 16 = 24\text{ V}.

Adım Adım Çözüm

1
Identify the known electrical quantities from the problem statement.
I=1.5 AI = 1.5\text{ A} and R=16 ΩR = 16\ \Omega
Ohm's law requires current and resistance values to calculate voltage.
2
State Ohm's law formula arranged to solve for voltage (VV).
V=I×RV = I \times R
The potential difference across a resistive element is directly proportional to the product of current and resistance.
3
Multiply the current by the resistance to find the voltage.
V=1.5 A×16 Ω=24 VV = 1.5\text{ A} \times 16\ \Omega = 24\text{ V}
Performing the multiplication yields the potential difference in volts.

Anahtar Kavram

Ohm's Law (V=I×RV = I \times R)
Tahmini Süre:30s
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